EP INTRO.TO GENERAL,ORGANIC...-OWL ACCE
EP INTRO.TO GENERAL,ORGANIC...-OWL ACCE
12th Edition
ISBN: 9781337915984
Author: Bettelheim
Publisher: Cengage Learning
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Chapter 15.1, Problem 15.1QC
Interpretation Introduction

Interpretation: Whether cocaine has an aliphatic, heterocyclic aliphatic, and/or heterocyclic aromatic amine should be determined. Also, the amines need to be classified as 1o, 2oor 3o .

Concept Introduction:An organic compound to which -NH2 is bonded to the carbon atom chain is said to be an amine. Based on the attachment to the carbon, the amines are classified as a primary, secondary, or tertiary amine.

An organic compound that contains a ring in their structure composed of carbon and heteroatoms like nitrogen, sulfur, oxygen, etc. are said to be heterocyclic compound.

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Predict the organic products that form in the reaction below: OH H+ H+ + ☑ Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. ✓ m
Determine the structures of the missing organic molecules in the following reaction: + H₂O +H H+ Y Z ☑ ☑ Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structures of the missing organic molecules X, Y, and Z. You may draw the structures in any arrangement that you like, so long as they aren't touching. Molecule X shows up in multiple steps, but you only have to draw its structure once. Click and drag to start drawing a structure. AP +
Please help, this is all the calculations i got!!! I will rate!!!Approx mass of KMnO in vial: 3.464 4 Moss of beaker 3×~0. z Nax200: = 29.9219 Massof weacerv after remosimgain N2C2O4. Need to fill in all the missing blanks. ง ง Approx mass of KMnO4 in vials 3.464 Mass of beaker + 3x ~0-304: 29.9219 2~0.20 Miss of beaker + 2x- 29.7239 Mass of beaker + 1x~0.2g Naz (204 29-5249 Mass of beaver after removing as qa Na₂ C₂O T1 T2 T3 Final Buiet reading Initial butet reading (int)) Hass of NaOr used for Titration -reading (mL) calculation Results: 8.5ml 17mL 27.4mL Oml Om Oml T1 T2 T3 Moles of No CO Moles of KMO used LOF KM. O used Molenty of KMNO Averagem Of KMOWL

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EP INTRO.TO GENERAL,ORGANIC...-OWL ACCE

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