CONCEPTUAL INTEGRATED SCIENCE (PEARSON+
3rd Edition
ISBN: 2818440059223
Author: Hewitt
Publisher: PEARSON+
expand_more
expand_more
format_list_bulleted
Question
Chapter 15, Problem 92TE
To determine
To find:
The reason for the presence of bubbles in champagne.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
At sea level and at a body temperature of 37 degrees Celsius, how many oxygen molecules do the lungs contain at the end of a strong inhalation? (Hint: answer is not 0.039 molecules) Use Avogadro’s number to calculate the answer.
You are evaluating two biodegradable polymers, Polymer A and Polymer B, for material to release
hormonal birth control. The hormone drug is attached to the polymer backbone and drug is released
as the polymer degrades. You collect the following data on drug released from the polymer every 5
days over a 30-day study. State the mechanism by which Polymer A and Polymer B degrades and
calculate the rate constant, k, of degradation for Polymer A and Polymer B to 2 significant digits.
Show your work and upload your answers.
120%
70%
Polymer A
Polymer B
100%
60%
50%
80%
40%
60%
30%
40%
20%
20%
10%
0%
0%
0 5
10 15 20
25 30
0 5
10
15 20
25
30
Time (days)
Time (days)
Drug release
Drug release
Janice is grilling a steak for her July 4th barbecue dinner. The steak initially weighs 300 grams and is 25 mm thick. After grilling it for a while, she considers the steak done, and measures it again: it now weighs 215 grams, and is 15 mm thick. For both the cooked and uncooked steak, she uses the thumb-test to determine the done-ness, i.e. she uses her thumb (area ~5cm2) to push down with a force of 5 N. The uncooked steak compresses by 7 mm, and the cooked steak by 2 mm.
The change in elasticity of the steak on cooking is due partly to the loss of water volume (so that existing bonds get closer together) and partly to the creation of new bonds. Assume all of the difference in raw vs. cooked steak thickness is due to water loss that makes it thinner (25 mm thick in the uncooked steak, versus 15 mm thick in the cooked steak), and that the other dimensions of the steak (length and width) have not changed.
By what percentage has the steak's volume decreased from the original value?…
Chapter 15 Solutions
CONCEPTUAL INTEGRATED SCIENCE (PEARSON+
Ch. 15 - What are some of the characteristics of living...Ch. 15 - Describe what it means to say that living things...Ch. 15 - What are some examples of prokaryotes? What are...Ch. 15 - Describe three or more differences between...Ch. 15 - How is the DNA of prokaryotes packaged differently...Ch. 15 - What is the nucleus of a cell.Ch. 15 - Describe the functions of the following...Ch. 15 - What are three components of the cell membrane?Ch. 15 - Prob. 9RCCCh. 15 - Prob. 10RCC
Ch. 15 - Prob. 11RCCCh. 15 - What is the difference between diffusion and...Ch. 15 - Prob. 13RCCCh. 15 - How do endocytosis and exocytosis move materials...Ch. 15 - Prob. 15RCCCh. 15 - Describe what happens when a message molecule...Ch. 15 - Prob. 17RCCCh. 15 - What are the stages of cell cycle? What happens...Ch. 15 - Prob. 19RCCCh. 15 - What are the end products of mitosis?Ch. 15 - Prob. 21RCCCh. 15 - Prob. 22RCCCh. 15 - Prob. 23RCCCh. 15 - Prob. 24TISCh. 15 - Give an example of a a carbohydrate that functions...Ch. 15 - Describe the structure of DNA.Ch. 15 - Explain this statement: Proteins, carbohydrates,...Ch. 15 - Prob. 28TISCh. 15 - Why are electron microscopes particularly useful...Ch. 15 - Prob. 30TISCh. 15 - Prob. 31TISCh. 15 - Prob. 32TISCh. 15 - Prob. 33TISCh. 15 - Prob. 34TISCh. 15 - Prob. 35TISCh. 15 - Prob. 36TISCh. 15 - Prob. 37TISCh. 15 - Prob. 38TISCh. 15 - Prob. 39TISCh. 15 - Rank these three living things from largest to...Ch. 15 - Prob. 44TCCh. 15 - Prob. 45TCCh. 15 - Prob. 46TSCh. 15 - A typical cell in the body makes about 10 million...Ch. 15 - Prob. 48TSCh. 15 - Prob. 49TSCh. 15 - How can you tell a plant is alive even though it...Ch. 15 - What are some features of living organisms?...Ch. 15 - Bacteria reproduce by dividing in two. Is this an...Ch. 15 - Prob. 53TECh. 15 - Prob. 54TECh. 15 - Prob. 55TECh. 15 - DNA uses only four different kinds of nucleotides....Ch. 15 - Are your cells more like those of yeasts or those...Ch. 15 - You look at a cell under a microscope and discover...Ch. 15 - You hike near a pond, where you find strands of...Ch. 15 - Prob. 60TECh. 15 - What kind of microscope could you use to look at...Ch. 15 - How are a cells cytoskeleton and organelles like a...Ch. 15 - What organelle is found only in plants? What does...Ch. 15 - Prob. 64TECh. 15 - How is the function of a cell wall different from...Ch. 15 - Prob. 66TECh. 15 - Why is the cell membrane called a fluid mosaic?Ch. 15 - Prob. 68TECh. 15 - Prob. 69TECh. 15 - Prob. 70TECh. 15 - Prob. 71TECh. 15 - Prob. 72TECh. 15 - Prob. 73TECh. 15 - Prob. 74TECh. 15 - Message molecules and their receptors are...Ch. 15 - Prob. 76TECh. 15 - Prob. 77TECh. 15 - Prob. 78TECh. 15 - The deadly nerve gas sarin binds to an enzyme...Ch. 15 - Prob. 80TECh. 15 - Prob. 81TECh. 15 - Prob. 82TECh. 15 - Prob. 83TECh. 15 - Prob. 84TECh. 15 - Prob. 85TECh. 15 - Prob. 86TECh. 15 - Prob. 87TECh. 15 - Why cant you live without oxygen?Ch. 15 - What are some differences between fermentation and...Ch. 15 - You visit a friend who is a winemaker. Some of his...Ch. 15 - Prob. 92TECh. 15 - Some animals that live in desert environments,...Ch. 15 - Prob. 94TDICh. 15 - A friend in your class is reading about cells that...Ch. 15 - You and your friend are eating lunch in the...Ch. 15 - Prob. 97TDICh. 15 - Prob. 98TDICh. 15 - Prob. 1RATCh. 15 - Prob. 2RATCh. 15 - Prob. 3RATCh. 15 - Prob. 4RATCh. 15 - Prob. 5RATCh. 15 - Prob. 6RATCh. 15 - Prob. 7RATCh. 15 - Prob. 8RATCh. 15 - Prob. 9RATCh. 15 - Which of the following processes requires oxygen?...
Knowledge Booster
Similar questions
- Janice is grilling a steak for her July 4th barbecue dinner. The steak initially weighs 300 grams and is 25 mm thick. After grilling it for a while, she considers the steak done, and measures it again: it now weighs 215 grams, and is 15 mm thick. For both the cooked and uncooked steak, she uses the thumb-test to determine the done-ness, i.e. she uses her thumb (area ~5cm2) to push down with a force of 5 N. The uncooked steak compresses by 7 mm, and the cooked steak by 2 mm. Calculating elasticity What is the elasticity of the raw steak? Express your answer in Pascals but without including the units in your answer. What is the elasticity of the cooked steak? Express your answer in Pascals, but without including the units.arrow_forwardThere are two important isotopes of uranium, U235 and U238 ; these isotopes are nearly identical chemically but have different atomic masses. Only U235 is very useful in nuclear reactors. Separating the isotopes is called uranium enrichment (and is often in the news as of this writing, because of concerns that some countries are enriching uranium with the goal of making nuclear weapons.) One of the techniques for enrichment, gas diffusion, is based on the different molecular speeds of uranium hexafluoride gas, UF6 . (a) The molar masses of U235 and U238F6 are 349.0 g/mol and 352.0 g/mol, respectively. What is the ratio of their typical speeds vrms ? (b) At what temperature would their typical speeds differ by 1.00 m/s? (c) Do your answers in this problem imply that this technique may be difficult?arrow_forwardInsects do not have lungs as we do, nor do they breathe through their mouths. Instead, they have a system of tiny tubes, called tracheae, through which oxygen diffuses into their bodies. The tracheae begin at the surface of the insect's body and penetrate into the interior. Suppose that a tracheae is 1.83 mm long with a cross-sectional area of 1.47 x 10-9m2. The concentration of oxygen in the air outside the insect is 0.651 kg/m3, and the diffusion constant is 1.79 x 10-5 m2/s. If the mass per second of oxygen is diffusing through a trachea is 1.77 x 10-12 kg/s, then find the oxygen concentration at the interior end of the tube.arrow_forward
- Calculate the osmotic pressure of a 5% urea solution at a temperature of 273 K. Note that the molecular weight of urea (/60g) is the osmotic pressure of a solution obtained by mixing 100ml of a 4.5% solution of urea and 100ml of a 3.42% solution of sugar solution at a temperature of 300K. Suppose that 1 = 0arrow_forwardThree forces are applied to a tree sapling, as shown in (Figure 1) , to stabilize it. Suppose that F⃗ AF→AF_A = 345 NN and F⃗ BF→BF_B = 485 NN . Determine the magnitude of F⃗ CF→C. Determine the angle between F⃗ AF→A and F⃗ CF→C, measured clockwise.arrow_forwardThe proportions of various gases in the earth’s atmosphere change somewhat with altitude. Would you expect the proportion of oxygen at high altitude to be greater or less than at sea level compared to the proportion of nitrogen? Why?arrow_forward
- . (I) (a) At atmospheric pressure, in what phases can CO2 exist? (b) For what range of pressures and temperatures can CO2 be a liquid? Refer to Fig. 13–23.arrow_forwardLiving creatures generally have a higher temperature than their environment. Explain why this makes sense.arrow_forwardFor divers going to great depths, the composition of the air in the tank must be modified. The ideal composition is to have approximately the same number of O2 molecules per unit volume as in surface air (to avoid oxygen poisoning), and to use helium instead of nitrogen for the remainder of the gas (to avoid nitrogen narcosis, which results from nitrogen dissolving in the bloodstream). Of the molecules in dry surface air, 78.0% are N2, 21.0% are O2, and 1.00% are Ar. (Assume that the density of seawater is 1025 kg/m3 and the temperature is 20.0°C.) Density of dry air at 20.0°C is 1.20 kg/m3. Molar mass of N2 is 14.007 g/mol, O2 is 15.999 g/mol, and Ar is 39.948 g/mol. For a diver going to a depth of 141 m, what percentage of the gas molecules in the tank should be O2?arrow_forward
- The partial pressure of carbon dioxide in the lungs is about 470 Pa when the total pressure in the lungs is 1.0 atm. What percentage of the air molecules in the lungs is carbon dioxide? Compare your result to the percentage of carbon dioxide in the atmosphere, but 0.033%.arrow_forward12arrow_forward45. Insects do not have lungs as we do, nor do they breathe through their mouths. Instead, they have a system of tiny tubes, called tra- cheae, through which oxygen diffuses into their bodies. The tracheae begin at the surface of an insect's body and penetrate into the interior. Suppose that a trachea is 1.9 mm long with a cross-sectional area of 2.1 × 10-º m². The concentration of oxygen in the air outside the insect is 0.28 kg/m², and the diffusion constant is 1.1 × 10-5 m²/s. If the mass per second of oxygen diffusing through a trachea is 1.7 X 10-12 kg/s, find the oxygen concentra- tion at the interior end of the tube.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning