CAMPBELL BIOLOGY,VOL.II >CUSTOM<
17th Edition
ISBN: 9781323803677
Author: Urry
Publisher: PEARSON
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Chapter 15, Problem 8TYU
Two genes of a flower, one Controlling blue (B) versus white (b) petals and the other Controlling round (R) versus oval (r) stamens, are linked and are 10 map units apart. You cross a homozygous blue oval plant with a homozygous white round plant. The resulting F, progeny are crossed with homozygous white oval plants, and 1,000 offspring plants are obtained. How many plants of each of the four
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Two genes of a flower, one controlling blue (B) versus white(b) petals and the other controlling round (R) versus oval (r)stamens, are linked and are 10 map units apart. You cross ahomozygous blue oval plant with a homozygous white round plant. The resulting F1 progeny are crossed with homozygouswhite oval plants, and 1,000 offspring plants are obtained.How many plants of each of the four phenotypes do youexpect?
In autotetraploid Chinese primrose (Primula sinensis L.), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for red stigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploid strain.
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Chapter 15 Solutions
CAMPBELL BIOLOGY,VOL.II >CUSTOM<
Ch. 15.1 - Which one of Mendel's laws describes the...Ch. 15.1 - MAKE CONNECTIONS Review the description of...Ch. 15.1 - WHAT IF? Propose a possible reason that the first...Ch. 15.2 - A white-eyed female Drosophila is mated with a...Ch. 15.2 - Neither Tim nor Rhoda has Duchenne muscular...Ch. 15.2 - MAKE CONNECTIONS Consider what you learned about...Ch. 15.3 - When two genes are located on the same chromosome,...Ch. 15.3 - VISUAL SKILLS For each type of offspring of the...Ch. 15.3 - Prob. 3CCCh. 15.4 - Prob. 1CC
Ch. 15.4 - Prob. 2CCCh. 15.4 - Prob. 3CCCh. 15.5 - Gene dosagethe number of copies of a gene that are...Ch. 15.5 - Reciprocal crosses between two primrose varieties,...Ch. 15.5 - WHAT IF? Mitochondrial genes are critical to the...Ch. 15 - What characteristic of the sex chromosomes allowed...Ch. 15 - Why are males affected by X-Iinked disorders much...Ch. 15 - Why are specific alleles of two distant genes more...Ch. 15 - Prob. 15.4CRCh. 15 - Explain how genomic imprinting and inheritance of...Ch. 15 - A man with hemophilia (a recessive, sex-linked...Ch. 15 - Pseudohypertrophic muscular dystrophy is an...Ch. 15 - A wild-type fruit fly (heterozygous for gray body...Ch. 15 - A planet is inhabited by creatures that reproduce...Ch. 15 - Using the information from problem 4, scientists...Ch. 15 - A wild-type fruit fly (heterozygous for gray body...Ch. 15 - Assume that genes, A and B are on the same...Ch. 15 - Two genes of a flower, one Controlling blue (B)...Ch. 15 - You design Drosophila crosses to provide...Ch. 15 - Banana plants, which are triploid, are seedless...Ch. 15 - EVOLUTION CONNECTION Crossing over is thought to...Ch. 15 - SCIENTIFIC INQUIRY DRAW IT Assume you are mapping...Ch. 15 - WRITE ABOUT A THEME: INFORMATION The continuity of...Ch. 15 - SYNTHESIZE YOUR KNOWLEDGE Butter flies have an X-Y...
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- In pea plants, yellow seeds (Y) are dominant to green seeds (y) and round seeds (R) are dominant to wrinkled seeds (). The genes for seed color and seed shape are on different chromosomes. Two true-breeding parents, one with yellow round peas and the other with green wrinkled peas, are crossed to produce a hybrid (heterozygous) F₁. Two F₁ individuals are crossed to give an F2; this is depicted in the Punnett square below. Place the correct genotypes in the Punnett square and the place the correct phenotypic ratios next to their appropriate phenotype on the right. YYRR YYRr YyRR YYrr yyRR yyRr Yyrr YyRr 3/16 1/16 yyrr 9/16 3/16 1/4 E 1/2 16/16 YR ✪✪✪ Yr yR YYRR Y YyRr Yr yR YR YYRr YYRR YyRr yr YyRr yyrr yr YyRr Yyrr yyRr F2 phenotype Phenotypic ratio Aarrow_forwardIn roses, purple flower color is determined by the dominant P allele, while pphomozygotes are white. The presence of long stems is determined by the dominant S allele, while ss homozygotes have short stems. Both mutations are completely penetrant. A test cross was performed between a rose plant of unknown genotype with a white flowered, short stemmed rose plant (pp ss) and the following 200 progeny plants were obtained: 84 white flowers, long stems 16 purple flowers, long stems 82 purple flowers, short stems 18 white flowers, short stems Select two statements below that are TRUE. options: The P and S genes independently assort during meiosis. The map distance between P and S is 17 cM. The genotype of the progeny plants with purple flowers and short stems is PP ss. The map distance between P and S is 83 cM. The homologs in the plant with…arrow_forwardIn cucumbers, speckled fruit color (u') is dominant to uniform fruit color (u), and large spines (ss") are dominant to small spines (ss). These two genes are linked at a map distance of 20.4 m.u. A true-breeding cucumber plant with speckled fruit and large spines is crossed with a true-breeding plant with uniform fruit color and small spines. One of the F1 plants is crossed with a plant with uniform fruit color and small spines. What percentage of the offspring of this cross are expected to have uniform fruit color and small spines? 39.8% 10.2% 79.6% 20.4%arrow_forward
- Two genes, m (apical meristem) and r (starburst rhizosomes), are linked on chromosome #5 in pea plants. Both genes are recessive to wild type and found to be 8 MU apart. If a wild type heterozygote is test- crossed, and produces 91 apical meristem plants and 8 apical, starburst plants from a total of 200 plants were produced, how many wild type plants will be produced? 4 8. 12 16arrow_forwardTwo pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forwardA cross was made between a Red and Long flowered (RRLL) plant and a blue and dwarfflowered (rrll) plant. The resulting F1 plants were testcrossed to blue and dwarf plants.160 red and long40 red and dwarf38 blue and long150 blue and dwarfAfter showing your Punnett square for the testcross, use the Chi Square test to determine if thegenes are assorting independently. If they are linked, calculate the distance between the twogenes. Show your work.arrow_forward
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