(a)
Interpretation:
The statement “Aniline is an aromatic
(a)

Answer to Problem 5MCP
The given statement is true.
Explanation of Solution
Aniline is the simplest aromatic amine with the formula
(b)
Interpretation:
The statement “Aniline has a lower boiling point than benzoic acid” has to be predicted as true or false. If the statement is false, the reason for the false statement has to be described.
(b)

Answer to Problem 5MCP
The given statement is true.
Explanation of Solution
Aniline is an amine and benzoic acid is
The ability of primary and secondary amines to form
(c)
Interpretation:
The statement “Aniline is planar molecule” has to be predicted as true or false. If the statement is false, the reason for the false statement has to be described.
(c)

Answer to Problem 5MCP
The given statement is false because it is slightly pyramidalized molecule.
Explanation of Solution
Aniline is slightly pyramidalized molecule, with hybridization of the nitrogen between
Hence, the given statement is false.
(d)
Interpretation:
The statement “The molecular formula of aniline is
(d)

Answer to Problem 5MCP
The given statement is false because the molecular formula of aniline is
Explanation of Solution
Aniline is the simplest aromatic amine with the formula
Hence, the statement “Aniline has a molecular formula of
(e)
Interpretation:
The statement “Aniline is a structural isomer of xylene” has to be predicted as true or false. If the statement is false, the reason for the false statement has to be described.
(e)

Answer to Problem 5MCP
The given statement is false because both aniline and xylene have different molecular formulas.
Explanation of Solution
Structural isomers are those with same molecular formula but differ in arrangement of atoms.
The molecular formula of aniline is
The molecular formula of xylene is
Both these are not structural isomers with each other.
Hence, the statement “aniline is structural isomer of xylene” is false because they have different molecular formulas.
(f)
Interpretation:
The statement “Aniline is more soluble than phenol” has to be predicted as true or false. If the statement is false, the reason for the false statement has to be described.
(f)

Answer to Problem 5MCP
The given statement is false because both aniline and phenol are sparingly soluble in water.
Explanation of Solution
Aniline does not form hydrogen bonds with water to a very large extent due to the presence of large hydrophobic
The hydroxyl group of phenol is polar in nature, the oxygen is more electronegative than hydrogen, and hence it attracts shared electrons and acquires partial negative charge. The hydrogen of hydroxyl group in phenol carries partial negative charge. Phenol forms hydrogen bonding with water. However, the large part of phenol molecule is phenyl group is non-polar, thus making it sparingly soluble in water.
Hence, the given statement is false because both aniline and phenol are sparingly soluble in water.
(g)
Interpretation:
The statement “Aniline produces phenylammonium ion in water” has to be predicted as true or false. If the statement is false, the reason for the false statement has to be described.
(g)

Answer to Problem 5MCP
The given statement is true.
Explanation of Solution
Aniline acts as bases, accepting
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Chapter 15 Solutions
GENERAL,ORGANIC,+BIOCHEMISTRY
- Using the conditions of spontaneity to deduce the signs of AH and AS Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions A This reaction is always spontaneous, but proceeds slower at temperatures above 120. °C. ΔΗ is (pick one) AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous except above 117. °C. AS is (pick one) ΔΗ is (pick one) This reaction is slower below 20. °C than C above. AS is |(pick one) ? 18 Ar 1arrow_forwardCalculating the pH at equivalence of a titration Try Again Your answer is incorrect. 0/5 a A chemist titrates 70.0 mL of a 0.7089 M hydrocyanic acid (HCN) solution with 0.4574M KOH solution at 25 °C. Calculate the pH at equivalence. The pK of hydrocyanic acid is 9.21. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of KOH solution added. pH = 11.43] G 00. 18 Ar B•arrow_forwardBiological Macromolecules Naming and drawing the products of aldose oxidation and reduction aw a Fischer projection of the molecule that would produce L-ribonic acid if it were subjected to mildly oxidizing reaction conditions. Click and drag to start drawing a structure. X AP ‡ 1/5 Naor Explanation Check McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Accessibilarrow_forward
- ● Biological Macromolecules Identifying the parts of a disaccharide Take a look at this molecule, and then answer the questions in the table below it. CH2OH O H H H OH OH OH H H CH2OH H O OH H OH H H H H OH Is this a reducing sugar? Does this molecule contain a glycosidic bond? If you said this molecule does contain a glycosidic bond, write the symbol describing it. If you said this molecule does contain a glycosidic bond, write the common names (including anomer and enantiomer labels) of the molecules that would be released if that bond were hydrolyzed. If there's more than one molecule, separate each name with a comma. Explanation Check O yes X O no ○ yes O no Uarrow_forwardThe aim of the lab is to measure the sodium content from tomato sauce using the Mohr titration method. There are two groups being: Regular Tomato sauce & Salt Reduced tomato sauce QUESTION: State how you would prepare both Regular & Salt reduced tomato sauce samples for chemical analysis using the Mohr titration methodarrow_forwardUsing the conditions of spontaneity to deduce the signs of AH and AS Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions A The reverse of this reaction is always spontaneous but proceeds faster at temperatures above -48. °C. ΔΗ is (pick one) ✓ AS is (pick one) B This reaction is spontaneous except below 114. °C but proceeds at a slower rate below 135. °C. ΔΗ is (pick one) AS is (pick one) ΔΗ is C This reaction is exothermic and proceeds faster at temperatures above -43. °C. (pick one) AS is (pick one) v Х 5 ? 18 Ararrow_forward
- ion. A student proposes the following Lewis structure for the perchlorate (CIO) io : :0: : Cl : - - : :0: ك Assign a formal charge to each atom in the student's Lewis structure. atom central O formal charge ☐ top O ☐ right O ☐ bottom O ☐ Cl ☐arrow_forwardDecide whether these proposed Lewis structures are reasonable. proposed Lewis structure Yes. Is the proposed Lewis structure reasonable? Cl- : 2: :Z: :Z: N—N : 0: C C1: O CO No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* ☐ Yes. No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0". ☑arrow_forwardUse the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions ΔΗ is (pick one) A This reaction is faster above 103. °C than below. AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous only above -9. °C. AS is (pick one) ΔΗ is (pick one) C The reverse of this reaction is always spontaneous. AS is (pick one) 18 Ararrow_forward
- Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions A The reverse of this reaction is always spontaneous but proceeds slower at temperatures below 41. °C. ΔΗ is (pick one) AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous except above 94. °C. AS is (pick one) This reaction is always spontaneous, but ΔΗ is (pick one) C proceeds slower at temperatures below −14. °C. AS is (pick one) Х 00. 18 Ar 무ㅎ B 1 1arrow_forwardDraw the product of the reaction shown below. Ignore inorganic byproducts. + H CH3CH2OH HCI Drawingarrow_forwardplease explain this in simple termsarrow_forward
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