Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 15, Problem 56E
Interpretation Introduction
Interpretation:
The molar concentration of chloride ions is to be calculated.
Concept introduction:
Molarity is defined as the number of moles of solute per unit volume in liters of solution.
The formula of molarity is given below.
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Using the conditions of spontaneity to deduce the signs of AH and AS
Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy
AS.
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reaction
observations
conclusions
A
This reaction is always spontaneous, but
proceeds slower at temperatures above
120. °C.
ΔΗ is
(pick one)
AS is
(pick one)
ΔΗ is
(pick one)
B
This reaction is spontaneous except above
117. °C.
AS is
(pick one)
ΔΗ is
(pick one)
This reaction is slower below 20. °C than
C
above.
AS is
|(pick one)
?
18
Ar
1
Calculating the pH at equivalence of a titration
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0/5
a
A chemist titrates 70.0 mL of a 0.7089 M hydrocyanic acid (HCN) solution with 0.4574M KOH solution at 25 °C. Calculate the pH at equivalence. The pK of
hydrocyanic acid is 9.21.
Round your answer to 2 decimal places.
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00.
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Ar
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Chapter 15 Solutions
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Ch. 15 - Prob. 1CECh. 15 - Prob. 2CECh. 15 - Prob. 3CECh. 15 - Prob. 4CECh. 15 - Prob. 5CECh. 15 - Prob. 6CECh. 15 - Prob. 7CECh. 15 - Prob. 8CECh. 15 - Prob. 9CECh. 15 - Prob. 1KT
Ch. 15 - Prob. 2KTCh. 15 - Prob. 3KTCh. 15 - Prob. 4KTCh. 15 - Prob. 5KTCh. 15 - Prob. 6KTCh. 15 - Prob. 7KTCh. 15 - Prob. 8KTCh. 15 - Prob. 9KTCh. 15 - Prob. 10KTCh. 15 - Prob. 11KTCh. 15 - Prob. 12KTCh. 15 - Prob. 13KTCh. 15 - Prob. 14KTCh. 15 - Prob. 15KTCh. 15 - Prob. 16KTCh. 15 - Prob. 17KTCh. 15 - Prob. 18KTCh. 15 - Prob. 19KTCh. 15 - Prob. 20KTCh. 15 - Prob. 21KTCh. 15 - Prob. 22KTCh. 15 - Prob. 1ECh. 15 - Prob. 2ECh. 15 - Prob. 3ECh. 15 - Prob. 4ECh. 15 - Prob. 5ECh. 15 - Prob. 6ECh. 15 - Prob. 7ECh. 15 - Prob. 8ECh. 15 - Prob. 9ECh. 15 - Prob. 10ECh. 15 - Prob. 11ECh. 15 - Prob. 12ECh. 15 - Prob. 13ECh. 15 - Prob. 14ECh. 15 - Prob. 15ECh. 15 - Prob. 16ECh. 15 - Prob. 17ECh. 15 - Prob. 18ECh. 15 - Prob. 19ECh. 15 - Prob. 20ECh. 15 - Prob. 21ECh. 15 - Prob. 22ECh. 15 - Prob. 23ECh. 15 - Prob. 24ECh. 15 - Prob. 25ECh. 15 - Prob. 26ECh. 15 - Prob. 27ECh. 15 - Prob. 28ECh. 15 - Prob. 29ECh. 15 - Prob. 30ECh. 15 - Prob. 31ECh. 15 - Prob. 32ECh. 15 - Prob. 33ECh. 15 - Prob. 34ECh. 15 - Prob. 35ECh. 15 - Prob. 36ECh. 15 - Prob. 37ECh. 15 - Prob. 38ECh. 15 - Prob. 39ECh. 15 - Prob. 40ECh. 15 - Prob. 41ECh. 15 - Prob. 42ECh. 15 - Prob. 43ECh. 15 - Prob. 44ECh. 15 - Prob. 45ECh. 15 - Prob. 46ECh. 15 - Prob. 47ECh. 15 - Prob. 48ECh. 15 - Prob. 49ECh. 15 - Prob. 50ECh. 15 - Prob. 51ECh. 15 - Prob. 52ECh. 15 - Prob. 53ECh. 15 - Prob. 54ECh. 15 - Prob. 55ECh. 15 - Prob. 56ECh. 15 - Prob. 57ECh. 15 - Prob. 58ECh. 15 - Prob. 59ECh. 15 - Prob. 60ECh. 15 - Prob. 1STCh. 15 - Prob. 2STCh. 15 - Prob. 3STCh. 15 - Prob. 4STCh. 15 - Prob. 5STCh. 15 - Prob. 6STCh. 15 - Prob. 7STCh. 15 - Prob. 8STCh. 15 - Prob. 9STCh. 15 - Prob. 10STCh. 15 - Prob. 11STCh. 15 - Prob. 12STCh. 15 - Prob. 13STCh. 15 - Prob. 14STCh. 15 - Prob. 15STCh. 15 - Prob. 16ST
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