Heating air in the lungs. Human lung capacity varies iron about 4 L to b L, so we shall use an average or 5.0 L. The air enters at the ambient temperature of the atmosphere and must be heated to internal body temperature at an approximately constant pressure of 1.0 aim in our model. Suppose you are outside on a winter day when the temperature is −10°F. (a) How many moles of air does your lung hold if the 5.0 L is at the internal body temperature of 37°C? (b) How much heat must your body have supplied to get the 5.0 L of air up to internal body temperature, assuming that the atmosphere is all N 2 ? (See Table 15.4 .) (c) Suppose instead that you manage to inhale the full 5.0 L of air in one breath and held it in your lungs without expanding (or contracting) them. How much heat would your body have had to supply in that case to raise the air up to internal body temperature?
Heating air in the lungs. Human lung capacity varies iron about 4 L to b L, so we shall use an average or 5.0 L. The air enters at the ambient temperature of the atmosphere and must be heated to internal body temperature at an approximately constant pressure of 1.0 aim in our model. Suppose you are outside on a winter day when the temperature is −10°F. (a) How many moles of air does your lung hold if the 5.0 L is at the internal body temperature of 37°C? (b) How much heat must your body have supplied to get the 5.0 L of air up to internal body temperature, assuming that the atmosphere is all N 2 ? (See Table 15.4 .) (c) Suppose instead that you manage to inhale the full 5.0 L of air in one breath and held it in your lungs without expanding (or contracting) them. How much heat would your body have had to supply in that case to raise the air up to internal body temperature?
Heating air in the lungs. Human lung capacity varies iron about 4 L to b L, so we shall use an average or 5.0 L. The air enters at the ambient temperature of the atmosphere and must be heated to internal body temperature at an approximately constant pressure of 1.0 aim in our model. Suppose you are outside on a winter day when the temperature is −10°F. (a) How many moles of air does your lung hold if the 5.0 L is at the internal body temperature of 37°C? (b) How much heat must your body have supplied to get the 5.0 L of air up to internal body temperature, assuming that the atmosphere is all N2? (See Table 15.4.) (c) Suppose instead that you manage to inhale the full 5.0 L of air in one breath and held it in your lungs without expanding (or contracting) them. How much heat would your body have had to supply in that case to raise the air up to internal body temperature?
For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you
A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).
What are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V)
ammeter
I =
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