Explanation Given information: An object of volume V is weighed in air on an equal-arm balance with the use of counterweights of density ρ . The true weight is the weight of the object that is measured in the air and the apparent weight is the weight of the object that is measured in the water. The net weight of an object can be measured in a vacuum is equal to the apparent weight is, F g − F B = F ′ g − F ′ B (I) F g is the true weight of an object. F ′ g is the apparent weight of an object. F B is the buoyant force acts on the object. F ′ B is the apparent buoyant force acts on the object. Formula to calculate the buoyant force acts on the object is, F B = ρ air g V Formula to calculate the apparent buoyant force acts on the object is, F ′ B = ρ air g ( F ′ g ρ g ) Substitute ρ air g V for F B and ρ air g ( F ′ g ρ g ) for F ′ B in equation (I)

Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term

5th Edition

ISBN: 9781133422013

Author: Raymond A. Serway; John W. Jewett

Publisher: Cengage Learning

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Chapter 15, Problem 54P

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To show: The true weight of the object is Fg=F′g+(V−F′gρg)ρairg .

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Chapter 15, Problem 53P

Chapter 15, Problem 55P

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Chapter 15 Solutions

Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term

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The true weight of the object is F g = F ′ g + ( V − F ′ g ρ g ) ρ air g .

Solution Summary: The author explains that an object of volume V is weighed in air on an equal-arm balance with the use of counterweights of density rho

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To show: The true weight of the object is Fg=F′g+(V−F′gρg)ρairg .

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Chapter 15 Solutions