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Thymol (molecular formula
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ORGANIC CHEMISTRY
- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardCompound B of molecular formula C9H19N shows a noteworthy infrared absorption at 3300 cm-1. Its 1H-NMR spectrum shows three singlets – δ 1.0 (6H), 1.1 (12H), 1.4 (1H) ppm. Its 13C-NMR spectrum has four signals – δ 25, 28, 41, 64 ppm. Suggest a structure for this compound.arrow_forwardA hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forward
- Propose a structure for compound X (molecular formula C6H12O2), which gives a strong peak in its IR spectrum at 1740 cm−1. The 1H NMR spectrum of X shows only two singlets, including one at 3.5 ppm. The 13C NMR spectrum is given below. Propose a structure for X.arrow_forwardAn unknown compound C3H2NCl shows moderately strong IR absorptions around 1650 cm-1 and 2200 cm-1. Its NMR spectrum consists of two doublets (J = 14 Hz) at δ 5.9 and δ 7.1. Propose a structure consistent with this data?arrow_forwardCompound B of molecular formula C9H19N shows a noteworthy infrared absorption at 3300 cm-1. Its 1H-NMR spectrum shows three singlets – δ 1.0 (6H), 1.1 (12H), 1.4 (1H) ppm. Its 13C-NMR spectrum has four signals – δ 25, 28, 41, 64 ppm. Suggest a structure for this compound. Please show work.arrow_forward
- Compound P has molecular formula C5H9ClO2. Deduce the structure of P from its 1H and 13C NMR spectra.arrow_forwardDeduce the structure of a compound with molecular formula C5H100 that exhibits the following ¹H and ¹³C NMR spectra. IH NMR CNMR 150 10 Structure A Structure B Structure C Structure D 24 1C 100 B 2H H 20 50 10 D 311arrow_forwardAn unknown compound A has the molecular formula C4H3O2. Based on the following H NMR spectrum, what is the structure of compound A? | зн |3H | 2H 11 10 7. 6 3 1 Select one: OHarrow_forward
- Compound L has the formula C₁1H₁5 NO. The ¹H NMR, 13C NMR and the IR spectra for Compound L are shown below. Propose a structure for Compound L. 12 4800 11 HSP-01-587 DEPT-90 DEPT-135 1 : T T 10 9 200 2 2 CDS-06-337 8 7 180 160 6 : 140 5 ppm 120 4 4 3 100 : 6 ppm 2 T T 1 to maineriberent waiho mlenmol wons havus saonic 80 D 0 -1 T 60 40 20 4 T 0arrow_forward22. A compound with the molecular formula C8H8O produces an IR spectrum with signals at 3063, 1686, and 1646 cm-1. The 1H NMR spectrum of this compound exhibits a singlet at 2.6ppm(l=3H), and a multiplet at 7.5(l= 5H). Draw the structure and give the common name of this compound . Show the correlations between the structure and spectra.arrow_forwardIdentify the structures of isomers H and I (molecular formula C8H11N).a.Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm−1b.Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm−1arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning