COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 15, Problem 51QAP
To determine
To calculate:
The change in the internal energy of an ideal gas.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Chapter 15 Solutions
COLLEGE PHYSICS
Ch. 15 - Prob. 1QAPCh. 15 - Prob. 2QAPCh. 15 - Prob. 3QAPCh. 15 - Prob. 4QAPCh. 15 - Prob. 5QAPCh. 15 - Prob. 6QAPCh. 15 - Prob. 7QAPCh. 15 - Prob. 8QAPCh. 15 - Prob. 9QAPCh. 15 - Prob. 10QAP
Ch. 15 - Prob. 11QAPCh. 15 - Prob. 12QAPCh. 15 - Prob. 13QAPCh. 15 - Prob. 14QAPCh. 15 - Prob. 15QAPCh. 15 - Prob. 16QAPCh. 15 - Prob. 17QAPCh. 15 - Prob. 18QAPCh. 15 - Prob. 19QAPCh. 15 - Prob. 20QAPCh. 15 - Prob. 21QAPCh. 15 - Prob. 22QAPCh. 15 - Prob. 23QAPCh. 15 - Prob. 24QAPCh. 15 - Prob. 25QAPCh. 15 - Prob. 26QAPCh. 15 - Prob. 27QAPCh. 15 - Prob. 28QAPCh. 15 - Prob. 29QAPCh. 15 - Prob. 30QAPCh. 15 - Prob. 31QAPCh. 15 - Prob. 32QAPCh. 15 - Prob. 33QAPCh. 15 - Prob. 34QAPCh. 15 - Prob. 35QAPCh. 15 - Prob. 36QAPCh. 15 - Prob. 37QAPCh. 15 - Prob. 38QAPCh. 15 - Prob. 39QAPCh. 15 - Prob. 40QAPCh. 15 - Prob. 41QAPCh. 15 - Prob. 42QAPCh. 15 - Prob. 43QAPCh. 15 - Prob. 44QAPCh. 15 - Prob. 45QAPCh. 15 - Prob. 46QAPCh. 15 - Prob. 47QAPCh. 15 - Prob. 48QAPCh. 15 - Prob. 49QAPCh. 15 - Prob. 50QAPCh. 15 - Prob. 51QAPCh. 15 - Prob. 52QAPCh. 15 - Prob. 53QAPCh. 15 - Prob. 54QAPCh. 15 - Prob. 55QAPCh. 15 - Prob. 56QAPCh. 15 - Prob. 57QAPCh. 15 - Prob. 58QAPCh. 15 - Prob. 59QAPCh. 15 - Prob. 60QAPCh. 15 - Prob. 61QAPCh. 15 - Prob. 62QAPCh. 15 - Prob. 63QAPCh. 15 - Prob. 64QAPCh. 15 - Prob. 65QAPCh. 15 - Prob. 66QAPCh. 15 - Prob. 67QAPCh. 15 - Prob. 68QAPCh. 15 - Prob. 69QAPCh. 15 - Prob. 70QAPCh. 15 - Prob. 71QAPCh. 15 - Prob. 72QAPCh. 15 - Prob. 73QAPCh. 15 - Prob. 74QAPCh. 15 - Prob. 75QAPCh. 15 - Prob. 76QAPCh. 15 - Prob. 77QAPCh. 15 - Prob. 78QAPCh. 15 - Prob. 79QAPCh. 15 - Prob. 80QAPCh. 15 - Prob. 81QAPCh. 15 - Prob. 82QAPCh. 15 - Prob. 83QAPCh. 15 - Prob. 84QAPCh. 15 - Prob. 85QAPCh. 15 - Prob. 86QAPCh. 15 - Prob. 87QAPCh. 15 - Prob. 88QAPCh. 15 - Prob. 89QAPCh. 15 - Prob. 90QAPCh. 15 - Prob. 91QAPCh. 15 - Prob. 92QAPCh. 15 - Prob. 93QAPCh. 15 - Prob. 94QAPCh. 15 - Prob. 95QAPCh. 15 - Prob. 96QAPCh. 15 - Prob. 97QAPCh. 15 - Prob. 98QAPCh. 15 - Prob. 99QAPCh. 15 - Prob. 100QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (a) An ideal gas expands adiabatically from a volume of 2.0103 m3 to 2.5103 m3. If the initial pressure and temperature 5.0105 Pa and 300 K, respectively, what are the final pressure and temperature of the gas? Use =5/3 for the gas. (b) In an isothermal process, an ideal gas expands from a of 2.0103 m3 to 2.5103 m3. If the initial pressure and temperature were 5.0105 Pa and 300 K, respectively, what are the final pressure and temperature of the gas?arrow_forwardCompare the charge in internal energy of an ideal gas for a quasi-static adiabatic expansion with that for a quasi-static isothermal expansion. What happens to the temperature of an ideal gas in an adiabatic expansion?arrow_forwardA gas expands from I to Fin Figure P20.58 (page 622). The energy added to the gas by heat is 418 J when the gas goes from I to F along the diagonal path, (a) What is the change in internal energy of the gas? (b) How much energy must be added to the gas by heat along the indirect path IAF?arrow_forward
- One mole of an ideal gas does 3 000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and volume of 25.0 L. Determine (a) the initial volume and (b) the temperature of the gas.arrow_forwardPressure and volume measurements of a dilute gas undergoing a quasi-static adiabatic expansion are shown below. Plot In p vs. V and determine 7 for this gas from your graph.arrow_forwardIf a gas is compressed isothermally, which of the following statements is true? (a) Energy is transferred into the gas by heat. (b) No work is done on the gas. (c) The temperature of the gas increases, (d) The internal energy of the gas remains constant, (e) None of those statements is true.arrow_forward
- Two containers hold an ideal gas at the same temperature and pressure. Both containers hold the same type of gas, but container B has twice the volume of container A. (i) What is the average translational kinetic energy per molecule in container B? (a) twice that of container A (b) the same as that of container A (c) half that of container A (d) impossible to determine (ii) From the same choices, describe the internal energy of the gas in container B.arrow_forwardThere is no change in the internal of an ideal gas undergoing an isothermal process since the internal energy depends only on the temperature. Is it therefore correct to say that an isothermal process is the same as an adiabatic process for an ideal gas? Explain your answer. `arrow_forwardA biology laboratory is maintained at a constant temperature of 7.00C by an air conditioner, which is vented to the air outside. On a typical hot summer day, the outside temperature is 27.0C and the air-conditioning unit emits energy to the outside at a rate of 10.0 kW. Model the unit as having a coefficient of performance (COP) equal to 40.0% of the COP of an ideal Carnot device. (a) At what rate does the air conditioner remove energy from the laboratory? (b) Calculate the power required for the work input. (c) Find the change in entropy of the Universe produced by the air conditioner in 1.00 h. (d) What If? The outside temperature increases to 32.0C. Find the fractional change in the COP of the air conditioner.arrow_forward
- A gascooled nuclear reactor operates between hot and cold reservoir temperatures of 700C and 27.0C. (a) What is the maximum eficiency of a heat engine operating between these temperatures? (b) Find the ratio of this eficiency to the Carnot eficiency of a standard nuclear reactor (found in Example 15.4).arrow_forwardIn Figure P19.22, the change in internal energy of a gas that is taken from A to C along the blue path is +800 J. The work done on the gas along the red path ABC is 500 J. (a) How much energy must be added to the system by heat as it goes from A through B to C? (b) If the pressure at point A is five times that of point C, what is the work done on the system in going from C to D? Figure P19.22 (c) What is the energy exchanged with the surroundings by heat as the gas goes from C to A along the green path? (d) If the change in internal energy in going from point D to point A is +500 J, how much energy must be added to the system by heat as it goes from point C to point D?arrow_forwardAir (a diatomic ideal gas) at 27.0C and atmospheric pressure is drawn into a bicycle pump (Figure P17.53) that has a cylinder with an inner diameter of 2.50 cm and length 50.0 cm. The downstroke adiabatically compresses the air, which reaches a gauge pressure of 8.00 105 Pa before entering the tire. We wish to investigate the temperature increase of the pump. (a) What is the initial volume of the air in the pump? (b) What is the number of moles of air in the pump? (c) What is the absolute pressure of the compressed air? (d) What is the volume of the compressed air? (e) What is the temperature of the compressed air? (f) What is the increase in internal energy of the gas during the compression? What If? The pump is made of steel that is 2.00 mm thick. Assume 4.00 cm of the cylinders length is allowed to come to thermal equilibrium with the air. (g) What is the volume of steel in this 4.00-cm length? (h) What is the mass of steel in this 4.00-cm length? (i) Assume the pump is compressed once. After the adiabatic expansion, conduction results in the energy increase in part (f) being shared between the gas and the 4.00-cm length of steel. What will be the increase in temperature of the steel after one compression? Figure P17.53arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Thermodynamics: Crash Course Physics #23; Author: Crash Course;https://www.youtube.com/watch?v=4i1MUWJoI0U;License: Standard YouTube License, CC-BY