Chemistry In Focus
7th Edition
ISBN: 9781337399692
Author: Tro, Nivaldo J.
Publisher: Cengage Learning,
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Question
Chapter 15, Problem 51E
Interpretation Introduction
Interpretation:
Dew in terms of relative humidity is to be explained.
Concept Introduction:
The water droplets that are found on thin and exposed objects in morning and evening are called dew.
Relative humidity is the amount of water vapour present in the air which is calculated as the percentage of vapour required for saturation at the same temperature.
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Chapter 15 Solutions
Chemistry In Focus
Ch. 15 - Prob. 15.1YTCh. 15 - Prob. 1SCCh. 15 - Prob. 2SCCh. 15 - Prob. 3SCCh. 15 - Prob. 1ECh. 15 - Prob. 2ECh. 15 - Prob. 3ECh. 15 - Prob. 4ECh. 15 - Prob. 5ECh. 15 - Prob. 6E
Ch. 15 - Prob. 7ECh. 15 - Prob. 8ECh. 15 - Prob. 9ECh. 15 - Prob. 10ECh. 15 - Prob. 11ECh. 15 - Prob. 12ECh. 15 - Prob. 13ECh. 15 - Define eutrophication.Ch. 15 - Prob. 15ECh. 15 - Prob. 16ECh. 15 - Prob. 17ECh. 15 - Prob. 18ECh. 15 - Prob. 19ECh. 15 - What are the three types of interactions that...Ch. 15 - Prob. 21ECh. 15 - Prob. 22ECh. 15 - Prob. 23ECh. 15 - Prob. 24ECh. 15 - Prob. 25ECh. 15 - Prob. 26ECh. 15 - Prob. 27ECh. 15 - Prob. 28ECh. 15 - Prob. 29ECh. 15 - How do sunscreens protect your skin from the Suns...Ch. 15 - Prob. 31ECh. 15 - Prob. 32ECh. 15 - Prob. 33ECh. 15 - Prob. 34ECh. 15 - Prob. 35ECh. 15 - Prob. 36ECh. 15 - Prob. 37ECh. 15 - Prob. 38ECh. 15 - Prob. 39ECh. 15 - Prob. 40ECh. 15 - Prob. 41ECh. 15 - Prob. 42ECh. 15 - Prob. 43ECh. 15 - Prob. 44ECh. 15 - Prob. 45ECh. 15 - Prob. 46ECh. 15 - The salt bridges that hold hair protein (keratin)...Ch. 15 - Prob. 48ECh. 15 - The hydrochloric acid present in toilet bowl...Ch. 15 - Prob. 50ECh. 15 - Prob. 51ECh. 15 - Prob. 52ECh. 15 - Prob. 53ECh. 15 - Prob. 54ECh. 15 - Prob. 55ECh. 15 - Prob. 56ECh. 15 - Prob. 57ECh. 15 - Prob. 58ECh. 15 - Prob. 59ECh. 15 - Prob. 60ECh. 15 - Prob. 61ECh. 15 - Prob. 62ECh. 15 - Prob. 64ECh. 15 - Prob. 65E
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- Explain why butter is solid in room temperature, while vegetable oil is liquid?arrow_forward4. What type of bond promotes solubility of alcohols in water? A. Hydrogen bonds B. Dipole-dipole bonds C. Covalent bonds D. Van der Waals forcesarrow_forward3. Compare the following set of molecules in terms of the properties indicated in each item. Explain your answer based on their intermolecular interaction not on actual values from books or other sources. a. Butane and butanol in terms of boiling point b. Cl2 and HCl in terms of solubility in water c. Propane and Hexane in terms of physical statearrow_forward
- Select the compound with the higher boiling point. HF or HCLarrow_forwardWhat intermolecular forces control melting points of cinnamon acid?arrow_forwardPropane boils at -42 degree Celsius, ethanal boils at 20.8 degree Celsius and ethanol boils at 78.3 degree Celsius. Although their molecular masses are very similar, their boiling points are very different, explain why?arrow_forward
- Diagram the hydrogen bonds that form between water molecules and explain how those bonds produce the unique properties of water.arrow_forward12. Normal boiling point of ethanol (C2H5OH) is 78 °C, and of propanol (C3H;OH) is 97 °C. a. Explain the reason for the difference in boiling points of these two alcohols. b. When the underline methyl group in propanol, CH3CH2CH2OH, is replaced with a hydroxyl group (HOCH2CH2OH), boiling point of the molecule increases to 197 °C. Explain the reason for observed increase in the boiling point.arrow_forwardCompare the TWO structures represented below: 0=S=0 Molecule A Molecule B a. Molecule A has a boiling point of -60 °C and Molecule B has a boiling point of -10 °C. Write 3 sentences to explain this difference in terms of the intermolecular forces that exist between the molecules in each pure substance (you might draw structural diagrams to support your explanation). b. Calculate the enthalpy of vaporization (AvapH) for Molecule A using the following experimental data: the vapour pressure is measured to be 6000 kPa at 75 °C and is 8800 kPa at 95 °C. H-S-Harrow_forward
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