BIOLOGY 12E CONNECT ACCESS CARD
12th Edition
ISBN: 9781264938513
Author: Raven
Publisher: MCG
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Textbook Question
Chapter 15, Problem 3S
Describe how each of the following mutations will affect the final protein product (protein begins with start codon). Name the type of mutation.
Original template strand:
3′ – CGTTACCCGACCGTACGATTAGG–5′
3′ – CGTTACCCGAGCCGTAACGATTAGG –5′
3′ – CGTTACCCGATCCGTACGATTAGG –5′
3′ – CGTTACCCGAGCCGTTCGATTAGG –5′
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The sequence of the coding strand of a bacterial gene is given below. The positions of the first nine bases are numbered for your convenience. A missense mutation was introduced at position seven where the C was changed to a T resulting a mutant gene.
123456789
5'- ATGGCCCGACCGCAACTTTTCCGAGCTCTGGTGTCTGCGCAGTGACC-3
a. Write the template DNA (complementary strand) sequence for the wild type gene above
b. Write the DNA sequence of the mutant gene (Both DNA strands)
c. Write the sequence of mRNA produced from the mutant gene
d. Write the sequence of the mutant protein using the codon usage table provided in the end of this document.
Consider the following DNA template:
5’-AAGAGGTTCCAATGCAGGCACTCACCAACTCTTAAATAAA-3’
3’-TTCTCCAAGGTTACGTCCGTGAGTGGTTGAGAATTTATTT-5’
If the bottom DNA strand is used as template to transcribe mRNA, predict the amino acid sequence that would result from the process of translation.
Met-Ala-Leu-Thr-Gln-Glu-Gly
Met-Gly-Ser-Leu-Asn-Ser-Gln
Met-Thr-Asn-Ser-Leu-Ala-Gln
Met-Gln-Ala-Leu-Thr-Asn-Ser
Met-Glu-Ala-His-Trp-Ser-Tyr
What is the sequence of the mRNA transcript that will be produced from the following sequence of DNA? The top strand is the template strand, the bottom strand is the coding strand.
5’ – TCGGGATTAGACGCACGTTGGCATACCTCG – 3’
3’ – AGCCCTAATCTGCGTGCAACCGTATGGAGC – 5’
Enter the mRNA sequence here (pay close attention to the direction of the molecule!): 5'-_____-3'
Chapter 15 Solutions
BIOLOGY 12E CONNECT ACCESS CARD
Ch. 15.1 - Prob. 1LOCh. 15.1 - Prob. 2LOCh. 15.1 - List the roles played by RNA in gene expression.Ch. 15.2 - Prob. 1LOCh. 15.2 - Describe the characteristics of the genetic code.Ch. 15.2 - Prob. 3LOCh. 15.3 - Prob. 1LOCh. 15.3 - Differentiate among initiation, elongation, and...Ch. 15.3 - Prob. 3LOCh. 15.4 - Prob. 1LO
Ch. 15.4 - Prob. 2LOCh. 15.4 - Explain the differences between bacterial and...Ch. 15.5 - Prob. 1LOCh. 15.5 - Prob. 2LOCh. 15.5 - Prob. 3LOCh. 15.6 - Explain why the tRNA charging reaction is critical...Ch. 15.6 - Prob. 2LOCh. 15.7 - Prob. 1LOCh. 15.7 - Prob. 2LOCh. 15.7 - Compare translation on the RER and in the...Ch. 15.9 - Prob. 1LOCh. 15.9 - Explain the nature of triplet repeat expansion.Ch. 15.9 - Prob. 3LOCh. 15 - Prob. 1DACh. 15 - Prob. 2DACh. 15 - Prob. 1IQCh. 15 - Prob. 2IQCh. 15 - Prob. 3IQCh. 15 - The experiments with nutritional mutants in...Ch. 15 - What is the central dogma of molecular biology? a....Ch. 15 - In the genetic code, one codon a. consists of...Ch. 15 - Eukaryotic transcription differs from prokaryotic...Ch. 15 - An anticodon would be found on which of the...Ch. 15 - RNA polymerase binds to a ________ to initiate...Ch. 15 - During translation, the codon in mRNA is actually...Ch. 15 - You have mutants that all affect the same...Ch. 15 - The splicing process a. occurs in prokaryotes. b....Ch. 15 - The enzyme that forms peptide bonds is called...Ch. 15 - In comparing gene expression in prokaryotes and...Ch. 15 - The codon CCA could be mutated to produce a. a...Ch. 15 - An inversion will a. necessarily cause a mutant...Ch. 15 - What is the relationship between mutations and...Ch. 15 - Prob. 1SCh. 15 - Frameshift mutations often result in truncated...Ch. 15 - Describe how each of the following mutations will...Ch. 15 - There are a number of features that are unique 10...
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- This is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: bottom strand is the noncoding strand). 5'-ААCGCATGAGAAAGCCCCCCGGAAGATCACСТТСCGGGGGCТТТАТАТААТТАGC-3' 3'-тTGCGTACтстттCGGGGGGCCTTCTAGTGGAAGGCCCCCGАААТАТАТТААТтCG-5' (i) Draw the structure of hairpin loop that will be formed during transcription. (ii) Illustrate how the hairpin loop structure initiates the termination of transcription.arrow_forwardPlease write the sequence of the mRNA transcript transcribed from the given DNA double helix by indicating template and non template strands.(SLO1)5’-ACGGCATGCATGGTTTAAAAGGGGCCCAAAA-3’3’-TGCCGTACGTACCAAATTTTCCCCGGGTTTT-5’arrow_forwardGiven the following DNA sequence of the template strand for a given gene: 5' TTTCCGTCTCAGGGCTGAAAATGTTTGCTCATCGAACGC3' Part A ) Write the mRNA that will be transcribed from the DNA sequence above (be sure to label the 5' and 3' ends). Part B ) Use the genetic code to write the peptide sequence translated in a cell from the mRNA in part A. Please use the 3 letter abbreviation for each amino acid. Part C: How would the peptide synthesized in a cell be different if the mRNA was translated in vitro (i.e. not in the cell)?arrow_forward
- Using the codon table, identify a 5’-3’ sequence of nucleotides in the dna template strand for mRna coding for the polypeptide sequence NH2-PHe-Pro-lys-COOH.arrow_forwardThe following bacterial DNA sequence uses the top strand as the coding strand and the bottom strand as the template strand. Write what the messenger RNA sequence for this gene would be after transcription occurs.arrow_forwardWhat kind of mutation is present in the following DNA strand?: Wild-type: 3'-AGTCCCTGAAAT-5' Mutant: 3'-AGTCCCTGCAAT-5' Use the codon table if you need it. Answer choices: Deletion, Insertion, Missence, Silent I selected missence, but the answer is incorrect. Please help.arrow_forward
- Use the genetic code table to determine the amino acid sequence of the given message strand of DNA below, from N to C terminal. All introns were removed in this sequence for simplicity. Write the amino acids in their 3-letter abbreviation and separate with a dash.arrow_forwardBelow is the 5’–3’ strand of a double-stranded DNA molecule with the following nucleotide sequences:5’ C C T A T G C A G T G G C C A T A T T C C A A A G C A T A G C 3’1. If the above DNA strand is the coding (sense) strand and the DNA molecule is transcribed, what is the correct nucleotide sequence and direction of the RNA formed after transcription?arrow_forwardWhich of the following represents the sequence of an RNA transcript for which the coding strand (also known as non-template strand) of DNA has the sequence: GTACTGGCTAGCTGCTAGAA? Note all sequences are written 5'-3'. OA. AAGAUCGUCGAUCGGUCAUG OB. AAGATCGTCGATCGG TCATG OC. GTACTGGC TAGCTGC TAGAA OD. GUACUGGCUAGCUGCUAGAAarrow_forward
- The DNA sequence below is transcribed from left to right (the partner/coding strand is shown). Using this sequence, write the sequence of the polypeptide that results from this gene. Be sure to appropriately label the ends of the molecule. 5'-ATGCACGGCGACTAG-3' Second letter A UAU Tyr UAC First letter U A G U UUU1 UUC UUA LOU Leu CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu AUU AUC lle AUA AUG Met Val C UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala CAU His CAC CAA CAG Gin AAU Asn AAC AAA 1 Lys AAG LYS G {}a UAA Stop UGA Stop A UAG Stop UGG Trp GAU 1 GAC Asp GAA GIU Glu GAGJ UGU UGC CGU CGC CGA CGG AGU AGC AGA AGG Cys GGU GGC GGA GGG Arg Ser Arg DOA DOA DOA DUTO Third letter Glyarrow_forwardFor each mutant, state what change has occurred in the DNA, whether it was a substitution by transition or transversion, sense mutation, nonsense or reading frame change. It must present the codon sequence. Normal nucleotide sequence starting from the third codon: CCC-ACG-GUG-ACG-ACA-CGG-UGG Please show the codon and nucleotide sequence of the mutation.arrow_forwardThis is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' Draw the structure of hairpin loop that will be formed during the end of transcription.arrow_forward
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