Exercises 1 through 4 refer to the data set shown in Table 15-12 The table shows the scores on a Chem 103 test consisting of 10 questions worth 10 points each. Table 15-12 Chem 103 test scores Student ID Score Student ID Score 1362 50 4315 70 1486 70 4719 70 1721 80 4951 60 1932 60 5321 60 2489 70 5872 100 2766 10 6433 50 2877 80 6921 50 2964 60 8317 70 3217 70 8854 100 3588 80 8964 80 3780 80 9158 60 3921 60 9347 60 4107 40 Suppose that the grading scale for the test is A : 80 − 100 ; B : 70 − 79 ; C : 60 − 69 ; D : 50 − 59 ; and F : 0 − 49 . a. Make a frequency table for the distribution of the test grades. b. Draw a relative frequency bar graph for the test grades.
Exercises 1 through 4 refer to the data set shown in Table 15-12 The table shows the scores on a Chem 103 test consisting of 10 questions worth 10 points each. Table 15-12 Chem 103 test scores Student ID Score Student ID Score 1362 50 4315 70 1486 70 4719 70 1721 80 4951 60 1932 60 5321 60 2489 70 5872 100 2766 10 6433 50 2877 80 6921 50 2964 60 8317 70 3217 70 8854 100 3588 80 8964 80 3780 80 9158 60 3921 60 9347 60 4107 40 Suppose that the grading scale for the test is A : 80 − 100 ; B : 70 − 79 ; C : 60 − 69 ; D : 50 − 59 ; and F : 0 − 49 . a. Make a frequency table for the distribution of the test grades. b. Draw a relative frequency bar graph for the test grades.
Solution Summary: The author explains the frequency table for the distribution of the test grades. The grading scale is A 80-100 B 70-79 C 60-69
Exercises 1 through 4 refer to the data set shown in Table 15-12 The table shows the scores on a Chem 103 test consisting of 10 questions worth 10 points each.
Table 15-12
Chem 103 test scores
Student ID
Score
Student ID
Score
1362
50
4315
70
1486
70
4719
70
1721
80
4951
60
1932
60
5321
60
2489
70
5872
100
2766
10
6433
50
2877
80
6921
50
2964
60
8317
70
3217
70
8854
100
3588
80
8964
80
3780
80
9158
60
3921
60
9347
60
4107
40
Suppose that the grading scale for the test is
A
:
80
−
100
;
B
:
70
−
79
;
C
:
60
−
69
;
D
:
50
−
59
; and
F
:
0
−
49
.
a. Make a frequency table for the distribution of the test grades.
b. Draw a relative frequency bar graph for the test grades.
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
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How to make Frequency Distribution Table / Tally Marks and Frequency Distribution Table; Author: Reenu Math;https://www.youtube.com/watch?v=i_A6RiE8tLE;License: Standard YouTube License, CC-BY