EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 9780100793439
Author: KALPAKJIAN
Publisher: YUZU
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Chapter 15, Problem 37QLP
In hydrostatic extrusion, complex seals are used between the ram and the container, but not between the billet and the die. Explain why.
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A cylindrical billet that is 80 mm long and 32 mm diameter is reduced by
backward extrusion to a 12 mm diameter. Half die angle is 90°. If the
Johnson equation has a= 0.8 and b= 1.2 , and the flow curve for the work
material has strength coefficient is 500 MPa, and strain hardening
exponent is 0.8, Determine (a) extrusion ration, (b) true strain, (c)
extrusion strain, (d) ram pressure, and (e) ram force.
During a direct extrusion process for a billet with 5 in long and diameter
2.5 in to 1.6 in. For the work metal, strength coefficient is 75000 Ib/in,
and strain hardening exponent is 0.4, also the die angle of extrusion is
90. In Johnson extrusion strain equation a = 0.8, and b= 1.5. Determine:
(a) extrusion ratio (b) true strain (c) extrusion strain, and (d) ram pressure
at length 5, 4.2, 2.3,1.5,and 0 in.
A 3in long and 1in diameter billet is extruded in a direct extrusion operation with an rx = 4.0. The extrusion has a cross section. The angle of the die (half angle) is 90o. The work metal has a resistance coefficient of 60ksi and a strain hardening exponent of 0.18. Use Johnston's formula with a = 0.8 and b = 1.5 to estimate the extrusion stress. Determine the pressure applied to the end of the billet when the piston moves forward.
Chapter 15 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 15 - How does extrusion differ from rolling and...Ch. 15 - Explain the difference between extrusion and...Ch. 15 - What is a spider die? What is it used for?Ch. 15 - Why are wires sometimes drawn in bundles?Ch. 15 - What is a dead-metal zone?Ch. 15 - Define the terms (a) cladding, (b) dummy block,...Ch. 15 - Why is glass a good lubricant in hot extrusion?Ch. 15 - What types of defects may occur in (a) extrusion...Ch. 15 - Describe the difference between direct and reverse...Ch. 15 - What is land? What is its function in a die?
Ch. 15 - How are tubes extruded? Can they also be drawn?...Ch. 15 - Prob. 12RQCh. 15 - What is the difference between piping and...Ch. 15 - What is impact extrusion?Ch. 15 - What is the pipe defect in extrusion?Ch. 15 - List the similarities and differences between...Ch. 15 - Explain why extrusion is a batch, or...Ch. 15 - The extrusion ratio, die geometry, extrusion...Ch. 15 - Explain why cold extrusion is an important...Ch. 15 - What is the function of a stripper plate in impact...Ch. 15 - Explain the different ways by which changing the...Ch. 15 - Glass is a good lubricant in hot extrusion. Would...Ch. 15 - How would you go about avoiding center-cracking...Ch. 15 - Table 15.1 gives temperature ranges for extruding...Ch. 15 - Will the force in direct extrusion vary as the...Ch. 15 - Comment on the significance of metal flow patterns...Ch. 15 - In which applications could you use the type of...Ch. 15 - What is the purpose of the land in a drawing die?...Ch. 15 - Can spur gears be made by (a) drawing and (b)...Ch. 15 - How would you prepare the end of a wire in order...Ch. 15 - What is the purpose of a dummy block in extrusion?...Ch. 15 - Describe your observations concerning Fig. 15.9.Ch. 15 - Occasionally, steel wire drawing will take place...Ch. 15 - Explain the advantages of bundle drawing.Ch. 15 - Under what circumstances would backward extrusion...Ch. 15 - Why is lubrication detrimental in extrusion with a...Ch. 15 - In hydrostatic extrusion, complex seals are used...Ch. 15 - Describe the purpose of a container liner in...Ch. 15 - Estimate the force required in extruding 7030...Ch. 15 - Assuming an ideal drawing process, what is the...Ch. 15 - Prob. 41QTPCh. 15 - Calculate the extrusion force for a round billet...Ch. 15 - Prob. 43QTPCh. 15 - A round wire made of a perfectly plastic material...Ch. 15 - Assume that the summary to this chapter is...Ch. 15 - Prob. 47SDPCh. 15 - Figure 15.2 shows examples of discrete parts that...Ch. 15 - The parts shown in Fig. 15.2 are economically...Ch. 15 - Survey the technical literature, and explain how...Ch. 15 - Prob. 51SDPCh. 15 - List the processes that are suitable for producing...
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- The process of extrusion is usually described as a semi-continuous operation. Explain it?arrow_forwardA upset forging operation is performed in an open die. The initial size of the workpart is: Do = 63 mm, and ho = 100 mm. The part is upset to a diameter = 70 mm. The work metal has a flow curve with strength coefficient = 600 MPa and strain hardening exponent= 0.22. Coefficient of friction at the die-work interface = 0.40. Determine (a) final height of the part, and (b) maximum force in the operation.arrow_forwardA direct extrusion operation produces a product with a 20 mm x 60 mm cross sectional area from a brass billet whose diameter = 125 mm and length = 350 mm. The flow curve parameters of the brass are K = 700 MPa and n = 0.35. In the Johnson strain equation, a = 0.7 and b = 1.4. Determine (a) the extrusion ratio, (b) the shape factor, (c) the force required to drive the ram forward during extrusion at the point in the process when the billet length remaining in the container = 300 mm, and (d) the length of the extruded section at the end of the operation if the volume of the butt left in the container is 600,000 mm3arrow_forward
- A billet 75mmlong and 25mmin diameter is to be extruded in a direct extrusion operation with extrusion ratio rx = 4.0. The extrudate has a round cross section. The die angle (half angle) = 90° The work metal has a strength coefficient = 415 MPa, and strainhardening exponent = 0.18. Use the Johnson formula with a = 0.8 and b = 1.5 to estimate extrusion strain. Determine the pressure applied to the end of the billet as the ram moves forwardarrow_forwardA cylindrical part is warm upset forged in an open die. The initial diameter is 50 mm and the initial height is 40 mm. The height after forging is 30 mm. The coefficient of friction at the die-work interface is 0.25. The yield strength of the work material is 285 MPa, and its flow curve is defined by a strength coefficient of 600 MPa and a strain-hardening exponent of 0.12. Calculate the strain at yield point.arrow_forwardCalculate the ram pressure during indirect extrusion process when a cylindrical billet is 300 mm long and 150 mm in diameter used to produce a 45 mm diameter. In this process: a=0.8, b=1.4, K=275MPA, n=0.12.arrow_forward
- A billet 100 mm long and 30 mm in diameter is to be extruded in a direct extrusion operation with extrusion ratio r, = 3.5. The extrudate has a round cross section. The die angle (half angle) = 60°. The work metal has a strength coefficient = 720 MPa, and strain hardening exponent = 0.17. Use the Johnson formula with a = 0.8 andb= 1.2 to estimate extrusion strain. Determine the following: 1. Diameter of the extrudate = mm 2. Butt volume = mm3 3. Actual extrudate length = mm 4. The pressure applied to perform the extrusion process = MPa 5. Ram force = N.arrow_forward◆ A billet 75 mm long and 25 mm in diameter is to be extruded in a direct extrusion operation with extrusion ratio rx = 4.0. The extrudate has a round cross section. The die angle (half angle)=90. The work metal has a strength coefficient =-415 MPa, and strain-hardening exponent = 0.18. Use the Johnson formula with a = 0.8 and b = 1.5 to estimate extrusion strain. Determine the pressure applied to the end of the billet as the ram moves forward.arrow_forwardWith a neat diagram differentiate the direct and indirect extrusion process. Write any two advantages and applications of extrusion.arrow_forward
- One way to describe forging processes is by the amount of work that can be done in the die. Based on this grouping, what are the three main types?arrow_forwardExample 10.3 A cylindrical billet of 40 mm diameter and 100 mm length is reduced by indirect (backward) extrusion to a 15 mm diameter using Flat dies. If the Johnson equation has a = 0.8 and b = 1.5 and the flow curve for the work metal has K = 750 MPa and n = 0.15, determine : (i) Extrusion rations (ii) True strain (homogencous deformation) (iii) Extrusion strain (iv) Ram forcearrow_forwardAn open die forging operation is performed to produce a steel cylinder with a diameter of 9.7mm and a height of 1.7mm. The strength coefficient for this steel is 500MPA, and the strain hardening exponent is 0.25. Coefficient of friction at the die-work interface is 0.12. The initial stock of raw material has a diameter of 5mm. (a) What height/length of stock is needed to provide sufficient volume of material for this forging operation? (b) Compute the maximum force that the punch must apply to form the head in this open- die operation.arrow_forward
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