Biology
12th Edition
ISBN: 9781260494570
Author: Raven, Peter
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Textbook Question
Chapter 15, Problem 2U
What is the central dogma of molecular biology?
a. DNA is the genetic material.
b. Information passes from DNA directly to protein.
c. Information passes from DNA to RNA to protein.
d. One gene encodes only one polypeptide.
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Chapter 15 Solutions
Biology
Ch. 15.1 - Prob. 1LOCh. 15.1 - Prob. 2LOCh. 15.1 - List the roles played by RNA in gene expression.Ch. 15.2 - Prob. 1LOCh. 15.2 - Describe the characteristics of the genetic code.Ch. 15.2 - Prob. 3LOCh. 15.3 - Prob. 1LOCh. 15.3 - Differentiate among initiation, elongation, and...Ch. 15.3 - Prob. 3LOCh. 15.4 - Prob. 1LO
Ch. 15.4 - Prob. 2LOCh. 15.4 - Explain the differences between bacterial and...Ch. 15.5 - Prob. 1LOCh. 15.5 - Prob. 2LOCh. 15.5 - Prob. 3LOCh. 15.6 - Explain why the tRNA charging reaction is critical...Ch. 15.6 - Prob. 2LOCh. 15.7 - Prob. 1LOCh. 15.7 - Prob. 2LOCh. 15.7 - Compare translation on the RER and in the...Ch. 15.9 - Prob. 1LOCh. 15.9 - Explain the nature of triplet repeat expansion.Ch. 15.9 - Prob. 3LOCh. 15 - Prob. 1DACh. 15 - Prob. 2DACh. 15 - Prob. 1IQCh. 15 - Prob. 2IQCh. 15 - Prob. 3IQCh. 15 - The experiments with nutritional mutants in...Ch. 15 - What is the central dogma of molecular biology? a....Ch. 15 - In the genetic code, one codon a. consists of...Ch. 15 - Eukaryotic transcription differs from prokaryotic...Ch. 15 - An anticodon would be found on which of the...Ch. 15 - RNA polymerase binds to a ________ to initiate...Ch. 15 - During translation, the codon in mRNA is actually...Ch. 15 - You have mutants that all affect the same...Ch. 15 - The splicing process a. occurs in prokaryotes. b....Ch. 15 - The enzyme that forms peptide bonds is called...Ch. 15 - In comparing gene expression in prokaryotes and...Ch. 15 - The codon CCA could be mutated to produce a. a...Ch. 15 - An inversion will a. necessarily cause a mutant...Ch. 15 - What is the relationship between mutations and...Ch. 15 - Prob. 1SCh. 15 - Frameshift mutations often result in truncated...Ch. 15 - Describe how each of the following mutations will...Ch. 15 - There are a number of features that are unique 10...
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- which event contradicts the central dogma of molecular biology?arrow_forwardWhich of the following is true about the three major classes of RNAs in the cell: mRNAs, tRNAs, and rRNAs? A. mRNAs encode polypeptide chains. B. tRNAs are structural components of the ribosome. C. rRNAs are adapter molecules that translate the information on an mRNA into a polypeptide sequence. D. mRNAs can also encode tRNAs and rRNAs.arrow_forwardWhy can the transcriptome not be used to predict the proteome with complete accuracy? a. It cannot be sequenced like the genome can be. b. The transcriptome is too dynamic to be used to make predictions. c. Not all genes are transcribed. d. Many transcripts are alternatively spliced to produce different proteins.arrow_forward
- Which of the following does not conform about Genetic Engineering? * a. used recombinant DNA (rDNA) technology b. direct manipulation of only one gene c. requires complex machinery and innovative minds d. process of manually transferring genetic informationarrow_forwardYou are working in the lab and have measured the size of mRNA that has been transcribed from a particular gene in your cell population. The length of the gene in the cells you are working, measured from the start to the stop sequence is 9000 nucleotides. When you measure the RNA, however, the size is only 3000 nucleotides. What do you think happened? O a. Three DNA base pairs code for one RNA nucleotide. b. mRNA does not contain exons. c. There must have been a deletion mutation in the DNA in these cells. Od. The poly-A tail is present in the DNA but not on the mRNA. Oe. RNA splicing occurred, so introns are removed in the mRNA.arrow_forwardWhich of the following is FALSE about the human genome? a. repetitive DNA is approximately 50% of the base pairs b. less than 5% of the DNA codes for unique proteins c. many genes have introns d. The genes are all unique to humans and show no similarity to genes from other organisms.arrow_forward
- The original DNA base sequence is 5’-AGCGTTACCGT-3’; a mutation in the DNA strand results in the base sequence 5’-AGGCGTTACCGT-3’. What can you conclude about the mutation? A. It is a frameshift mutation. B. It is a silent mutation. C. It is a deleterious mutation. D. It may result in a single amino acid change in the protein being coded for by this base sequence.arrow_forwardWhat observations are consistent with the conclusion that DNA serves as the genetic material in eukaryotes? Select the four correct statements. a. DNA content and ploidy in various cell types( sperm and somatic cells) are related b. DNA is found to be the only macromolecule in eukaryotes that has different subunits. c. Gene transfer is a direct evidence as it has been facilitated by recombinant DNA techniques. d. The correlation of the action and absorption spectra of ultraviolet light support the interpretation that DNA is a genetic material. e. DNA is shown to be present in ribosomes, matrix, and nucleus, where genetic function is performed. f. DNA is shown to be present in mitochondria, chloroplasts, and nucleus, where genetic function is performed.arrow_forwardWhat is the difference between orthologs and paralogs? a. Orthologs are homologous sequences; paralogs are analogous sequences. b. Orthologs are more similar than paralogs. c. Orthologs are in the same species; paralogs are in different species. d. Orthologs are in different species; paralogs are in the same species.arrow_forward
- If Avery, MacLeod, and McCarty had found that samples of heat-killed bacteria treated with RNase and DNase transformed bacteria, but that samples treated with protease did not, what conclusion would they have drawn? a. Protease carries out transformation. b. RNA and DNA are the genetic materials. c. Protein is the genetic material. d. RNase and DNAse are necessary for transformationarrow_forwardWhen using gene therapy to treat an hereditary disease, the idea is to: A. Introduce the correct gene into the patient's DNA B. Inject the patient with a specific protein to cure the disease. C. Blood transfusions from healthy individuals. D. ntroduce mRNA molecules with the correct genetic information to the patient. E. Introduce a virus to the patient that will specifically destroy mutated cells.arrow_forwardWhat did the Hershey / Chase experiments (above) demonstrate about the molecules responsible for genetic inheritance patterns in the T2 bacteriophage? A. the genetic material consists of carbohydrates, not RNA B. the genetic material consists of protein, not lipids C. the genetic material consists of DNA, not polypeptides D. the genetic material consists of protein, not DNA E. the genetic material consists of lipids, not polypeptidesarrow_forward
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