Concept explainers
(a)
Interpretation:
Chalk should be classified as chiral or achiral.
Concept Introduction:
Chirality is the presence of an asymmetric carbon center in a molecule and a molecule which contains a chiral center cannot superimpose on its mirror image. To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other.
In the above diagram, where C is the chiral center/ asymmetric carbon center.
A, B, D, E are four different
Answer to Problem 21P
Chalk is achiral.
Explanation of Solution
To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other. The mirror image of chalk is identical and is superimposable on their mirror images. Though they have not sharpened edges, the object and its mirror images are superimposable with each other. Thus, chalk is achiral.
(b)
Interpretation:
Pair of shoes should be classified as chiral or achiral.
Concept Introduction:
Chirality is the presence of an asymmetric carbon center in a molecule and a molecule which contains a chiral center cannot superimpose on its mirror image. To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other.
In the above diagram, where C is the chiral center/ asymmetric carbon center.
A, B, D, E are four different functional groups.
Answer to Problem 21P
Pair of shoes are chiral.
Explanation of Solution
To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other. The mirror image of pair of shoes arenot identical and not superimposable. The object and its mirror images are not superimposable with each otherand not align all the parts of the objects with its mirror image. Thus, pair of shoes are chiral.
(c)
Interpretation:
A football should be classified as chiral or achiral.
Concept Introduction:
Chirality is the presence of an asymmetric carbon center in a molecule and a molecule which contains a chiral center cannot superimpose on its mirror image. To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other.
In the above diagram, where C is the chiral center/ asymmetric carbon center.
A, B, D, E are four different functional groups.
Answer to Problem 21P
Football is achiral.
Explanation of Solution
To be considered as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other. The mirror image of a football is identical and superimposable. The object and its mirror images are superimposable with each other. Thus, football is achiral.
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Chapter 15 Solutions
General, Organic, and Biological Chemistry - 4th edition
- Propose a synthesis of 1-butanamine from the following: (a) a chloroalkane of three carbons (b) a chloroalkane of four carbonsarrow_forwardSelect the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forward
- b. H3C CH3 H3O+ ✓ H OHarrow_forward2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forward
- Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forwardInstructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forward
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning