(a) Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn. Concept introduction: The general steps followed by free-radical reaction are stated below: 1. First step is initiation that involves formation of radical. 2. Second step is propagation. 3. Third step is the termination that involves the formation of stable bond.

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Answer 1

Question

Chapter 15, Problem 15.66P

Interpretation Introduction

(a)

Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Interpretation Introduction

(b)

Interpretation: An explanation for the given statement that the homolysis of this OH bond is preferred to the homolysis of either OH bond in the other benzene ring is to be stated.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

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Resveratrol is an antioxidant found in the skin of red grapes. Its anticancer, anti-inflammatory, and various cardiovascular effects are under active investigation. (a) Draw all resonance structures for the radical that results from homolysis of the OH bond shown in red. (b) Explain why homolysis of this OH bond is preferred to homolysis of either OH bond in the other benzene ring.

1) The carbon-oxygen double bond present in aldehydes and ketones is very polar. What does this mean and how does it arise? 2) The carbon-oxygen double bond is readily attacked by nucleophiles like cyanide ions or ammonia. (i) What do you understand by the term nucleophile? (ii) Which part of the carbon-oxygen double bond is attractive to nucleophiles? 3) Why is there a difference between aldehydes and ketones in their response to oxidizing agents such as potassium dichromate(VI) solution acidified with dilute sulfuric acid?

Consider the tetracyclic compound with rings labeled A–D. (a) Which ring is the most reactive in electrophilic aromatic substitution? (b) Which ring is the least reactive in electrophilic aromatic substitution?

Answer 2

Question

Chapter 15, Problem 15.66P

Interpretation Introduction

(a)

Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Interpretation Introduction

(b)

Interpretation: An explanation for the given statement that the homolysis of this OH bond is preferred to the homolysis of either OH bond in the other benzene ring is to be stated.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

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Answer 3

Question

Chapter 15, Problem 15.66P

Interpretation Introduction

(a)

Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Interpretation Introduction

(b)

Interpretation: An explanation for the given statement that the homolysis of this OH bond is preferred to the homolysis of either OH bond in the other benzene ring is to be stated.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

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Answer 4

Question

Chapter 15, Problem 15.66P

Interpretation Introduction

(a)

Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Interpretation Introduction

(b)

Interpretation: An explanation for the given statement that the homolysis of this OH bond is preferred to the homolysis of either OH bond in the other benzene ring is to be stated.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

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Answer 5

Chapter 15, Problem 15.66P

Interpretation Introduction

(a)

Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Interpretation Introduction

(b)

Interpretation: An explanation for the given statement that the homolysis of this OH bond is preferred to the homolysis of either OH bond in the other benzene ring is to be stated.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Answer 6

Chapter 15, Problem 15.66P

Interpretation Introduction

(a)

Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Answer 7

Chapter 15, Problem 15.66P

Interpretation Introduction

(a)

Interpretation: All resonance structures for the radical that result from the homolysis of OH bond are to be drawn.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Answer 8

Interpretation Introduction

(b)

Interpretation: An explanation for the given statement that the homolysis of this OH bond is preferred to the homolysis of either OH bond in the other benzene ring is to be stated.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Answer 9

Interpretation Introduction

(b)

Interpretation: An explanation for the given statement that the homolysis of this OH bond is preferred to the homolysis of either OH bond in the other benzene ring is to be stated.

Concept introduction: The general steps followed by free-radical reaction are stated below:

1. First step is initiation that involves formation of radical.

2. Second step is propagation.

3. Third step is the termination that involves the formation of stable bond.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 15 - Prob. 15.1P Ch. 15 - Prob. 15.2P Ch. 15 - Prob. 15.3P Ch. 15 - Prob. 15.4P Ch. 15 - Prob. 15.5P Ch. 15 - Problem 15.6 Using mechanism 15.1 as guide, write...Ch. 15 - Prob. 15.7P Ch. 15 - Problem 15.8 Which bond in the each compound is...Ch. 15 - Prob. 15.9P Ch. 15 - Prob. 15.10P

Solution Summary: The author explains that the radical formed by the homolysis of OH bond is shown in Figure 1.

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