PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.
2nd Edition
ISBN: 9781266811852
Author: SMITH
Publisher: MCG
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Chapter 15, Problem 15.62AP
Why are LDLs soluble in the blood?
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6. The equilibrium constant for the reaction
2 HBr (g)
→ H2(g) + Br2(g)
Can be expressed by the empirical formula
11790 K
In K-6.375 + 0.6415 In(T K-¹)
-
T
Use this formula to determine A,H as a function of temperature. Calculate A,-H at 25 °C and at
100 °C.
3. Nitrosyl chloride, NOCI, decomposes according to
2 NOCI (g) → 2 NO(g)
+ Cl2(g)
Assuming that we start with no moles of NOCl (g) and no NO(g) or Cl2(g), derive an expression
for Kp in terms of the equilibrium value of the extent of reaction, Seq, and the pressure, P.
Given that K₂ = 2.00 × 10-4, calculate Seq/
of
29/no when P = 0.080 bar. What is the new value
по
ƒª/ at equilibrium when P = 0.160 bar? Is this result in accord with Le Châtelier's
Principle?
Consider the following chemical equilibrium:
2SO2(g) + O2(g) = 2SO3(g)
•
Write the equilibrium constant expression for this reaction.
Now compare it to the equilibrium constant expression for the related reaction:
•
.
1
SO2(g) + O2(g) = SO3(g)
2
How do these two equilibrium expressions differ?
What important principle about the dependence of equilibrium constants on the stoichiometry of a
reaction can you learn from this comparison?
Chapter 15 Solutions
PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.
Ch. 15.1 - In which solvents or solutions will a lipid be...Ch. 15.2 - (a) Draw a skeletal structure for each fatty acid....Ch. 15.2 - Prob. 15.3PCh. 15.2 - Prob. 15.4PCh. 15.3 - Draw the structure of a wax formed from stearic...Ch. 15.3 - One component of jojoba oil is a wax formed from...Ch. 15.3 - What hydrolysis products are formed when cetyl...Ch. 15.4 - Draw the structure of a triacylglycerol that...Ch. 15.4 - Prob. 15.9PCh. 15.4 - Draw the structure of a triacylglycerol that fits...
Ch. 15.5 - Draw the products formed from hydrolysis of each...Ch. 15.5 - Prob. 15.12PCh. 15.6 - Draw the structure of two different cephalins...Ch. 15.6 - Classify each lipid as a triacylglycerol,...Ch. 15.7 - Why are phospholipids rather than triacylglycerols...Ch. 15.7 - Prob. 15.16PCh. 15.8 - Prob. 15.17PCh. 15.8 - Prob. 15.18PCh. 15.9 - Prob. 15.19PCh. 15.9 - Prob. 15.20PCh. 15.10 - Why is it much easier to overdose on a fat-soluble...Ch. 15.10 - Prob. 15.22PCh. 15 - Prob. 15.23UKCCh. 15 - Prob. 15.24UKCCh. 15 - Prob. 15.25UKCCh. 15 - What hydrolysis products are formed when the wax...Ch. 15 - Prob. 15.27UKCCh. 15 - Prob. 15.28UKCCh. 15 - Draw the products formed when the given...Ch. 15 - Prob. 15.30UKCCh. 15 - Prob. 15.31UKCCh. 15 - Prob. 15.32UKCCh. 15 - Prob. 15.33APCh. 15 - Label each compound as a hydrolyzable or...Ch. 15 - Prob. 15.35APCh. 15 - Prob. 15.36APCh. 15 - Prob. 15.37APCh. 15 - How does each of the following affect the melting...Ch. 15 - Rank the fatty acids in order of increasing...Ch. 15 - How would you expect the melting points of the...Ch. 15 - Prob. 15.41APCh. 15 - Why are soaps water soluble, but the fatty acids...Ch. 15 - Draw the structure of a wax formed from palmitic...Ch. 15 - Prob. 15.44APCh. 15 - Prob. 15.45APCh. 15 - Prob. 15.46APCh. 15 - Prob. 15.47APCh. 15 - What hydrolysis products are formed when each wax...Ch. 15 - Draw a triacylglycerol that fits each description:...Ch. 15 - Draw a triacylglycerol that fits each description:...Ch. 15 - Prob. 15.51APCh. 15 - Prob. 15.52APCh. 15 - Prob. 15.53APCh. 15 - Prob. 15.54APCh. 15 - Prob. 15.55APCh. 15 - Draw the products formed when the given...Ch. 15 - Prob. 15.57APCh. 15 - Prob. 15.58APCh. 15 - Prob. 15.59APCh. 15 - Prob. 15.60APCh. 15 - Prob. 15.61APCh. 15 - Why are LDLs soluble in the blood?Ch. 15 - Describe the role of HDLs and LDLs in cholesterol...Ch. 15 - Prob. 15.64APCh. 15 - Prob. 15.65APCh. 15 - Prob. 15.66APCh. 15 - Answer each question with regards to vitamins A...Ch. 15 - Answer each question in Problem 15.67 for vitamins...Ch. 15 - Prob. 15.69APCh. 15 - Prob. 15.70APCh. 15 - Prob. 15.71APCh. 15 - How are soaps and phosphoacylglycerols similar in...Ch. 15 - Some fish oils contain triacylglycerols formed...Ch. 15 - Some marine plankton contain triacylglycerols...Ch. 15 - Prob. 15.75APCh. 15 - Prob. 15.76APCh. 15 - Prob. 15.77APCh. 15 - Prob. 15.78APCh. 15 - Prob. 15.79CPCh. 15 - Prob. 15.80CP
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- Given Kp for 2 reactions. Find the Kp for the following reaction: BrCl(g)+ 1/2 I2(g) ->IBr(g) + 1/2 Cl2(g)arrow_forwardFor a certain gas-phase reaction at constant pressure, the equilibrium constant Kp is observed to double when the temperature increases from 300 K to 400 K. Calculate the enthalpy change of the reaction, Ah, using this information.arrow_forwardHydrogen bonding in water plays a key role in its physical properties. Assume that the energy required to break a hydrogen bond is approximately 8 kJ/mol. Consider a simplified two-state model where a "formed" hydrogen bond is in the ground state and a "broken" bond is in the excited state. Using this model: • Calculate the fraction of broken hydrogen bonds at T = 300 K, and also at T = 273 K and T = 373 K. • At what temperature would approximately 50% of the hydrogen bonds be broken? • What does your result imply about the accuracy or limitations of the two-state model in describing hydrogen bonding in water? Finally, applying your understanding: • Would you expect it to be easier or harder to vaporize water at higher temperatures? Why? If you were to hang wet laundry outside, would it dry more quickly on a warm summer day or on a cold winter day, assuming humidity is constant?arrow_forward
- (3 pts) Use the Kapustinskii equation to calculate the lattice enthalpy for MgBr2 anddiscuss any differences between this result and that from #4.arrow_forward(3 pts) Silver metal adopts a fcc unit cell structure and has an atomic radius of 144 pm. Fromthis information, calculate the density of silver. Show all work.arrow_forward4. (3 pts) From the information below, determine the lattice enthalpy for MgBr2. Show all work. AH/(kJ mol-¹) Sublimation of Mg(s) +148 lonization of Mg(g) +2187 to Mg2+(g) Vaporization of Br₂(1) +31 Dissociation of Br,(g) +193 Electron gain by Br(g) -331 Formation of MgBr₂(s) -524arrow_forward
- 1. (4 pts-2 pts each part) Consider the crystal structures of NaCl, ZnS, and CsCl (not necessarily shown in this order). a. For one of the three compounds, justify that the unit cell is consistent with stoichiometry of the compound. b. In each of the crystal structures, the cations reside in certain holes in the anions' packing structures. For each compound, what type of holes are occupied by the cations and explain why those particular types of holes are preferred.arrow_forward(2 pts) What do you expect to happen in a Na2O crystal if a Cl− ion replaces one of the O2−ions in the lattice?arrow_forward(2 pts) WSe2 is an ionic compound semiconductor that can be made to be p-type or n-type.What must happen to the chemical composition for it to be p-type? What must happen tothe chemical composition for it to be n-type?arrow_forward
- 8. (2 pts) Silicon semiconductors have a bandgap of 1.11 eV. What is the longest photon wavelength that can promote an electron from the valence band to the conduction band in a silicon-based photovoltaic solar cell? Show all work. E = hv = hc/λ h = 6.626 x 10-34 Js c = 3.00 x 108 m/s 1 eV 1.602 x 10-19 Jarrow_forwardA solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l) E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 Varrow_forwardFrom the following reduction potentials I2 (s) + 2e- = 2I- (aq) E0= 0.535 V I2 (aq) + 2e- = 2I- (aq) E0= 0.620 V I3- (aq) + 2e- = 3I- (aq) E0= 0.535 V a) Calculate the equilibrium constant for I2 (aq) + I- (aq) = I3- (aq). b) Calculate the equilibrium constant for I2 (s) + I- (aq) = I3- (aq). c) Calculate the solubility of I2 (s) in water.arrow_forward
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