Principles of Instrumental Analysis
7th Edition
ISBN: 9781305577213
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cengage Learning
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Chapter 15, Problem 15.5QAP
Interpretation Introduction
Interpretation:
The reason for some absorbing compounds being fluoresce but others are not is to be stated.
Concept introduction:
Fluorescence is a term used to define the members of the luminescence family. In the luminescence family, the molecules of a substance can produce their own light with the help for electronically excited states which can be formed by chemical,physical or mechanical mechanism.
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The table includes macrostates characterized by 4 energy levels (&) that are
equally spaced but with different degrees of occupation.
a) Calculate the energy of all the macrostates (in joules). See if they all have
the same energy and number of particles.
b) Calculate the macrostate that is most likely to exist. For this macrostate,
show that the population of the levels is consistent with the Boltzmann
distribution.
macrostate 1 macrostate 2 macrostate 3
ε/k (K) Populations
Populations
Populations
300
5
3
4
200
7
9
8
100
15
17
16
0
33
31
32
DATO: k = 1,38×10-23 J K-1
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In an experiment, the viscosity of water was measured at different
temperatures and the table was constructed from the data obtained.
a) Calculate the activation energy of viscous flow (kJ/mol).
b) Calculate the viscosity at 30°C.
T/°C
0
20
40
60
80
η/cpoise 1,972 1,005 0,656 0,469 0,356
Chapter 15 Solutions
Principles of Instrumental Analysis
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- A laser emits a line at 632.8 nm. If the cavity is 12 cm long, how many modes oscillate in the cavity? How long does it take for the radiation to travel the entire cavity? What is the frequency difference between 2 consecutive modes?(refractive index of the medium n = 1).arrow_forwardThe number of microstates corresponding to each macrostate is given by N. The dominant macrostate or configuration of a system is the macrostate with the greatest weight W. Are both statements correct?arrow_forwardFor the single step reaction: A + B → 2C + 25 kJ If the activation energy for this reaction is 35.8 kJ, sketch an energy vs. reaction coordinate diagram for this reaction. Be sure to label the following on your diagram: each of the axes, reactant compounds and product compounds, enthalpy of reaction, activation energy of the forward reaction with the correct value, activation energy of the backwards reaction with the correct value and the transition state. In the same sketch you drew, after the addition of a homogeneous catalyst, show how it would change the graph. Label any new line "catalyst" and label any new activation energy.arrow_forward
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