Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)
5th Edition
ISBN: 9780133887518
Author: H. Scott Fogler
Publisher: Prentice Hall
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Chapter 15, Problem 15.5P
(a)
Interpretation Introduction
Interpretation:
The concentration of reactant at a distance of
(b)
Interpretation Introduction
Interpretation:
If the effectiveness factor is to be 0.8, to what diameter should the pellet be reduced has to be determined.
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P1
(a)
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%at
Chapter 15 Solutions
Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)
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- Use the binary diagram, 45 line above and material balance to solve the One thousand kg/h of a (50-50 wt%) acetone-in-water solution is to be extracted at 25C in a continuous, countercurrent system with pure 1,1,2-trichloroethane to obtain a raffinate containing 10 wt% acetone. Using the following equilibrium data, determine with an equilateral-triangle diagram: a the minimum flow rate of solvent; b. the number of stages required for a solvent rate equal to 1.5 times minimum, and composition of each streamleaving each stage. Repeat the calculation of (a) and (b) if the solvent used has purity 93wt% (4wr% acetone, 3wt% water impurities) acetone 0.6 water 0.13 1,1,2-trichloroethane 0.27 Raffinate. Weight Fraction Acetone Extract. Weight Fraction Acetone 0.5 0.04 0.46 0.44 0.56 0.4 0.03 0.57 0.29 0.40 0.3 0.02 0.681 0.12 0.18 0.2 0.015 0.785 0.0 0.0 0.1 0.01 0.89 0.55 0.35 0.1 0.5 0.43 0.07 0.4 0.57 0.03 0.3 0.68 0.02 0.2 0.79 0.01 0.1 0.895 0.005arrow_forwardMaterial Sciencearrow_forwardMaterial Sciencearrow_forward
- Material Sciencearrow_forwardTernary Phase Diagram+ Material balance One thousand kg/h of a (50-50 wt%) acetone-in-water solution is to be extracted at 25C in a continuous, countercurrent system with pure 1,1,2-trichloroethane to obtain a raffinate containing 10 wt% acetone. Using the following equilibrium data, determine with an equilateral-triangle diagram: a- the minimum flow rate of solvent; b- the number of stages required for a solvent rate equal to 1.5 times minimum, and composition of each streamleaving each stage. c. Repeat the calculation of (a) and (b) if the solvent used has purity 93wt% (4wr% acetone, 3wt% water impurities) acetone water 1,1,2-trichloroethane Raffinate. Weight Extract. Weight 0.6 0.13 0.27 Fraction Acetone Fraction Acetone 0.5 0.04 0.46 0.44 0.56 0.4 0.03 0.57 0.29 0.40 0.3 0.02 0.68 0.12 0.18 0.2 0.015 0.785 0.0 0.0 0.1 0.01 0.89 0.55 0.35 0.1 0.5 0.43 0.07 0.4 0.57 0.03 0.3 0.68 0.02 0.2 0.79 0.01 0.1 0.895 0.005arrow_forwardI need a detailed drawing with explanation so A 4 しか شكا Write a complete C++ program that includes a function to check whether a given sequence of parentheses is balanced using stack or Linked stack 7:30 م PU + 9625 =-2c125 750 x2.01 58³arrow_forward
- Ternary Phase Diagram+ Material balance Feed mixture weighing 200 kg of unknown composition containing water, acetic acid, isopropyl ether is contacted in a single stage with 280kg mixture containing 40wt% acetic acid. 10wt% water and 50wt% isopropyl ether. The resulting raffinate layer weight 320 kg and containing 29.5 wt% acetic acid, 66.5 wt% water and 4wt% isopropyl ether. Determine the composition of the original feed mixture and the extract layer Water layer Isopropyl ether layer acetic acid 0 water 98.8 Isopropyl ether 1.2 acetic acid 0 water Isopropyl ether 0.6 99.4 0.69 98.1 1.2 0.18 0.5 99.3 1.41 97.1 1.5 0.37 0.7 98.9 2.89 95.5 1.6 0.79 0.8 98.4 6.42 91.7 1.9 1.93 1 97.1 13.3 84.4 2.3 4.82 1.9 93.3 25.5 71.1 3.4 11.4 3.9 84.7 36.7 58.9 4.4 21.6 6.9 71.5 44.3 5.1 10.6 31.1 10.8 58.5 46.4 37.1 16.5 36.2 15.1 48.7arrow_forwardGraphically+Material balance 2500 kg/hr of (20-80) nicotine water solution is to be extracted with benzene containing 0.5% nicotine in the 1st and 2nd stages while the 3rd stage is free of nicotine. Cross-current operation is used with different amounts of solvent for each stages 2000kg/hr in the 1st stage, 2300 kg/hr in the 2nd stage, 2600 kg/hr in the 3rd, determine:- a- The final raffinate concentration and % extraction. b- b-The minimum amount of solvent required for counter-current operation if the minimum concentration will be reduced to 5% in the outlet raffinate. Equilibrium data Wt % Nicotine in water 0 4 16 25 Wt % Nicotine in benzene 0 4 21 30arrow_forwardgraphically +material balance 1000 Kg/hr on an acetone water mixture containing 10% of acetone is to be extracted with trichloroethane. The recovered solvent to be used is free of acetone. If 95% recovery of acetone is desired, the equilibrium relationship is given by kg acetone/kg trichloroethane 1.65 kg acetone/kg water. Estimate the number of stages required if 1.5 times the minimum solvent is used when: - a- b- Cross-current is to be extracted. b- Counter-current is to be extracted.arrow_forward
- use Graphically 1000 Kg/hr on an acetone water mixture containing 10% of acetone is to be extracted with trichloroethane. The recovered solvent to be used is free of acetone. If 95% recovery of acetone is desired, the equilibrium relationship is given by kg acetone/kg trichloroethane 1.65 kg acetone/kg water. Estimate the number of stages required if 1.5 times the minimum solvent is used when: - Cross-current is to be extracted. a- b- b- Counter-current is to be extracted.arrow_forwardA solution of 5% acetaldehyde in toluene is to be extracted with water in five stage co-current operation. If 25kg/100kg feed is used, what is the mass of acetaldehyde extracted and the final concentration? The Equilibrium relation is given by: kg acetaldehyde /kg water = 2.2 kg acetaldehyde / kg toluene.arrow_forwardFeed mixture weighing 200 kg of unknown composition containing water, acetic acid, isopropyl ether is contacted in a single stage with 280kg mixture containing 40wt% acetic acid. 10wt% water and 50wt% isopropyl ether. The resulting raffinate layer weight 320 kg and containing 29.5wt% acetic acid, 66.5 wt% water and 4wt% isopropyl ether. Determine the composition of the original feed mixture and the extract layer Water layer Isopropyl ether layer acetic acid water Isopropyl ether acetic acid water Isopropyl ether 0 98.8 1.2 0 0.6 99.4 0.69 98.1 1.2 0.18 0.5 99.3 1.41 97.1 1.5 0.37 0.7 98.9 2.89 95.5 1.6 0.79 0.8 98.4 6.42 91.7 1.9 1.93 1 97.1 13.3 84.4 2.3 4.82 1.9 93.3 25.5 71.1 3.4 11.4 3.9 84.7 36.7 58.9 4.4 21.6 6.9 71.5 44.3 5.1 10.6 31.1 10.8 58.5 46.4 37.1 16.5 36.2 15.1 48.7arrow_forward
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