The following question can be explained by the classification of carbohydrates. Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes , alcohols, ketones , acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond. Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Question

Want to see more full solutions like this?

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 15, Problem 15.45UTC

Interpretation Introduction

Interpretation: The following question can be explained by the classification of carbohydrates.

Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes, alcohols, ketones, acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond.

Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Expert Solution & Answer

Answer to Problem 15.45UTC

Solution: (a) It is a disaccharide.

(b) The monosaccharides of Isomaltase are 2 molecules of α-glucose.

(c) The glycosidic link in Isomaltase is α-1,6-glycosidic bond.

(d) The given isomer is α-isomer.

Explanation of Solution

(a) In the given structure, there are 2 units of monosaccahrides. Thus, it is a disaccharide.

(b) If the molecule of Isomaltase is broken, then there is formation of 2 monosaccharide units of α-glucose molecules.

General, Organic, and Biological Chemistry: Structures of Life (5th Edition), Chapter 15, Problem 15.45UTC , additional homework tip 2

$I s o m a l t a s e \overset{}{\to} 2 α - g l u c o s e$

(c) The glycosidic bond in Isomaltase is formed between the C1 carbon of the 1st glucose molecule and the C6 carbon of the 2nd glucose. Thus the glycosidic link in Isomaltase is α-1, 6-glycosidic bond.

(d) When the hydroxyl group on C1 carbon atom is facing in downwards direction, then the isomer is called the α-isomer and when the hydroxyl group on C1 carbon atom is facing in upwards direction, then the isomer is called the β-isomer.

Here, the hydroxyl group on C1 carbon atom is facing in downwards direction, thus the given isomer is α-isomer.

Conclusion

Carbohydrates play important roles in the immune system, fertilization, blood clotting, overall development and preventing pathogenesis.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

Show work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?

13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 15, Problem 15.45UTC

Interpretation Introduction

Interpretation: The following question can be explained by the classification of carbohydrates.

Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes, alcohols, ketones, acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond.

Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Expert Solution & Answer

Answer to Problem 15.45UTC

Solution: (a) It is a disaccharide.

(b) The monosaccharides of Isomaltase are 2 molecules of α-glucose.

(c) The glycosidic link in Isomaltase is α-1,6-glycosidic bond.

(d) The given isomer is α-isomer.

Explanation of Solution

(a) In the given structure, there are 2 units of monosaccahrides. Thus, it is a disaccharide.

(b) If the molecule of Isomaltase is broken, then there is formation of 2 monosaccharide units of α-glucose molecules.

General, Organic, and Biological Chemistry: Structures of Life (5th Edition), Chapter 15, Problem 15.45UTC , additional homework tip 2

$I s o m a l t a s e \overset{}{\to} 2 α - g l u c o s e$

(c) The glycosidic bond in Isomaltase is formed between the C1 carbon of the 1st glucose molecule and the C6 carbon of the 2nd glucose. Thus the glycosidic link in Isomaltase is α-1, 6-glycosidic bond.

(d) When the hydroxyl group on C1 carbon atom is facing in downwards direction, then the isomer is called the α-isomer and when the hydroxyl group on C1 carbon atom is facing in upwards direction, then the isomer is called the β-isomer.

Here, the hydroxyl group on C1 carbon atom is facing in downwards direction, thus the given isomer is α-isomer.

Conclusion

Carbohydrates play important roles in the immune system, fertilization, blood clotting, overall development and preventing pathogenesis.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 15, Problem 15.45UTC

Interpretation Introduction

Interpretation: The following question can be explained by the classification of carbohydrates.

Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes, alcohols, ketones, acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond.

Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Expert Solution & Answer

Answer to Problem 15.45UTC

Solution: (a) It is a disaccharide.

(b) The monosaccharides of Isomaltase are 2 molecules of α-glucose.

(c) The glycosidic link in Isomaltase is α-1,6-glycosidic bond.

(d) The given isomer is α-isomer.

Explanation of Solution

(a) In the given structure, there are 2 units of monosaccahrides. Thus, it is a disaccharide.

(b) If the molecule of Isomaltase is broken, then there is formation of 2 monosaccharide units of α-glucose molecules.

General, Organic, and Biological Chemistry: Structures of Life (5th Edition), Chapter 15, Problem 15.45UTC , additional homework tip 2

$I s o m a l t a s e \overset{}{\to} 2 α - g l u c o s e$

(c) The glycosidic bond in Isomaltase is formed between the C1 carbon of the 1st glucose molecule and the C6 carbon of the 2nd glucose. Thus the glycosidic link in Isomaltase is α-1, 6-glycosidic bond.

(d) When the hydroxyl group on C1 carbon atom is facing in downwards direction, then the isomer is called the α-isomer and when the hydroxyl group on C1 carbon atom is facing in upwards direction, then the isomer is called the β-isomer.

Here, the hydroxyl group on C1 carbon atom is facing in downwards direction, thus the given isomer is α-isomer.

Conclusion

Carbohydrates play important roles in the immune system, fertilization, blood clotting, overall development and preventing pathogenesis.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 15, Problem 15.45UTC

Interpretation Introduction

Interpretation: The following question can be explained by the classification of carbohydrates.

Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes, alcohols, ketones, acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond.

Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Expert Solution & Answer

Answer to Problem 15.45UTC

Solution: (a) It is a disaccharide.

(b) The monosaccharides of Isomaltase are 2 molecules of α-glucose.

(c) The glycosidic link in Isomaltase is α-1,6-glycosidic bond.

(d) The given isomer is α-isomer.

Explanation of Solution

(a) In the given structure, there are 2 units of monosaccahrides. Thus, it is a disaccharide.

(b) If the molecule of Isomaltase is broken, then there is formation of 2 monosaccharide units of α-glucose molecules.

General, Organic, and Biological Chemistry: Structures of Life (5th Edition), Chapter 15, Problem 15.45UTC , additional homework tip 2

$I s o m a l t a s e \overset{}{\to} 2 α - g l u c o s e$

(c) The glycosidic bond in Isomaltase is formed between the C1 carbon of the 1st glucose molecule and the C6 carbon of the 2nd glucose. Thus the glycosidic link in Isomaltase is α-1, 6-glycosidic bond.

(d) When the hydroxyl group on C1 carbon atom is facing in downwards direction, then the isomer is called the α-isomer and when the hydroxyl group on C1 carbon atom is facing in upwards direction, then the isomer is called the β-isomer.

Here, the hydroxyl group on C1 carbon atom is facing in downwards direction, thus the given isomer is α-isomer.

Conclusion

Carbohydrates play important roles in the immune system, fertilization, blood clotting, overall development and preventing pathogenesis.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 15, Problem 15.45UTC

Interpretation Introduction

Interpretation: The following question can be explained by the classification of carbohydrates.

Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes, alcohols, ketones, acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond.

Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Expert Solution & Answer

Answer to Problem 15.45UTC

Solution: (a) It is a disaccharide.

(b) The monosaccharides of Isomaltase are 2 molecules of α-glucose.

(c) The glycosidic link in Isomaltase is α-1,6-glycosidic bond.

(d) The given isomer is α-isomer.

Explanation of Solution

(a) In the given structure, there are 2 units of monosaccahrides. Thus, it is a disaccharide.

(b) If the molecule of Isomaltase is broken, then there is formation of 2 monosaccharide units of α-glucose molecules.

General, Organic, and Biological Chemistry: Structures of Life (5th Edition), Chapter 15, Problem 15.45UTC , additional homework tip 2

$I s o m a l t a s e \overset{}{\to} 2 α - g l u c o s e$

(c) The glycosidic bond in Isomaltase is formed between the C1 carbon of the 1st glucose molecule and the C6 carbon of the 2nd glucose. Thus the glycosidic link in Isomaltase is α-1, 6-glycosidic bond.

(d) When the hydroxyl group on C1 carbon atom is facing in downwards direction, then the isomer is called the α-isomer and when the hydroxyl group on C1 carbon atom is facing in upwards direction, then the isomer is called the β-isomer.

Here, the hydroxyl group on C1 carbon atom is facing in downwards direction, thus the given isomer is α-isomer.

Conclusion

Carbohydrates play important roles in the immune system, fertilization, blood clotting, overall development and preventing pathogenesis.

Answer 6

Chapter 15, Problem 15.45UTC

Interpretation Introduction

Interpretation: The following question can be explained by the classification of carbohydrates.

Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes, alcohols, ketones, acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond.

Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Expert Solution & Answer

Answer to Problem 15.45UTC

Solution: (a) It is a disaccharide.

(b) The monosaccharides of Isomaltase are 2 molecules of α-glucose.

(c) The glycosidic link in Isomaltase is α-1,6-glycosidic bond.

(d) The given isomer is α-isomer.

Explanation of Solution

(a) In the given structure, there are 2 units of monosaccahrides. Thus, it is a disaccharide.

(b) If the molecule of Isomaltase is broken, then there is formation of 2 monosaccharide units of α-glucose molecules.

General, Organic, and Biological Chemistry: Structures of Life (5th Edition), Chapter 15, Problem 15.45UTC , additional homework tip 2

$I s o m a l t a s e \overset{}{\to} 2 α - g l u c o s e$

(c) The glycosidic bond in Isomaltase is formed between the C1 carbon of the 1st glucose molecule and the C6 carbon of the 2nd glucose. Thus the glycosidic link in Isomaltase is α-1, 6-glycosidic bond.

(d) When the hydroxyl group on C1 carbon atom is facing in downwards direction, then the isomer is called the α-isomer and when the hydroxyl group on C1 carbon atom is facing in upwards direction, then the isomer is called the β-isomer.

Here, the hydroxyl group on C1 carbon atom is facing in downwards direction, thus the given isomer is α-isomer.

Conclusion

Carbohydrates play important roles in the immune system, fertilization, blood clotting, overall development and preventing pathogenesis.

Answer 7

Chapter 15, Problem 15.45UTC

Interpretation Introduction

Interpretation: The following question can be explained by the classification of carbohydrates.

Concept introduction: Carbohydrates are simple derivatives of polyhydroxy aldehydes, alcohols, ketones, acids, and their polymers having acetal type linkage. They may be categorized as monosaccharides, disaccharides and polysaccharides. Monosaccharides contain an aldehyde or a ketone group and it only contains 1 unit. Disaccharides contain an aldehyde or a ketone group and it only contains2 units of monosaccharides linked together with a glycosidic bond. Polysaccharides contain more than 1 unit of monosaccharide linked together with a glycosidic bond.

Given: Here we are given the Haworth structure of Isomaltose which we get from thebreakdown of starch and we are asked to find out the whether it is mono-, di-, or polysaccharide. We are also asked to find the monosaccharides and glycosidic link in isomaltose. Also, we need to find α or β-anomer of isomaltose, and whether it is a reducing sugar.

Answer 8

Expert Solution & Answer

Answer to Problem 15.45UTC

Solution: (a) It is a disaccharide.

(b) The monosaccharides of Isomaltase are 2 molecules of α-glucose.

(c) The glycosidic link in Isomaltase is α-1,6-glycosidic bond.

(d) The given isomer is α-isomer.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

(a) In the given structure, there are 2 units of monosaccahrides. Thus, it is a disaccharide.

(b) If the molecule of Isomaltase is broken, then there is formation of 2 monosaccharide units of α-glucose molecules.

General, Organic, and Biological Chemistry: Structures of Life (5th Edition), Chapter 15, Problem 15.45UTC , additional homework tip 2

$I s o m a l t a s e \overset{}{\to} 2 α - g l u c o s e$

(c) The glycosidic bond in Isomaltase is formed between the C1 carbon of the 1st glucose molecule and the C6 carbon of the 2nd glucose. Thus the glycosidic link in Isomaltase is α-1, 6-glycosidic bond.

(d) When the hydroxyl group on C1 carbon atom is facing in downwards direction, then the isomer is called the α-isomer and when the hydroxyl group on C1 carbon atom is facing in upwards direction, then the isomer is called the β-isomer.

Here, the hydroxyl group on C1 carbon atom is facing in downwards direction, thus the given isomer is α-isomer.