EBK FUNDAMENTALS OF GEOTECHNICAL ENGINE
EBK FUNDAMENTALS OF GEOTECHNICAL ENGINE
5th Edition
ISBN: 8220101425829
Author: SIVAKUGAN
Publisher: CENGAGE L
Question
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Chapter 15, Problem 15.1P

(a)

To determine

Whether the statement “A key is provided at the base of a cantilever retaining wall to improve the stability with respect to overturning” is true or false.

(a)

Expert Solution
Check Mark

Answer to Problem 15.1P

The given statement is False_.

Explanation of Solution

Actually a key is provided to increase the passive resistance at the toe which will increase the factor of safety against sliding. Hence, the base key will improve the stability of wall with respect to sliding.

Therefore, the given statement is False_.

(b)

To determine

Whether the statement “The earth pressure distribution beneath the base of the retaining wall is uniform” is true or false.

(b)

Expert Solution
Check Mark

Answer to Problem 15.1P

The given statement is False_.

Explanation of Solution

The distribution of earth pressure below the base slab is not uniform because,

  • Different earth pressure exerts on the base slab.
  • The base slab is not a homogeneous one (concrete has homogeneous property).
  • The friction between soil and base slab can distribute the earth pressure that is non-uniform in nature.

Therefore, the given statement is False_.

(c)

To determine

Whether the statement “The lateral earth pressures in active state are greater in loose sands than in dense sands” is true or false.

(c)

Expert Solution
Check Mark

Answer to Problem 15.1P

The given statement is True_.

Explanation of Solution

  • Active lateral earth pressure is the tilting of wall away from the position.
  • The chance of tilting is more in loose sands compared to dense sands. Hence, the lateral earth pressures in active state are greater in loose sands than in dense sands.

Therefore, the given statement is True_.

(d)

To determine

Whether the statement “A base heave problem is more serious in soft clays than in stiff clays” is true or false.

(d)

Expert Solution
Check Mark

Answer to Problem 15.1P

The given statement is True_.

Explanation of Solution

  • Braced cuts in clay may become unstable due to the formation of heaving at the bottom of the excavation.
  • Heave is the upward movement of the ground due to the expansion of clay, which swells when wet.
  • More expansion will lead to heave. The expansion of soft clay is more compared to stiff clay. Hence, the base heave problem is more serious in soft clays than in stiff clays.

Therefore, the given statement is True_.

(e)

To determine

Whether the statement “Cantilever sheet piles have to be driven deeper in loose sands than in dense sands” is true or false.

(e)

Expert Solution
Check Mark

Answer to Problem 15.1P

The given statement is True_.

Explanation of Solution

  • The reason to drive sheet piles at a certain depth below the bottom excavation is to reduce the lateral yielding of wall during the last stages of excavation.
  • The lateral yielding in the loose sands is greater than the dense sands. Hence, the cantilever sheet piles have to be driven deeper in loose sands than in dense sands. The deeper piles will reduce the lateral yielding.

Therefore, the given statement is True_.

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1. What is the weight of each block shown below in pounds? A) 2’x2’x10’ Steel Bar w=490lb/ft^3 B) 5’x4’x3’ Concrete Block w=150lb/ft^3 A) 3’x10’x2’ Wood block w=50lb/ft^3 2.The 6” thick, 20’x25’ concrete slab weights 150lbs/ft^3 and has an area load of 50lbs/ft^2 (psf). What is the total load of the floor?
Lab Assignment #2 Loads: UDL and Concentrated Name: TA 1. Use the provided beam models to solve for the equivalent concentrated load of each beam configuration. Draw the loading conditions showing the equivalent concentrated load(s). a) w = 30lbs/ft 6ft 6ft c) w = 50lbs/ft 12ft w = 70lbs/ft b) 4ft w = 20lbs/ft w = 40lbs/ft d) 9ft 2. Find the equivalent concentrated load(s) for the bags of cement stacked on the dock as shown here. Each bag weighs 100 lbs and is 12 inches long. Draw the loading conditions for each showing the equivalent concentrated load(s). 1 bag = 100lbs L= 12 ft L= 6ft L= 8ft
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