A 1.50-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W . Ignore the very small variation in tension along the length of the string that is produced by the weight of the string. When you pluck the string slightly, the waves traveling up the string obey the equation y ( x , t ) = ( 8.50 mm ) cos ( 172 rad/m x − 4830 rad/s t ) Assume that the tension of the string is constant and equal to W . (a) How much time does it take a pulse to travel the full length of the string? (b) What is the weight W ? (c) How many wavelengths are on the string at any instant of time? (d) What is the equation for waves traveling down the string?
A 1.50-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W . Ignore the very small variation in tension along the length of the string that is produced by the weight of the string. When you pluck the string slightly, the waves traveling up the string obey the equation y ( x , t ) = ( 8.50 mm ) cos ( 172 rad/m x − 4830 rad/s t ) Assume that the tension of the string is constant and equal to W . (a) How much time does it take a pulse to travel the full length of the string? (b) What is the weight W ? (c) How many wavelengths are on the string at any instant of time? (d) What is the equation for waves traveling down the string?
A 1.50-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Ignore the very small variation in tension along the length of the string that is produced by the weight of the string. When you pluck the string slightly, the waves traveling up the string obey the equation
y
(
x
,
t
)
=
(
8.50
mm
)
cos
(
172
rad/m
x
−
4830
rad/s
t
)
Assume that the tension of the string is constant and equal to W. (a) How much time does it take a pulse to travel the full length of the string? (b) What is the weight W? (c) How many wavelengths are on the string at any instant of time? (d) What is the equation for waves traveling down the string?
Use the following information to answer the next question.
Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of
42°. The ray of light reflects off mirror B and then enters water, as shown below:
Incident
ray at A
Note: This diagram is not to
scale.
a
Air (n = 1.00)
Water (n = 1.34)
1) Determine the angle of refraction of the ray of light in the water.
B
Hi can u please solve
6. Bending a lens in OpticStudio or OSLO. In either package, create a BK7 singlet lens of 10 mm semi-diameter
and with 10 mm thickness. Set the wavelength to the (default) 0.55 microns and a single on-axis field point at
infinite object distance. Set the image distance to 200 mm. Make the first surface the stop insure that the lens
is fully filled (that is, that the entrance beam has a radius of 10 mm). Use the lens-maker's equation to
calculate initial glass curvatures assuming you want a symmetric, bi-convex lens with an effective focal length
of 200 mm. Get this working and examine the RMS spot size using the "Text" tab of the Spot Diagram analysis
tab (OpticStudio) or the Spd command of the text widnow (OSLO). You should find the lens is far from
diffraction limited, with a spot size of more than 100 microns.
Now let's optimize this lens. In OpticStudio, create a default merit function optimizing on spot size.Then insert
one extra line at the top of the merit function. Assign the…
Chapter 15 Solutions
University Physics with Modern Physics (14th Edition)
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Wave Speed on a String - Tension Force, Intensity, Power, Amplitude, Frequency - Inverse Square Law; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=vEzftaDL7fM;License: Standard YouTube License, CC-BY