Explanation Given: V Z = 6.3 V The open loop gain is A O L = 1000 The no-load current is I O = 1 mA The full-load current is I O = 100 mA Calculation: Figure 1 Load regulation = V o ( N L ) − V o ( F L ) V o ( N L ) × 100 % ..... ( 1 ) Here, V o ( N L ) is no-load output voltage, and V o ( F L ) is full-load output voltage. Write the equation of nodal analysis at node V 1 . V 1 10 k Ω = V o − V 1 10 k Ω Here, V 1 Is inverting terminal voltage, and V o Is output voltage. Simplify the expression into shortest possible form. V 1 10 k Ω = V o 10 k Ω − V 1 10 k Ω V 1 10 k Ω + V 1 10 k Ω = V o 10 k Ω V 1 ( 1 10 k Ω + 1 10 k Ω ) = V o 10 k Ω V 1 ( 2 10 k Ω ) = V o 10 k Ω V 1 = ( 10 k Ω 2 × 1 10 k Ω ) V o V 1 = V o 2 Write the equation of nodal analysis at node V o and reduce equation into possible short form. V o − V 1 10 k Ω + V o R L + V o − A O L ( V Z − V 1 ) R o = 0 Here, V Z is Zener diode voltage, A O L is open loop gain, R L is load resistance, and R o is output resistance. Simplify the expression into shortest possible form. V o 10 k Ω − V 1 10 k Ω + V o R L + V o R o − A O L V Z R o + A O L V 1 R o = 0 V o ( 1 10 k Ω + 1 R o ) + V o R L + V 1 ( A O L R o − 1 10 k Ω ) − A O L V Z R o = 0 Write the expression for output voltage ( I o ) . ( I o ) = V O R L Substitute I o for V O R L and V O 2 for V 1 in equation (1) and re-arrange equation to find the output voltage. V o ( 1 10 k Ω + 1 R o ) + I o + V o 2 ( A O L R o − 1 10 k Ω ) − A O L V Z R o = 0 V o ( 1 10 k Ω + 1 R o ) + I o + V o ( A O L 2 R o − 1 20 k Ω ) − A O L V Z R o = 0 V o ( 1 10 k Ω + 1 R o + A O L 2 R o − 1 20 k Ω ) + I o − A O L V Z R o = 0 V o ( 1 10 k Ω + 1 R o + A O L 2 R o − 1 20 k Ω ) = A O L V Z R o − I o V o = ( A O L V Z R o − I o ) ( 1 10 k Ω + 1 R o + A O L 2 R o − 1 20 k Ω )

MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)

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ISBN: 9781266368622

Author: NEAMEN

Publisher: MCG

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