MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
4th Edition
ISBN: 9781266368622
Author: NEAMEN
Publisher: MCG
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Chapter 15, Problem 1RQ
To determine
To explain: Difference between active and passive filter and also advantage of active filter.
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You and your crew have made it through the night and the day has brought more warmth. After searching the industrial site, you find an abundant amount of fuel to run the generators to keep you warm. You also find a memory card labelled “cure”, but your cell phone battery is dead. First things first, you will need to stay safe as the zombies continue to hunt you in your current location. The industrial site is surrounded by a metal chain-link fence. You decide you will electrify the fence to keep the zombies from scaling it. But the output voltage from the generators is not high enough to really deter them. You would like to apply around 10 kV to the fence (AC or DC, at that voltage it doesn’t really matter). You find a transformer that you can use but it only has a turn ratio of 10. You find some diodes and capacitors and construct the circuit shown in Figure 3 with the intention of hooking Vout to the fence.
Perform a simulation, displaying the voltage Vout using a scope.…
Please answer all questions
1. Calculate the magnitude (in RMS) of the current through R1 2. Calculate the magnitude (in RMS) of the current through R2. Simulation 1. Construct the circuit in Figure 2 in the Circuit JS simulator. Note that transformers in Circuit JS may be unstable. It is suggested to draw them by clicking from the bottom left corner to the top right corner and refresh your simulation before taking a measurement. 2. Perform a simulation, displaying the voltage across the voltage source, the current through R1, and the current through R2 in a “stacked” scope. Display the RMS average for each trace. Include a screenshot.
Analysis 1. Compare the simulation results for the currents through R1 and R2. What is the percentage difference between the calculated and simulated value for each? Comment on why there may be a discrepancy.
Chapter 15 Solutions
MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
Ch. 15 - Design a twopole lowpass Butterworth filter with a...Ch. 15 - Consider the switchedcapacitor circuit in Figure...Ch. 15 - Prob. 15.3EPCh. 15 - (a) Design a threepole highpass Butterworth active...Ch. 15 - Prob. 15.2TYUCh. 15 - Prob. 15.3TYUCh. 15 - Simulate a 25M resistance using the circuit in...Ch. 15 - Design the phaseshift oscillator shown in Figure...Ch. 15 - Design the Wienbridge circuit in Figure 15.17 to...Ch. 15 - Prob. 15.5TYU
Ch. 15 - Prob. 15.6TYUCh. 15 - Prob. 15.6EPCh. 15 - Redesign the street light control circuit shown in...Ch. 15 - A noninverting Schmitt trigger is shown m Figure...Ch. 15 - For the Schmitt trigger in Figure 15.30(a), the...Ch. 15 - Prob. 15.9TYUCh. 15 - Prob. 15.8EPCh. 15 - Prob. 15.9EPCh. 15 - Consider the 555 IC monostablemultivibrator. (a)...Ch. 15 - The 555 IC is connected as an...Ch. 15 - Prob. 15.10TYUCh. 15 - Prob. 15.11TYUCh. 15 - Prob. 15.12TYUCh. 15 - Prob. 15.12EPCh. 15 - Prob. 15.13EPCh. 15 - (a) Consider the bridge amplifier in Figure 15.46...Ch. 15 - Prob. 15.14EPCh. 15 - Prob. 15.15EPCh. 15 - Prob. 15.16EPCh. 15 - Prob. 1RQCh. 15 - Prob. 2RQCh. 15 - Consider a lowpass filter. What is the slope of...Ch. 15 - Prob. 4RQCh. 15 - Describe how a capacitor in conjunction with two...Ch. 15 - Sketch a onepole lowpass switchedcapacitor filter...Ch. 15 - Explain the two basic principles that must be...Ch. 15 - Prob. 8RQCh. 15 - Prob. 9RQCh. 15 - Prob. 10RQCh. 15 - Prob. 11RQCh. 15 - What is the primary advantage of a Schmitt trigger...Ch. 15 - Sketch the circuit and explain the operation of a...Ch. 15 - Prob. 14RQCh. 15 - Prob. 15RQCh. 15 - Prob. 16RQCh. 15 - Prob. 17RQCh. 15 - Prob. 18RQCh. 15 - Prob. D15.1PCh. 15 - Prob. 15.2PCh. 15 - The specification in a highpass Butterworth filter...Ch. 15 - (a) Design a twopole highpass Butterworth active...Ch. 15 - (a) Design a threepole lowpass Butterworth active...Ch. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - A lowpass filter is to be designed to pass...Ch. 15 - Prob. 15.10PCh. 15 - Prob. 15.11PCh. 15 - Prob. D15.12PCh. 15 - Prob. D15.13PCh. 15 - Prob. D15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - A simple bandpass filter can be designed by...Ch. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. D15.22PCh. 15 - Prob. 15.23PCh. 15 - Consider the phase shift oscillator in Figure...Ch. 15 - In the phaseshift oscillator in Figure 15.15, the...Ch. 15 - Consider the phase shift oscillator in Figure...Ch. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - A Wienbridge oscillator is shown in Figure P15.32....Ch. 15 - Prob. 15.33PCh. 15 - Prob. D15.34PCh. 15 - Prob. D15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. D15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Prob. 15.41PCh. 15 - For the comparator in the circuit in Figure...Ch. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Consider the Schmitt trigger in Figure P15.46....Ch. 15 - The saturated output voltages are VP for the...Ch. 15 - Consider the Schmitt trigger in Figure 15.30(a)....Ch. 15 - Prob. 15.50PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. D15.58PCh. 15 - Prob. 15.59PCh. 15 - The saturated output voltages of the comparator in...Ch. 15 - (a) The monostablemultivibrator in Figure 15.37 is...Ch. 15 - A monostablemultivibrator is shown in Figure...Ch. 15 - Prob. D15.63PCh. 15 - Design a 555 monostablemultivibrator to provide a...Ch. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - An LM380 must deliver ac power to a 10 load. The...Ch. 15 - Prob. 15.70PCh. 15 - Prob. D15.71PCh. 15 - Prob. 15.72PCh. 15 - (a) Design the circuit shown in Figure P15.72 such...Ch. 15 - Prob. 15.74PCh. 15 - Prob. 15.75PCh. 15 - Prob. 15.76PCh. 15 - Prob. D15.77PCh. 15 - Prob. 15.78P
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- Please answer all You and your crew have made it through the night and the day has brought more warmth. After searching the industrial site, you find an abundant amount of fuel to run the generators to keep you warm. You also find a memory card labelled “cure”, but your cell phone battery is dead. First things first, you will need to stay safe as the zombies continue to hunt you in your current location. The industrial site is surrounded by a metal chain-link fence. You decide you will electrify the fence to keep the zombies from scaling it. But the output voltage from the generators is not high enough to really deter them. You would like to apply around 10 kV to the fence (AC or DC, at that voltage it doesn’t really matter). You find a transformer that you can use but it only has a turn ratio of 10. You find some diodes and capacitors and construct the circuit shown in Figure 3 with the intention of hooking Vout to the fence. 1. Perform a circuit JS simulation, displaying…arrow_forward2. A three-phase transformer connection Yy, 2000 kVA, 20000/6000 V has the relative short-circuit voltages Ecc = 7% and ERcc = 1.7%.It is known that when empty this transformer consumes a power Po = 12.24 kW. Calculate:a. Parameters Zcc, Rcc, Xcc, referring to the primary and EXcc.b. If the transformer is connected at rated voltage and feeds a load of 1800 kVA, fp = 0.8, calculate the line voltage at the secondary.c. The maximum apparent power, and the maximum efficiency fp = 0.8 inductive. Perform the exercise by the collaborators and without using artificial intelligence pleasearrow_forward1. A three-phase transformer with Yd connection, 300 kVA, 12000/220 V, has been short-circuit tested on the high voltage side giving the following results: 750 V, 14.434 A, 10838 W.When the transformer is connected to nominal voltage without load it consumes 5400W. Calculate:to. Relative voltages of short circuit high voltage side: εcc, εRcc and εXcc.b. The voltage in the secondary when the transformer is connected to nominal voltage and feeds a load of 200 kW fp = 0.8 in delay.c. Apparent power of maximum efficiency and maximum efficiency with fp = 0.95 inductive. Please solve for one of the collaborators and without using artificial intelligencearrow_forward
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