Interpretation:
Calculate the equilibrium constant and percentage given the fructose to glucose equilibrium reactions with respective temperature at 250C.
Concept Introduction:
Equilibrium constant: Concentration of the products to the respective molar concentration of reactants it is called equilibrium constant. If the K value is less than one the reaction will move to the left side and the K values is higher (or) greater than one the reaction will move to the right side of reaction.
Equilibrium concentration: If Kc and the initial concentration for a reaction and calculate for both equilibrium concentration, and using the (ICE) chart and equilibrium constant and derived changes in respective reactants and products.
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Chemistry: Atoms First
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- Indicate which one of the following reactions most certainly results in a negative AS sys. O1402(g) + 3NH4NO3 (s) + C10 H22(1) → 3N2(g) + 17H2O(g) + 10CO2(g) ○ CO2(aq) = CO2(g) ○ H₂O(g) = H₂O(s) CaCO3(g) = CaO(s) + CO2(g) O CuSO4.5H2O(s) = CuSO4(s) + 5H2O(g)arrow_forwardEstimate the DH°rxn of the reaction below: H H-C-C=C-H H Н A table of bond energy Bond H Bond Energy (kJ/mol) C-H 413 C-O 360 C=O 743 C-C 348 |C = C 612 O-H 463 H-H 436 + H-H -> H H-C. - H | | 1 HHHarrow_forwardShow work...don't give Ai generated solutionarrow_forward
- Given the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 3A(g) + 1B (g) 4C (g) + 7D (g) Substance AH in kJ/mol A (g) - 25.07 B (g) - 36.51 C (g) - 90.09 D (g) + 56.11 AHran =?kJarrow_forwardWhat is the change in internal energy (ΔU) when a system is heated with 42.0 J of energy while it does 110.0 J of work?arrow_forwardCan you help me solve this problem and explain what the answers are?arrow_forward
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