Which of the following solutions contains the greatest number of particles? Support your answer. .0 mL of 0 10 M sodium chloride .0 mL of 0.10 M calcium chloride .0 mL of 0.10 M iron(III) chloride .0 mL of 0.10 M potassium bromide .0 mL of 0.10 M sucrose (table sugar)

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 15, Problem 11ALQ

Which of the following solutions contains the greatest number of particles? Support your answer.

.0 mL of 0 10 M sodium chloride

.0 mL of 0.10 M calcium chloride

.0 mL of 0.10 M iron(III) chloride

.0 mL of 0.10 M potassium bromide

.0 mL of 0.10 M sucrose (table sugar)

Expert Solution & Answer

Interpretation Introduction

Interpretation:

The solution containing the greatest number of particles is to be predicted.

Concept Introduction:

There are many ways to determine the concentration of the solution. One of the most used methods is molarity. Molarity may be defined as the number of moles of the solute in one liter of the whole solution. Thus, the molarity can be calculated as,

$M=moles of solute (mole)total volume of solution (L)$ .

Answer to Problem 11ALQ

The correct option is (b).

Explanation of Solution

Reason for correct option:

(b) The molarity of the $300 mL$ solution of calcium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×300 1000L=0.03 mol$

The total number of moles in the given solution is $0.03 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.03 ×6.022×1023=1.8×1022$

One mole of $CaCl2$ contains $1$ mole of $Ca2+$ and $2$ moles of $Cl−$ . Thus, the total number of particles present in the solution is $3×1.8×1022$ , that is, $5.4×1022$ particles.

Conclusion

Reasons for incorrect options:

(a) The molarity of the $400 mL$ solution of sodium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×400 1000L=0.04 mol$

The total number of moles in the given solution is $0.04 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.04 ×6.022×1023=2.4×1022$

One mole of $NaCl$ contains $1$ mole of $Na+$ and $1$ mol of $Cl−$ . Thus, the total number of particles present in the solution is $2×2.4×1022$ , that is, $4.8×1022$ particles.

(c) The molarity of the $200 mL$ solution of iron $(III)$ chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $FeCl3$ contains $1$ mole of $Fe3+$ and $3$ mole of $Cl−$ . Thus, the total number of particles present in the solution is $4×1.2×1022$ , that is, $4.8×1022$ particles.

(d) The molarity of the $200 mL$ solution of potassium bromide is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $KBr$ contains $1$ mole of $K+$ and $1$ mol of $Br−$ . Thus, the total number of particles present in the solution is $2×1.2×1022$ , that is, $2.4×1022$ particles.

(e) The molarity of the $800 mL$ solution of sucrose is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×800 1000L=0.08 mol$

The total number of moles in the given solution is $0.08 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.08 ×6.022×1023=4.8×1022$

The total number of particles present in the solution is $4.8×1022$ particles.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

What are the most proper reagents to achieve these products? سد 1. 2. OH ○ 1. BrMgC6H6; 2. H+ ○ 1. BrMgCH2CH2CH2CH2CH3; 2. H+ O 1. CH3CH2CHO; 2. H+ O 1. BrMgCH2CH3; 2. H+

Provide the IUPAC (systematic) name only for the following compound. Dashes, commas, and spaces must be correct. H

Please use the nernst equation to genereate the Ion Selective Electrode Analysis standard curve within my excel spread sheet. Nernst Equation: E = Eo + m (ln a) Link: https://mnscu-my.sharepoint.com/:x:/g/personal/vi2163ss_go_minnstate_edu/EaREe1-PfGNKq1Cbink6kkYB5lBy05hEaE3mbGPUb22S6w?rtime=zQaSX3xY3Ug

Answer 2

Textbook Question

Chapter 15, Problem 11ALQ

Which of the following solutions contains the greatest number of particles? Support your answer.

.0 mL of 0 10 M sodium chloride

.0 mL of 0.10 M calcium chloride

.0 mL of 0.10 M iron(III) chloride

.0 mL of 0.10 M potassium bromide

.0 mL of 0.10 M sucrose (table sugar)

Expert Solution & Answer

Interpretation Introduction

Interpretation:

The solution containing the greatest number of particles is to be predicted.

Concept Introduction:

There are many ways to determine the concentration of the solution. One of the most used methods is molarity. Molarity may be defined as the number of moles of the solute in one liter of the whole solution. Thus, the molarity can be calculated as,

$M=moles of solute (mole)total volume of solution (L)$ .

Answer to Problem 11ALQ

The correct option is (b).

Explanation of Solution

Reason for correct option:

(b) The molarity of the $300 mL$ solution of calcium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×300 1000L=0.03 mol$

The total number of moles in the given solution is $0.03 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.03 ×6.022×1023=1.8×1022$

One mole of $CaCl2$ contains $1$ mole of $Ca2+$ and $2$ moles of $Cl−$ . Thus, the total number of particles present in the solution is $3×1.8×1022$ , that is, $5.4×1022$ particles.

Conclusion

Reasons for incorrect options:

(a) The molarity of the $400 mL$ solution of sodium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×400 1000L=0.04 mol$

The total number of moles in the given solution is $0.04 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.04 ×6.022×1023=2.4×1022$

One mole of $NaCl$ contains $1$ mole of $Na+$ and $1$ mol of $Cl−$ . Thus, the total number of particles present in the solution is $2×2.4×1022$ , that is, $4.8×1022$ particles.

(c) The molarity of the $200 mL$ solution of iron $(III)$ chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $FeCl3$ contains $1$ mole of $Fe3+$ and $3$ mole of $Cl−$ . Thus, the total number of particles present in the solution is $4×1.2×1022$ , that is, $4.8×1022$ particles.

(d) The molarity of the $200 mL$ solution of potassium bromide is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $KBr$ contains $1$ mole of $K+$ and $1$ mol of $Br−$ . Thus, the total number of particles present in the solution is $2×1.2×1022$ , that is, $2.4×1022$ particles.

(e) The molarity of the $800 mL$ solution of sucrose is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×800 1000L=0.08 mol$

The total number of moles in the given solution is $0.08 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.08 ×6.022×1023=4.8×1022$

The total number of particles present in the solution is $4.8×1022$ particles.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 15, Problem 11ALQ

Which of the following solutions contains the greatest number of particles? Support your answer.

.0 mL of 0 10 M sodium chloride

.0 mL of 0.10 M calcium chloride

.0 mL of 0.10 M iron(III) chloride

.0 mL of 0.10 M potassium bromide

.0 mL of 0.10 M sucrose (table sugar)

Expert Solution & Answer

Interpretation Introduction

Interpretation:

The solution containing the greatest number of particles is to be predicted.

Concept Introduction:

There are many ways to determine the concentration of the solution. One of the most used methods is molarity. Molarity may be defined as the number of moles of the solute in one liter of the whole solution. Thus, the molarity can be calculated as,

$M=moles of solute (mole)total volume of solution (L)$ .

Answer to Problem 11ALQ

The correct option is (b).

Explanation of Solution

Reason for correct option:

(b) The molarity of the $300 mL$ solution of calcium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×300 1000L=0.03 mol$

The total number of moles in the given solution is $0.03 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.03 ×6.022×1023=1.8×1022$

One mole of $CaCl2$ contains $1$ mole of $Ca2+$ and $2$ moles of $Cl−$ . Thus, the total number of particles present in the solution is $3×1.8×1022$ , that is, $5.4×1022$ particles.

Conclusion

Reasons for incorrect options:

(a) The molarity of the $400 mL$ solution of sodium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×400 1000L=0.04 mol$

The total number of moles in the given solution is $0.04 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.04 ×6.022×1023=2.4×1022$

One mole of $NaCl$ contains $1$ mole of $Na+$ and $1$ mol of $Cl−$ . Thus, the total number of particles present in the solution is $2×2.4×1022$ , that is, $4.8×1022$ particles.

(c) The molarity of the $200 mL$ solution of iron $(III)$ chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $FeCl3$ contains $1$ mole of $Fe3+$ and $3$ mole of $Cl−$ . Thus, the total number of particles present in the solution is $4×1.2×1022$ , that is, $4.8×1022$ particles.

(d) The molarity of the $200 mL$ solution of potassium bromide is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $KBr$ contains $1$ mole of $K+$ and $1$ mol of $Br−$ . Thus, the total number of particles present in the solution is $2×1.2×1022$ , that is, $2.4×1022$ particles.

(e) The molarity of the $800 mL$ solution of sucrose is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×800 1000L=0.08 mol$

The total number of moles in the given solution is $0.08 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.08 ×6.022×1023=4.8×1022$

The total number of particles present in the solution is $4.8×1022$ particles.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 15, Problem 11ALQ

Which of the following solutions contains the greatest number of particles? Support your answer.

.0 mL of 0 10 M sodium chloride

.0 mL of 0.10 M calcium chloride

.0 mL of 0.10 M iron(III) chloride

.0 mL of 0.10 M potassium bromide

.0 mL of 0.10 M sucrose (table sugar)

Expert Solution & Answer

Interpretation Introduction

Interpretation:

The solution containing the greatest number of particles is to be predicted.

Concept Introduction:

There are many ways to determine the concentration of the solution. One of the most used methods is molarity. Molarity may be defined as the number of moles of the solute in one liter of the whole solution. Thus, the molarity can be calculated as,

$M=moles of solute (mole)total volume of solution (L)$ .

Answer to Problem 11ALQ

The correct option is (b).

Explanation of Solution

Reason for correct option:

(b) The molarity of the $300 mL$ solution of calcium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×300 1000L=0.03 mol$

The total number of moles in the given solution is $0.03 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.03 ×6.022×1023=1.8×1022$

One mole of $CaCl2$ contains $1$ mole of $Ca2+$ and $2$ moles of $Cl−$ . Thus, the total number of particles present in the solution is $3×1.8×1022$ , that is, $5.4×1022$ particles.

Conclusion

Reasons for incorrect options:

(a) The molarity of the $400 mL$ solution of sodium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×400 1000L=0.04 mol$

The total number of moles in the given solution is $0.04 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.04 ×6.022×1023=2.4×1022$

One mole of $NaCl$ contains $1$ mole of $Na+$ and $1$ mol of $Cl−$ . Thus, the total number of particles present in the solution is $2×2.4×1022$ , that is, $4.8×1022$ particles.

(c) The molarity of the $200 mL$ solution of iron $(III)$ chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $FeCl3$ contains $1$ mole of $Fe3+$ and $3$ mole of $Cl−$ . Thus, the total number of particles present in the solution is $4×1.2×1022$ , that is, $4.8×1022$ particles.

(d) The molarity of the $200 mL$ solution of potassium bromide is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $KBr$ contains $1$ mole of $K+$ and $1$ mol of $Br−$ . Thus, the total number of particles present in the solution is $2×1.2×1022$ , that is, $2.4×1022$ particles.

(e) The molarity of the $800 mL$ solution of sucrose is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×800 1000L=0.08 mol$

The total number of moles in the given solution is $0.08 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.08 ×6.022×1023=4.8×1022$

The total number of particles present in the solution is $4.8×1022$ particles.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Interpretation Introduction

Interpretation:

The solution containing the greatest number of particles is to be predicted.

Concept Introduction:

There are many ways to determine the concentration of the solution. One of the most used methods is molarity. Molarity may be defined as the number of moles of the solute in one liter of the whole solution. Thus, the molarity can be calculated as,

$M=moles of solute (mole)total volume of solution (L)$ .

Answer to Problem 11ALQ

The correct option is (b).

Explanation of Solution

Reason for correct option:

(b) The molarity of the $300 mL$ solution of calcium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×300 1000L=0.03 mol$

The total number of moles in the given solution is $0.03 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.03 ×6.022×1023=1.8×1022$

One mole of $CaCl2$ contains $1$ mole of $Ca2+$ and $2$ moles of $Cl−$ . Thus, the total number of particles present in the solution is $3×1.8×1022$ , that is, $5.4×1022$ particles.

Conclusion

Reasons for incorrect options:

(a) The molarity of the $400 mL$ solution of sodium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×400 1000L=0.04 mol$

The total number of moles in the given solution is $0.04 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.04 ×6.022×1023=2.4×1022$

One mole of $NaCl$ contains $1$ mole of $Na+$ and $1$ mol of $Cl−$ . Thus, the total number of particles present in the solution is $2×2.4×1022$ , that is, $4.8×1022$ particles.

(c) The molarity of the $200 mL$ solution of iron $(III)$ chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $FeCl3$ contains $1$ mole of $Fe3+$ and $3$ mole of $Cl−$ . Thus, the total number of particles present in the solution is $4×1.2×1022$ , that is, $4.8×1022$ particles.

(d) The molarity of the $200 mL$ solution of potassium bromide is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $KBr$ contains $1$ mole of $K+$ and $1$ mol of $Br−$ . Thus, the total number of particles present in the solution is $2×1.2×1022$ , that is, $2.4×1022$ particles.

(e) The molarity of the $800 mL$ solution of sucrose is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×800 1000L=0.08 mol$

The total number of moles in the given solution is $0.08 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.08 ×6.022×1023=4.8×1022$

The total number of particles present in the solution is $4.8×1022$ particles.

Answer 8

Expert Solution & Answer

Interpretation Introduction

Interpretation:

The solution containing the greatest number of particles is to be predicted.

Concept Introduction:

There are many ways to determine the concentration of the solution. One of the most used methods is molarity. Molarity may be defined as the number of moles of the solute in one liter of the whole solution. Thus, the molarity can be calculated as,

$M=moles of solute (mole)total volume of solution (L)$ .

Answer to Problem 11ALQ

The correct option is (b).

Explanation of Solution

Reason for correct option:

(b) The molarity of the $300 mL$ solution of calcium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×300 1000L=0.03 mol$

The total number of moles in the given solution is $0.03 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.03 ×6.022×1023=1.8×1022$

One mole of $CaCl2$ contains $1$ mole of $Ca2+$ and $2$ moles of $Cl−$ . Thus, the total number of particles present in the solution is $3×1.8×1022$ , that is, $5.4×1022$ particles.

Conclusion

Reasons for incorrect options:

(a) The molarity of the $400 mL$ solution of sodium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×400 1000L=0.04 mol$

The total number of moles in the given solution is $0.04 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.04 ×6.022×1023=2.4×1022$

One mole of $NaCl$ contains $1$ mole of $Na+$ and $1$ mol of $Cl−$ . Thus, the total number of particles present in the solution is $2×2.4×1022$ , that is, $4.8×1022$ particles.

(c) The molarity of the $200 mL$ solution of iron $(III)$ chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $FeCl3$ contains $1$ mole of $Fe3+$ and $3$ mole of $Cl−$ . Thus, the total number of particles present in the solution is $4×1.2×1022$ , that is, $4.8×1022$ particles.

(d) The molarity of the $200 mL$ solution of potassium bromide is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $KBr$ contains $1$ mole of $K+$ and $1$ mol of $Br−$ . Thus, the total number of particles present in the solution is $2×1.2×1022$ , that is, $2.4×1022$ particles.

(e) The molarity of the $800 mL$ solution of sucrose is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×800 1000L=0.08 mol$

The total number of moles in the given solution is $0.08 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.08 ×6.022×1023=4.8×1022$

The total number of particles present in the solution is $4.8×1022$ particles.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Interpretation Introduction

Interpretation:

The solution containing the greatest number of particles is to be predicted.

Concept Introduction:

There are many ways to determine the concentration of the solution. One of the most used methods is molarity. Molarity may be defined as the number of moles of the solute in one liter of the whole solution. Thus, the molarity can be calculated as,

$M=moles of solute (mole)total volume of solution (L)$ .

Answer 12

Answer to Problem 11ALQ

The correct option is (b).

Answer 13

Explanation of Solution

Reason for correct option:

(b) The molarity of the $300 mL$ solution of calcium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×300 1000L=0.03 mol$

The total number of moles in the given solution is $0.03 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.03 ×6.022×1023=1.8×1022$

One mole of $CaCl2$ contains $1$ mole of $Ca2+$ and $2$ moles of $Cl−$ . Thus, the total number of particles present in the solution is $3×1.8×1022$ , that is, $5.4×1022$ particles.

Answer 14

Conclusion

Reasons for incorrect options:

(a) The molarity of the $400 mL$ solution of sodium chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×400 1000L=0.04 mol$

The total number of moles in the given solution is $0.04 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.04 ×6.022×1023=2.4×1022$

One mole of $NaCl$ contains $1$ mole of $Na+$ and $1$ mol of $Cl−$ . Thus, the total number of particles present in the solution is $2×2.4×1022$ , that is, $4.8×1022$ particles.

(c) The molarity of the $200 mL$ solution of iron $(III)$ chloride is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $FeCl3$ contains $1$ mole of $Fe3+$ and $3$ mole of $Cl−$ . Thus, the total number of particles present in the solution is $4×1.2×1022$ , that is, $4.8×1022$ particles.

(d) The molarity of the $200 mL$ solution of potassium bromide is $0.10M$ .The number of moles present in the given solution is calculated by the formula,

$M=moles of solute (mole)total volume of solution (L)$

Substitute the values of molarity and volume in the given formula.

$moles of solute (mole)=M×total volume of solution (L)=0.1(mol L-1)×200 1000L=0.02 mol$

The total number of moles in the given solution is $0.02 mol$ .

To calculate the number of particles in a solution the formula used is,

$Moles=Number of particlesAvogadro number(NA)$

Avogadro number is equal to the number of particles present in one mole, that is, $6.022×1023$ particles.

Substitute the values of moles and Avogadro number in the given formula.

$Number of particles=Moles×Avogadro number(NA)=0.02 ×6.022×1023=1.2×1022$

One mole of $KBr$ contains $1$ mole of $K+$ and $1$ mol of $Br−$ . Thus, the total number of particles present in the solution is $2×1.2×1022$ , that is, $2.4×1022$ particles.