Explanation Given Information: The provided figure is shown below; Where, A = 114 ° , A H = 52 mi , A B = 78 mi Formula used: a 2 = b 2 + c 2 − 2 b c cosA Law of sines, a sin A = b sin B Where a , b and c are sides. A , B and C are the values of angle. Calculation: Consider the provided diagram with provided values, A = 114 ° , A H = 52 mi , A B = 78 mi Use law of cosines a 2 = b 2 + c 2 − 2 b c cosA to find the distance between ( H ) and ( B ) . Now substitute the value A = 114 ° , A H = 52 mi , A B = 78 mi in a 2 = b 2 + c 2 − 2 b c cosA , Therefore, H B 2 = ( 52 ) 2 + ( 78 ) 2 − 2 ( 52 ) ( 78 ) cos 114 ° H B = 2704 + 6084 − 8112 ( − 0.406 ) H B = 8788 + 3299.44 = 110 Hence, the distance between ( H ) and ( B ) is 110 mi

11th Edition

ISBN: 9781285199191

Author: Dale Ewen, C. Robert Nelson

Publisher: Cengage Learning

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Chapter 14.5, Problem 28E

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To calculate: The distance between the sailing point (B) and home port (H) and bearing angle at which ship will return to home port for the provided figure is,

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Chapter 14.5, Problem 27E

Chapter 14.5, Problem 29E

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Chapter 14 Solutions

Elementary Technical Mathematics

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The distance between the sailing point ( B ) and home port ( H ) and bearing angle at which ship will return to home port for the provided figure is,

Solution Summary: The author calculates the distance between the sailing point (B) and home port.

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To calculate: The distance between the sailing point (B) and home port (H) and bearing angle at which ship will return to home port for the provided figure is,

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Chapter 14 Solutions