Explanation Given Information: The provided function is y = 2 cos ( x − 60 ° ) . Formula Used: For a given function y = A s c t ( B x + Q ) , where s c t = sin / cos / tan Here, A = Amplitude , Period = 360 B and Phase = Q B Calculation: Consider the provided function: y = 2 cos ( x − 60 ° ) Now, compare the provided function y = 2 cos ( x − 60 ) with the function y = A s c t ( B x + Q ) . So, it can be concluded that, Amplitude = 2 And, period = 360 1 = 360 And, phase = − 60 1 = − 60 Thus, the amplitude is 2 , period is 360 ° and phase is 60 ° right in the given function y = 2 cos ( x − 60 ) . Graph: Consider the provided function: y = 2 cos ( x − 60 ) Now, obtain the values of y by assuming corresponding values of x as: Substitute x = 0 in the function y = 2 cos ( x − 60 ) . y = 2 cos ( 0 − 60 ) = 2 cos ( 60 ) = 2 ⋅ 0.5 = 1 Substitute x = 15 in the function y = 2 cos ( x − 60 ) . y = 2 cos ( 15 − 60 ) = 2 cos ( − 45 ) = 2 ⋅ 0.7071 = 1.4142 Substitute x = 30 in the function y = 2 cos ( x − 60 ) . y = 2 cos ( 30 − 60 ) = 2 cos ( − 30 ) = 2 ⋅ 0

11th Edition

ISBN: 9781285199191

Author: Dale Ewen, C. Robert Nelson

Publisher: Cengage Learning

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Chapter 14.2, Problem 15E

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To calculate: The period and amplitude and phase of the given expression y=2cos(x−60°) and graph the provided function.

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Chapter 14.2, Problem 14E

Chapter 14.2, Problem 16E

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Chapter 14 Solutions

Elementary Technical Mathematics

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The period and amplitude and phase of the given expression y = 2 cos ( x − 60 ° ) and graph the provided function.

Solution Summary: The author calculates the period, amplitude, and phase of the given expression y=2mathrmcos(x-60°).

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To calculate: The period and amplitude and phase of the given expression y=2cos(x−60°) and graph the provided function.

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Chapter 14 Solutions