Explanation Given Information: The provided function is y = 3.5 sin ( 2 3 x ) . Formula Used: For a given function y = A s c t ( B x ) , where s c t = sin / cos / tan Here, A = Amplitude and Period = 360 B Calculation: Consider the provided function: y = 3.5 sin ( 2 3 x ) Now, compare the provided function y = 3.5 sin ( 2 3 x ) with the function y = A s c t ( B x ) . So, it can be concluded that, Amplitude = 3.5 And, period = 360 2 3 = 360 ⋅ 3 2 = 540 Thus, the amplitude is 3.5 and period is 540 ° in the given function y = 3.5 sin ( 2 3 x ) . Graph: Consider the provided function: y = 3.5 sin ( 2 3 x ) Now, obtain the values of y by assuming corresponding values of x as: Substitute x = 0 in the function y = 3.5 sin ( 2 3 x ) . y = 3.5 sin ( 2 3 ⋅ 0 ) = 3.5 sin ( 0 ) = 0 Substitute x = 15 in the function y = 3.5 sin ( 2 3 x ) . y = 3.5 sin ( 2 3 ⋅ 15 ) = 3.5 sin ( 10 ) = 3.5 ⋅ 0.1736 = 0.6077 Substitute x = 30 in the function y = 3.5 sin ( 2 3 x ) . y = 3.5 sin ( 2 3 ⋅ 30 ) = 3.5 sin ( 20 ) = 3.5 ⋅ 0

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ISBN: 9781285199191

Author: Dale Ewen, C. Robert Nelson

Publisher: Cengage Learning

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Chapter 14.2, Problem 9E

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To calculate: The period and amplitude of the given expression y=3.5sin(23x) and graph the provided function.

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Chapter 14.2, Problem 8E

Chapter 14.2, Problem 10E

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Chapter 14 Solutions

Elementary Technical Mathematics

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The period and amplitude of the given expression y = 3.5 sin ( 2 3 x ) and graph the provided function.

Solution Summary: The author calculates the period and amplitude of the given expression y=3.5mathrmsin(23x).

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To calculate: The period and amplitude of the given expression y=3.5sin(23x) and graph the provided function.

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Chapter 14 Solutions