Use Problem 21 to evaluate the following
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- By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form x2+y2+Dx+Ey+F=0, we see that D=2h,E=2k, and F=h2+k2r2. Therefore, the center and the length of a radius of a circle can be found by using h=D2,k=E2 and r=h2+k2F. Use these relationship to find the center and the length of the radius of each of the following circles. x2+y2+4x14y+49=0arrow_forward5. Prove that the equation has no solution in an ordered integral domain.arrow_forwardJo 18.9. Let y denote the boundary of the rectangle whose vertices are -2 - 2i, 2 – 2i, 2+ i and -2+i in the positive direction. Evaluate each of the following integrals: (a). COS Z dz, 24 dz, (2z +1)2 dz, (b). T 2 4 (a). dz dz. (0). LE (0. sin z+ dz, (e). (z+1) z2 +2 (22 + 3)2 Jutio inside and 10arrow_forward
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