Explanation Given information: m A = m B = m C = 2 l b Velocity v o = ( 6.5 f t / s ) i Angle θ = 30 ° After impact Velocity of A, v A = ( 0.5 f t / s ) i and, Velocity of B, v B = ( 3.75 f t / s ) i + ( v B ) y j When the sphere moves freely than applying conservation of linear momentum: ∑ m v = ( ∑ m v ) 0 m v A + m v B + m v C = m ( v A ) 0 + m ( v B ) 0 + m ( v C ) 0 v A + v B + v C = ( v A ) 0 + ( v B ) 0 + ( v C ) 0 0.5 i + [ ( 3.75 ) i + ( v B ) y j ] + [ ( v c ) x i + ( v c ) y j ] = 6.5 i + 0 + 0 Taking both the components separately; 0.5 + 3.75 + ( v c ) x = 6.5 4.25 + ( v c ) x = 6.5 ( v c ) x = 2.25 f t / s ( v B ) y + ( v c ) y = 0 _ _ _ _ _ _ ( 1 ) Again taking into consideration conservation of angular momentum about O; ∑ [ r × m v ] = ∑ r × ( m v 0 ) Here, r A = r B = 0 a n d r C = ( 1

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Chapter 14.2, Problem 14.49P

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The velocity vector (vB)y of ball B and C immediately after impact.

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Chapter 14.2, Problem 14.48P

Chapter 14.2, Problem 14.50P

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Chapter 14 Solutions

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The velocity vector ( v B ) y of ball B and C immediately after impact.

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