Explanation Given: Velocity of suitcases is 7.2 ft/s , Velocity of baggage carrier is 3.6 ft/s , and weight of first suitcase is 30 lb . Concept used: Expression for conservation of momentum is given as follows: m 1 v 1 + m 2 v 2 = ( m 1 + m 2 + m 3 ) v ...... (1) Here, mass of suitcase is m , initial velocity of the suitcase is v , mass of baggage carrier m 3 and velocity of baggage carrier is v . Here, 1 and 2 are the subscript for first and second suitcases. Expression for the loss of energy is given as follows: K E L = K E i − K E f ...... (2) Here, initial kinetic energy is K E i , loss of kinetic energy is K E L and final kinetic energy is K E f . Calculation: After first suitcase hits the carrier: Substitute 7.2 ft/s for v 1 , 30 lb for m 1 , 0 lb for m 2 and 50 lb for m 3 in equation (1) To determine (b) The energy lost when second suitcase is hit by carrier.

12th Edition

ISBN: 9781260265521

Author: BEER

Publisher: MCG

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Conservation of Energy

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Chapter 14.2, Problem 14.32P

To determine

(a)

The energy lost when first suitcase is hit by carrier.

To determine

(b)

The energy lost when second suitcase is hit by carrier.

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Chapter 14.2, Problem 14.31P

Chapter 14.2, Problem 14.33P

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(a) The energy lost when first suitcase is hit by carrier.

Solution Summary: The author calculates the energy lost when first suitcase is hit by carrier.