Practice ProblemATTEMPT
Show that the following two-step mechanism is consistent with the experimentally determined rate law of rate
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Chemistry
- A reaction is believed to occur by the following mechanism: Stepl: 2AI (Fast equilibrium) Step 2: I + B C (Slow) Overall: 2 A + B C What experimentally determined rate law would lead to this mechanism? (a) Rate = k[A][B] (b) Rate = k[A]2[B] (c) Rate = k[A]2 (d) Rate = k[I][B]arrow_forwardIf the rate law for the reaction A ⟶Products is rate = k[A], calculate the value of k from the following data: [A] (M) Initial Rate (M/s) 0.10 0.015 (A)6.7 s-1 (B)0.015 s-1 (C)0.15 s-1 (D)67 s-1arrow_forwardView Policies Current Attempt in Progress Consider the reaction, CH3CI(g) + 3CI2(g) → CCI4(g) + 3HCI(g) (a) Express the rate of reaction with respect to each of the reactants and products. d[CH,C1] = - 3 1 d[Cl,]_ d[cC,I 1 ɖ[HCl] 3 %3D dt dt dt dt (CH,CI] = [C1,1 = [cci,I = [HC1] O dICH,CI] 1 d[Cl,] -dlcc,I 1 ɖ[HCl]_ dt dt 3 dt dt 3 d[Cl,] dt dt d[HCl] dt dt = -3 = 3 d[CH,C1] (b) If the instantaneous rate of the reaction with respect to HCI is 0.035 M-s-1, what is the instantaneous rate of the reaction with respect to CCI4? i M.s 1 eTextbook and Media GO Tutorial Save for Later Attempts: 0 of 15 used Submit Answer A O Sarrow_forward
- Please help with HW problemarrow_forwardQuestion carrow_forwardA study of the rate of dimerization of C,H, gave the data shown in the table: 2C,H6 → C3 H12 Time (s) 1600 3200 4800 6200 [C,HJ (M) 1.00 x 10-2 5.04 x 10-3 3.37 x 10-3 2.53 x 10-3 2.08 x 10-3 (a) Determine the average rate of dimerization between 0 s and 1600 s, and between 1600 s and 3200 s. (b) Estimate the instantaneous rate of dimerization at 3200 s from a graph of time veisus [C4H5]. What are the units of this rate? (c) Determine the average rate of formation of C3H12 at 1600 s and the instantaneous rate of formation at 3200 s from the rates found in parts (a) and (b).arrow_forward
- Question 3 of 8 Submit What are the units for the rate constant of a reaction with the rate law, Rate = k[A][B]? %3D A) s-1 B) M s-1 С) М-1 s-1 D) M-2 s-1 E) s M-1arrow_forwardWhen [A] is doubled, the rate doubles; when [B] is doubled, the rate quadruples; when [C] is doubled, the rate does not change. How would the rate change if the concentration of A and C are doubled when the concentration of B is tripled? A(g) + B(g) + C(g) => products A) The rate decreases by a factor of 4. B) The rate decreases by a factor of 2. C) The rate increases by a factor of 2. D) The rate increases by a factor of 4. E) The rate increases by a factor of 8. F) The rate increases by a factor of 16. G) The rate increase by a factor of 18. H) The rate does not change.arrow_forwardChloroform (CHCl3) is a known anesthetic. It is also used to produce the refrigerant carbon tetrachloride (CCl4) according to the reaction CHCl3(g) + Cl2(g)⟶CCl4(g) + HCl(g)Several experiments obtained the following data: Experiment Initial [CHCl3](M) Initial [Cl2](M) Initial Rate of Reaction (M/s) I 0.0011 0.014 2.60 x 10-4 II 0.0011 0.028 5.20 x 10-4 III 0.0022 0.028 2.08 x 10-3 IV 0.0022 0.014 1.04 x 10-3 Write the rate law expression for this reaction. Determine the value of the rate constant.arrow_forward
- Please quickly fastarrow_forwardThe initial rate of the reaction 2 A + B → C + D was studied in a series of kinetics experiments. Trial Conc A (M) Conc B (M) Initial Rate (M/s) 1 0.300 0.100 0.000704 2 0.900 0.100 0.006334 3 0.900 0.300 0.006334 What is the experimental rate law for this reaction? Question 16 options: A) Rate = k[B]2 B) Rate = k[A]2 C) Rate = k[A] D) Rate = k[A]2[B] E) Rate = k[A][B]arrow_forwardGiven the following data, determine the rate constant of the reaction 2NO(g) + Cl₂(g) → 2NOCI(g). Experiment 1 23 a) 59.6 M-25-1 Ob) 1.13 M-25-1 c) 37.8 M-2-1 d) 9.44 M-25-1 (d) [NO] (M) 0.0300 0.0150 0.0150 (e) 0.0265 M 2-1 [Cl₂] (M) 0.0100 0.0100 0.0400 Rate (M/s) 3.40 10 4 8.50 10 5 x 3.40 10-4arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning