
(a)
To determine: A mechanism that explains the fact that mustard gas is an exceptionally potent alkylating agent.
Interpretation: A mechanism is to be proposed that explains the fact that mustard gas is an exceptionally potent alkylating agent.
Concept introduction: Mustard gas was used as a poisonous chemical agent in World War I. It is much more toxic than a typical primary alkyl chloride. It is able to alkylate amino groups on important
(b)
To determine: The products that might be formed by the reaction of mustard gas with bleach.
Interpretation: The products that might be formed by the reaction of mustard gas with bleach are to be stated.
Concept introduction: Mustard gas was used as a poisonous chemical agent in World War I. It is much more toxic than a typical primary alkyl chloride. It is able to alkylate amino groups on important metabolic enzymes. It renders the enzyme inactive. Therefore, it is toxic.

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Chapter 14 Solutions
Student's Solutions Manual for Organic Chemistry
- (Please be sure that 7 carbons are available in the structure )Based on the 1H NMR, 13C NMR, DEPT 135 NMR and DEPT 90 NMR, provide a reasoning step and arrive at the final structure of an unknown organic compound containing 7 carbons. Dept 135 shows peak to be positive at 128.62 and 13.63 Dept 135 shows peak to be negative at 130.28, 64.32, 30.62 and 19.10.arrow_forward-lease help me answer the questions in the photo.arrow_forwardDefine electronegativity.arrow_forward
- Why do only the immediately adjacent H's show up in the number of peaks? Are there normally peaks for the H's that are 2-3 carbons away?arrow_forwardPlease help me understand this question. Thank you. Organic Chem 1arrow_forwardFor the reaction below, the concentrations at equilibrium are [SO₂] = 0.50 M, [0] = 0.45 M, and [SO3] = 1.7 M. What is the value of the equilibrium constant, K? 2SO2(g) + O2(g) 2SO3(g) Report your answer using two significant figures. Provide your answer below:arrow_forward
- scratch paper, and the integrated rate table provided in class. our scratch work for this test. Content attribution 3/40 FEEDBACK QUESTION 3 - 4 POINTS Complete the equation that relates the rate of consumption of H+ and the rate of formation of Br2 for the given reaction. 5Br (aq) + BrO3 (aq) + 6H (aq) →3Br2(aq) + 3H2O(l) • Your answers should be whole numbers or fractions without any decimal places. Provide your answer below: Search 尚 5 fn 40 * 00 99+ 2 9 144 a [arrow_forward(a) Write down the structure of EDTA molecule and show the complex structure with Pb2+ . (b) When do you need to perform back titration? (c) Ni2+ can be analyzed by a back titration using standard Zn2+ at pH 5.5 with xylenol orange indicator. A solution containing 25.00 mL of Ni2+ in dilute HCl is treated with 25.00 mL of 0.05283 M Na2EDTA. The solution is neutralized with NaOH, and the pH is adjusted to 5.5 with acetate buffer. The solution turns yellow when a few drops of indicator are added. Titration with 0.02299 M Zn2+ requires 17.61 mL to reach the red end point. What is the molarity of Ni2+ in the unknown?arrow_forwardA compound has the molecular formula CH40, and shows a strong IR absorption at 2850-3150 cm. The following signals appear in the 'H NMR spectrum: 1.4 ppm (triplet, 6H), 4.0 ppm (quartet, 4H), 6.8 ppm (broad singlet, 4H). Which of the following structures is consistent with these data? Select the single best answer. OCH CH₂ x OCH2CH3 CH₂OCH3 OH CH₂OCH OH CH, OCH₁ CH₂OCH, CH₂OCH HO OH ° CH₂OCH3arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
