Chapter 14.1, Problem 23PPS

To determine

To find:Simplification of $\cot \theta .\sec \theta$

Answer to Problem 23PPS

  $\mathrm{cosec}\theta$

Explanation of Solution

Given We know that, $\cot \theta .\sec \theta$

Calculation :

  $\begin{array}{l}\Rightarrow \cot \theta .\sec \theta \\ \Rightarrow \frac{\cancel{\cos \theta }}{\sin \theta }\times \frac{1}{\cancel{\cos \theta }}\\ \Rightarrow \mathrm{cosec}\theta \end{array}$