Chapter 14, Problem 18PT

To determine

To find :The value of $\sin 480°.$

Answer to Problem 18PT

  $\frac{1}{2}$

Explanation of Solution

Given information :

We know that, the given expression is $\text{sin 480°}\text{.}$

Calculation :

The given equation is

  $\begin{array}{l}\sin 480°=\sin (450°+30°)\\ =\sin 30°(\sin \theta \text{ is positive in IInd quadrant})\\ =\frac{1}{2}\end{array}$