Chapter 14, Problem 32SGR

To determine

To verify :The value of $\tan (\theta -\pi )=\tan \theta$ .

Explanation of Solution

Given information :

We know that, the given expression is $\tan (\theta -\pi )=\tan \theta$

Formula Used:

  $\tan (-\theta )=-\tan \theta$

Calculation :

The given equation is

  $\begin{array}{l}L.H.S.=\tan (\theta -\pi )\\ =\tan (-(\pi -\theta ))\\ =-\tan (\pi -\theta )\\ =-(-\tan \theta )\\ =\tan \theta \\ =R.H.S.\end{array}$