(a) Explanation The integrated rate law for the first order reaction depends only on the initial and final concentration of the reactant. The number of red spheres present at t = 0 min are 22 . The number of red and blue spheres present at t = 30 min are 6 and 16 . The initial concentration of the red spheres (reactant represented by A ) at t = 0 min is 22 and the final concentration of red spheres (reactant represented by A ) at t = 30 min is 6 . The integrated rate law for the first order reaction is given by the Equation, ln [ A ] t = − k t + ln [ A ] 0 From the above Equation, k is calculated by the formula, k = − ( ln [ A ] t − ln [ A ] 0 t ) Where, [ A ] t is the final concentration of reactant A at time t s . [ A ] 0 is the intial concentration of reactant A at time 0 s . k is the rate constant. t is the final time. Substitute the values of [ A ] t , [ A ] 0 and t in the above formula (b) Interpretation Introduction To determine: The fraction of the reactant that remains after the four half-life periods for a first order reaction.

Laboratory Experiments For Chemistry: The Central Science, Si Edition

14th Edition

ISBN: 9781292221335

Author: Theodore E. Brown

Publisher: PEARSON

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Chapter 14, Problem 7E

(a)

Interpretation Introduction

To determine: The half-life of the given reaction, if the reaction follows the first-order kinetics.

(b)

Interpretation Introduction

To determine: The fraction of the reactant that remains after the four half-life periods for a first order reaction.

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Chapter 14, Problem 6E

Chapter 14, Problem 8E

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Chapter 14 Solutions

Laboratory Experiments For Chemistry: The Central Science, Si Edition

Ch. 14.2 - If the experiment in Figure 14.2 is run for 60 s,...Ch. 14.2 - Prob. 14.1.2PE Ch. 14.2 - Which of the following could be the instantaneous...Ch. 14.2 - Using Figure 14.3, determine the instantaneous...Ch. 14.2 - At a certain time in a reaction, substance A is...Ch. 14.2 - Prob. 14.3.2PE Ch. 14.3 - Suppose the rate law for the reaction in this...Ch. 14.3 - Assuming that rate = k[A][B], rank the mixtures...Ch. 14.3 - Prob. 14.5.1PE Ch. 14.3 - Prob. 14.5.2PE

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