CHEMISTRY:MOLECULAR..(LL)-PRINT..W/CODE
7th Edition
ISBN: 9781119457282
Author: JESPERSEN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 14, Problem 6PE
Write the equilibrium law in terms of partial pressures for the following reaction. (Hint: Keep in mind how the mass action expression is written.)
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Chapter 14 Solutions
CHEMISTRY:MOLECULAR..(LL)-PRINT..W/CODE
Ch. 14 - In what way dots the chapter-opening photo...Ch. 14 - Write the equilibrium law for each of the...Ch. 14 - The equilibrium law for a reaction is...Ch. 14 - At25C,Kc=7.01025forthereaction2SO2(g)+O2(g)2SO3(g)...Ch. 14 - At 25C, the following reactions have the...Ch. 14 - Write the equilibrium law in terms of partial...Ch. 14 - Using partial pressures, write the equilibrium law...Ch. 14 - Nitrous oxide, , is a gas used as an anesthetic;...Ch. 14 - Methanol, CH5OH, is a promising fuel that can be...Ch. 14 - Write the equilibrium law for the following...
Ch. 14 - Write the equilibrium law for each of the...Ch. 14 - Suppose a mixture contained equal concentrations...Ch. 14 - Arrange the following reactions in order of their...Ch. 14 - Consider the equilibrium...Ch. 14 - Consider the equilibrium PCl3(g)+Cl2(g)PCl5(g) for...Ch. 14 - In a particular experiment, it was found that when...Ch. 14 - An equilibrium was established for the reaction...Ch. 14 - A student placed 0.200 mol of PCl3(g) and 0.100...Ch. 14 - The decomposition of ,
has vessel contained...Ch. 14 - Prob. 20PECh. 14 - During an experiment, 0.200molofH2and0.200molofI2...Ch. 14 - In an experiment, were placed in a 1.00 L vessel...Ch. 14 - At 25C, the reaction...Ch. 14 - In air at and 1.00 atm, the concentration is...Ch. 14 - Dynamic Equilibrium in Chemical Systems 14.1...Ch. 14 - Dynamic Equilibrium in Chemical Systems
14.2 Using...Ch. 14 - Dynamic Equilibrium in Chemical Systems Repeat the...Ch. 14 - Dynamic Equilibrium in Chemical Systems
14.4 Using...Ch. 14 - 14.5 What meanings do the terms reactants and...Ch. 14 - Equilibrium Laws
14.6 What is an equilibrium law?....Ch. 14 - Equilibrium Laws
14.7 How is the term reaction...Ch. 14 - Equilibrium Laws
14.8 When a chemical equation and...Ch. 14 - Equilibrium Laws 14.9 Under what conditions does...Ch. 14 - Equilibrium Laws
14.10 Describe in words how the...Ch. 14 - Equilibrium Laws Based on Pressures or...Ch. 14 - Equilibrium Laws Based on Pressures or...Ch. 14 - Equilibrium Laws Based on Pressures or...Ch. 14 - Equilibrium Laws Based on Pressures or...Ch. 14 - Equilibrium Laws for Heterogeneous Reactions 14.15...Ch. 14 - Equilibrium Laws for Heterogeneous Reactions 14.16...Ch. 14 - Position of Equilibrium and the Equilibrium...Ch. 14 - Position of Equilibrium and the Equilibrium...Ch. 14 - Position of Equilibrium and the Equilibrium...Ch. 14 - Position of Equilibrium and the Equilibrium...Ch. 14 - Equilibrium and Le Chtelier's Principle State Le...Ch. 14 - Equilibrium and Le Chtelier's Principle Explain,...Ch. 14 - Equilibrium and Le Chteliers Principle Halving the...Ch. 14 - Equilibrium and Le Chteliers Principle How will...Ch. 14 - Equilibrium and Le Châtelier's Principle
14.25 Why...Ch. 14 - Equilibrium and Le Chtelier's Principle Why doesnt...Ch. 14 - Equilibrium Laws
14.27 Write the equilibrium law...Ch. 14 - Equilibrium Laws
14.28 Write the equilibrium law...Ch. 14 - Write the equilibrium law for the following...Ch. 14 - Write the equilibrium law for the following...Ch. 14 - At 25C,Kc=11085 for the reaction...Ch. 14 - Use the following equilibria...Ch. 14 - Write the equilibrium law for each of the...Ch. 14 - 14.34 Write the equilibrium law for the...Ch. 14 - Equilibrium Laws Based on Pressures and...Ch. 14 - 14.36 Write the equilibrium law for the reactions...Ch. 14 - Prob. 37RQCh. 14 - Prob. 38RQCh. 14 - For which of the following reactions does Kp=Kc?...Ch. 14 - For which of the following reactions does KpKc?...Ch. 14 - 14.41 The reaction has a . What is the value of ...Ch. 14 - 14.42 The reaction has a . What is the value of ...Ch. 14 - 14.43 The reaction has a . What is the value of ...Ch. 14 - One possible way of removing NO from the exhaust...Ch. 14 - At 773C the reaction CO(g)+2H2(g)CH3OH(g) has...Ch. 14 - The reaction...Ch. 14 - Equilibrium Laws for Heterogeneous Reactions...Ch. 14 - Equilibrium Laws for Heterogeneous Reactions The...Ch. 14 - Equilibrium Laws for Heterogeneous Reactions
14.49...Ch. 14 - Equilibrium Laws for Heterogeneous Reactions
14.50...Ch. 14 - The heterogeneous reaction...Ch. 14 - At 25C,Kc=360 for the reaction...Ch. 14 - Equilibrium and Le Chtelier's Principle The...Ch. 14 - Equilibrium and Le Chtelier's Principle How will...Ch. 14 - 14.55 Consider the equilibrium
In which direction...Ch. 14 - Consider the equilibrium 2NO(g)+Cl2(g)2NOCl(g) for...Ch. 14 - Calculating Equilibrium Constants At 773C, a...Ch. 14 - Calculating Equilibrium Constants Ethylene, C2H4,...Ch. 14 - At high temperature, 2.00 mol of HBr was placed in...Ch. 14 - A 0.050 mol sample of formaldehyde vapor, CH2O,...Ch. 14 - The reaction NO2(g)+NO(g)N2O(g)+O2(g) reached...Ch. 14 - At 25C,0.0560molO2and0.020molN2O were placed in a...Ch. 14 - Using Equilibrium Constants to Calculate...Ch. 14 - Using Equilibrium Constants to Calculate...Ch. 14 - 14.65 At a certain temperature, the reaction
has...Ch. 14 - 14.66 for the reaction
at a certain temperature....Ch. 14 - At 25C,Kc=0.145 for the following reaction in the...Ch. 14 - At 25C,Kc=0.145 for the following reaction in the...Ch. 14 - 14.69 The equilibrium constant, Kc, for the...Ch. 14 - For the reaction in Problem 14.69, a reaction...Ch. 14 - 14.71 At a certain temperature the reaction
has ....Ch. 14 - At 25C,Kc=0.145 for the following reaction in the...Ch. 14 - The reaction...Ch. 14 - 14.74 At for the reaction
If and are placed in...Ch. 14 - 14.75 At , the decomposition of , has . If a 1.00...Ch. 14 - At 500C, the decomposition of water into hydrogen...Ch. 14 - 14.77 At a certain temperature, for the...Ch. 14 - At 460C, the reaction SO2(g)+NO2(g)NO(g)+SO3(g)...Ch. 14 - 14.79 At a certain temperature, for the...Ch. 14 - At 25C,Kc=0.145 for the following reaction in the...Ch. 14 - *14.81 At a certain temperature, for the...Ch. 14 - The reaction...Ch. 14 - 14.83 The reaction at
. In a reaction vessel...Ch. 14 - 14.84 At , the following concentrations were found...Ch. 14 - The following reaction in aqueous solution has...Ch. 14 - At a certain temperature, Kc=0.914 for the...Ch. 14 - At 27C,Kc=1.51018 for the reaction...Ch. 14 - Consider the equilibrium...Ch. 14 - At a certain temperature, Kc=0.914 for the...Ch. 14 - At a certain temperature, Kc=0.914 for the...Ch. 14 - 14.91 Two 1.00 L bulbs are filled with 0.500 atm...Ch. 14 - For the equilibrium 3NO2(g)N2O5(g)+NO(g)...Ch. 14 - To study the following reaction at 20C,...Ch. 14 - Describe in words how the mass action expression...Ch. 14 - *14.95 For the reaction below,
A mixture of was...Ch. 14 - At 2000C, the decomposition of CO2,...Ch. 14 - *14.97 At , the reaction
has are placed in a...Ch. 14 - At 200.0C,Kc=1.410-10 for the reaction...Ch. 14 - At 400C,Kc=2.9104 for the reaction:...Ch. 14 - *14.100 The reaction . Into a 4.50 L reaction...Ch. 14 - 14.101 In an equilibrium law, coefficients in the...Ch. 14 - Why are equilibrium concentrations useful to know?Ch. 14 - 14.103 Suppose we set up a system in which water...Ch. 14 - 14.104 Do equilibrium laws apply to other systems...Ch. 14 - What might prevent a system from reaching dynamic...Ch. 14 - 14.106 After many centuries the earth’s atmosphere...Ch. 14 - 14.107 If a mixture consisting of many small...Ch. 14 - Why doesnt Le Chteliers principle apply to the...Ch. 14 - 14.109 Le Châtelier’s principle qualitatively...
Additional Science Textbook Solutions
Find more solutions based on key concepts
4.50. Open the 3D Molecular Models on the book’s website for cyclopentane and vitamin . Compare cyclopentane wi...
Organic Chemistry
Find the change in enthalpy for carbon dioxide going from 500 to 1500 K by integrating the equation in Table A....
Fundamentals Of Thermodynamics
27. A resistor connected to a 3.0 V battery dissipates 1.0 W. If the battery is replaced by a 6.0 V battery, th...
College Physics: A Strategic Approach (3rd Edition)
25. Convert the following to SI units:
a. 75 in b. 3.45 × 106yr
c. 62 ft/day d. 2.2 × 104 mi2
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Match each of the following items with all the terms it applies to:
Human Physiology: An Integrated Approach (8th Edition)
47. Balance each chemical equation.
a.
b.
c.
d.
Introductory Chemistry (6th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Distinguish between the terms equilibrium constant and reaction quotient. When Q = K, what does this say about a reaction? When Q K, what does this say about a reaction? When Q K. what does this say about a reaction?arrow_forwardWrite equilibrium constant expressions for the following reactions. For gases, use either pressures or concentrations. (a) 2 H2O2(g) 2 H2O(g) + O2(g) (b) CO(g) + O2g CO2(g) (c) C(s) + CO2(g) 2 CO(g) (d) NiO(s) + CO(g) Ni(s) + CO2(g)arrow_forwardFor the reaction N2(g)+3H2(g)2NH3(g) show that Kc = Kp(RT)2 Do not use the formula Kp = Kc(RT)5n given in the text. Start from the fact that Pi = [i]RT, where Pi is the partial pressure of substance i and [i] is its molar concentration. Substitute into Kc.arrow_forward
- Describe a nonchemical system that is in equilibrium, and explain how the principles of equilibrium apply to the system.arrow_forwardYou place 0.600 mol of nitrogen, N2, and 1.800 mol of hydrogen, H2, into a reaction vessel at 450C and 10.0 atm. The reaction is N2(g)+3H2(g)2NH3(g) What is the composition of the equilibrium mixture if you obtain 0.048 mol of ammonia, NH3, from it?arrow_forwardThe atmosphere consists of about 80% N2 and 20% O2, yet there are many oxides of nitrogen that are stable and can be isolated in the laboratory. (a) Is the atmosphere at chemical equilibrium with respect to forming NO? (b) If not, why doesnt NO form? If so, how is it that NO can be made and kept in the laboratory for long periods?arrow_forward
- At a certain temperature, K=0.29 for the decomposition of two moles of iodine trichloride, ICl3(s), to chlorine and iodine gases. The partial pressure of chlorine gas at equilibrium is three times that of iodine gas. What are the partial pressures of iodine and chlorine at equilibrium?arrow_forwardAt 2300 K the equilibrium constant for the formation of NO(g) is 1.7 103. N2(g) + O2(g) 2 NO(g) (a) Analysis shows that the concentrations of N2 and O2 are both 0.25 M, and that of NO is 0.0042 M under certain conditions. Is the system at equilibrium? (b) If the system is not at equilibrium, in which direction does the reaction proceed? (c) When the system is at equilibrium, what are the equilibrium concentrations?arrow_forwardShow that the complete chemical equation, the total ionic equation, and the net ionic equation for the reaction represented by the equation KI(aq)+I2(aq)KI3(aq) give the same expression for the reaction quotient. KI3 is composed of the ions K+ and I3-.arrow_forward
- The diagram represents an equilibrium mixture for the reaction N2(g) + O2(g) ⇌ 2 NO(g) Estimate the equilibrium constant.arrow_forwardA solution is prepared by dissolving 0.050 mol of diiodocyclohexane, C5H10I2, in the solvent CCl4.The total solution volume is 1.00 L When the reaction C6H10I2 C6H10 + I2 has come to equilibrium at 35 C, the concentration of I2 is 0.035 mol/L. (a) What are the concentrations of C6H10I2 and C6H10 at equilibrium? (b) Calculate Kc, the equilibrium constant.arrow_forwardNitrosyl chloride, NOC1, decomposes to NO and Cl2 at high temperatures. 2 NOCl(g) ⇌ 2 NO(g) + Cl2(g) Suppose you place 2.00 mol NOC1 in a 1.00–L flask, seal it, and raise the temperature to 462 °C. When equilibrium has been established, 0.66 mol NO is present. Calculate the equilibrium constant Kc for the decomposition reaction from these data.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physical ChemistryChemistryISBN:9781133958437Author:Ball, David W. (david Warren), BAER, TomasPublisher:Wadsworth Cengage Learning,
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
Physical Chemistry
Chemistry
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Wadsworth Cengage Learning,
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY