Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 14, Problem 62P
To determine
The gravity at location of simple pendulum.
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A pendulum of length L oscillates with a frequency of 0.59 Hz near the surface of the planet Magrathea. When the length of the pendulum is decreased by 42 cm, the frequency increases to 0.81 Hz. What was the initial length of the pendulum?
A 52.1 cm-long pendulum takes 2.50 minutes to undergo 104.6 complete back-and-forth cycles.
(a) Compute the pendulum's period (in s).
______________________s
(b) Determine the acceleration due to gravity (in m/s2) at the place where the pendulum is located.
_____________________ m/s2
The theoretical expression for the period of oscillation for a simple pendulum with small oscillations is given by:
T = 2pi*sqrt(L/g)
where T is the period, L is the length of the pendulum, and g is the value of the Earth’s gravitational field.
Period (s) Length (m)
4.49 5.00
6.34 10.00
7.77 15.00
8.97 20.00
10.03 25.00
14.19 50.00
20.08 100.00
Knowing that LENGTH is the indipendent variable and PERIOD is the dependent one please write your equation in y=mx+b form, including the y.
Chapter 14 Solutions
Physics for Scientists and Engineers
Ch. 14 - Prob. 1PCh. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Prob. 8PCh. 14 - Prob. 9PCh. 14 - Prob. 10P
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- We do not need the analogy in Equation 16.30 to write expressions for the translational displacement of a pendulum bob along the circular arc s(t), translational speed v(t), and translational acceleration a(t). Show that they are given by s(t) = smax cos (smpt + ) v(t) = vmax sin (smpt + ) a(t) = amax cos(smpt + ) respectively, where smax = max with being the length of the pendulum, vmax = smax smp, and amax = smax smp2.arrow_forwardIf the speed of the observer is increased by 5.0%, what is the period of the pendulum when measured by this observer?arrow_forwardA simple pendulum has mass 1.20 kg and length 0.700 m. (a) What is the period of the pendulum near the surface of Earth? (b) If the same mass is attached to a spring, what spring constant would result in the period of motion found in part (a)?arrow_forward
- A grandfather clock has a pendulum length of 0.7 m and mass bob of 0.4 kg. A mass of 2 kg falls 0.8 m in seven days to keep the amplitude (from equilibrium) of the pendulum oscillation steady at 0.03 rad. What is the Q of the system?arrow_forwardIf a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? (a) It doubles. (b) It becomes 2 times as large. (c) It becomes half as large. (d) It becomes 1/2 times as large. (e) It remains the same.arrow_forwardFor each expression, identify the angular frequency , period T, initial phase and amplitude ymax of the oscillation. All values are in SI units. a. y(t) = 0.75 cos (14.5t) b. vy (t) = 0.75 sin (14.5t + /2) c. ay (t) = 14.5 cos (0.75t + /2) 16.3arrow_forward
- In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x=5.00cos(2t+6) where x is in centimeters and t is in seconds. At t = 0, find (a) the position of the piston, (b) its velocity, and (c) its acceleration. Find (d) the period and (e) the amplitude of the motion.arrow_forwardWhat is the length of a pendulum that has a period of 0.500 s?arrow_forwardAn object of mass m moves in simple harmonic motion with amplitude 12.0 cm on a light spring. Its maximum acceleration is 108 cm/s2. Regard m as a variable. (a) Find the period T of the object. (b) Find its frequency f. (c) Find the maximum speed vmax of the object. (d) Find the total energy E of the objectspring system. (e) Find the force constant k of the spring. (f) Describe the pattern of dependence of each of the quantities T, f, vmax, E, and k on m.arrow_forward
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SIMPLE HARMONIC MOTION (Physics Animation); Author: EarthPen;https://www.youtube.com/watch?v=XjkUcJkGd3Y;License: Standard YouTube License, CC-BY