Biology: The Unity and Diversity of Life
15th Edition
ISBN: 9780357093795
Author: STARR
Publisher: CENGAGE LEARNING (CUSTOM)
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Textbook Question
Chapter 14, Problem 5GP
Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY).
- a. With respect to X chromosome alleles, how many different types of gametes can a male produce?
- b. If a female is homozygous for an allele on an X chromosome, how many types of gametes can she produce with respect to that allele?
- c. If a female is heterozygous for an X chromosome allele, how many types or gametes can she produce with respect to that allele?
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A,b and c please
An XXY male appears as a normal male. He married a sexually normal female who is trisomic
for Patau syndrome.
a. Diagram the cross; give the gametes from each parent and give the progeny.
b. What kinds of offspring as to sexual chromosome aberration may they have? What is the
probability of each kind?
c. What is the probability that the couple will have a son with Patau syndrome?
d. What is the probability of a child with sexual and autosomal chromosome aberration?
e. What is the probability of having normal progeny?
If a diploid organism has 14 chromosomes (2n=14)
a. How many chromosomes will its gametes have?
b. After meiosis I during gamete formation, how many chromosomes are in each daughter cell?
c. After meiosis I during gamete formation, how many chromatids are in each daughter cell?
Chapter 14 Solutions
Biology: The Unity and Diversity of Life
Ch. 14 - Prob. 1DAACh. 14 - Prob. 2DAACh. 14 - Prob. 3DAACh. 14 - Prob. 4DAACh. 14 - Prob. 5DAACh. 14 - Prob. 1SQCh. 14 - Pedigree analysis is necessary when studying human...Ch. 14 - A recognized set of symptoms that characterize a...Ch. 14 - Prob. 4SQCh. 14 - A trait that is present in a male child but not in...
Ch. 14 - Choose the statement that is incorrect. a. A son...Ch. 14 - Prob. 7SQCh. 14 - Prob. 8SQCh. 14 - Klinefelter syndrome (XXY) can most be easily...Ch. 14 - Prob. 10SQCh. 14 - Does the phenotype indicated by the red circles...Ch. 14 - G6PD deficiency is an X-Linked recessive disorder....Ch. 14 - Marian syndrome (Section 13.5) is inherited in an...Ch. 14 - Duchenne muscular dystrophy, which is inherited in...Ch. 14 - Human females have two X chromosomes (XX); males...Ch. 14 - A mutation on an autosome causes a particular...Ch. 14 - Expression of the SRY gene on the Y chromosome...Ch. 14 - The somatic cells of most individuals with Down...Ch. 14 - Mutations in the genes for clotting factor VIII...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele? c. If a female is heterozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele?arrow_forwardA woman with normal chromosomes mates with a man who also has normal chromosomes. a. Suppose that, in the course of oogenesis, the woman’s sex chromosomes undergo nondisjunction in meiosis I; the man’s chromosomes separate normally. Give all possible combinations of sex chromosomes that this couple’s children might inherit and the number of Barr bodies that you would expect to see in each of the cells of each child. b. What chromosome combinations and numbers of Barr bodies would you expect to see if the chromosomes separate normally in oogenesis, but nondisjunction of the sex chromosomes takes place in meiosis I of spermatogenesis?arrow_forwardAn organism has a diploid number of 20 in a primary oocyte. a. How many tetrads are present in the meiotic prophase l? b. How many dyads are present in the meiotic prophase II ? c. How many monads migrate to each pole during meiotic anaphase II ?arrow_forward
- Assume that one of Merida's sons, who is heterozygous for orange hair color, married a girl that was also heterozygous. Create a Punnett square to show the possibilities that would result if they had children. a. List the possible genotypes and phenotypes for their children. b. What are the chances of a child with orange hair? c. What are the chantes of a child with yellow?arrow_forwardWhich of the following is a TRUE statement regarding the outcome of meiosis? A. In meiosis, one diploid cell (2n) can produce 2 haploid cells in males (1n). B. In meiosis, four haploid cells (1n) can produce 2 diploid cells (2n) in males. C. In meiosis, one diploid cell (2n) can produce up to 4 haploid cells (1n) in males. D. In meiosis, one diploid cell (2n) can produce 2 diploid cells (2n) in females.arrow_forwardAn individual is heterozygous for a reciprocal translocation, with the following chromosomes: A • B C D E F A • B C V W X R S T • U D E F R S T • U V W X a. Draw a picture of these chromosomes pairing in prophase I of meiosis. b. Draw the products of alternate, adjacent-1, and adjacent-2 segregations. c. Explain why the fertility of this individual is likely to be less than the fertility of an individual without a translocation.arrow_forward
- A.) In which parent did nondisjunction take place? B.) How many Chromosomes would be in zygote 1, 2, and 3? C.) Which zygote, if any, would be most likely to be healthy? Explain. D.) Name the conditions the non-healthy zygotes have.arrow_forwardWhat is the phenotype of a person who has XXXY sex chromosomes? a. Klinefelter syndromeb. Turner syndromec. Poly-X femalearrow_forwardMendel's observation of the random distribution of two different traits from parents to offspring (giving the 9:3:3:1 ratio of phentypes) was due to A. The random and independent way in which each pair of homologous chromosomes lines up at the metaphase plate during meiosis I. B. The random nature of the fertilization of ova by sperm. C. The random distribution of the sister chromatids to the two daughter cells during anaphase II. D. The relatively small degree of homology shared by the X and Y chromosomes.arrow_forward
- Chromosomal nondisjunction of the X chromosome in female gametes of humans means that live offspring can include Select one: O A. females with XX, and males with XY or XO O B. females with XX or XXX, and males with XY or XO O C. females with XX or XXX, and males with XY or XXY O D. females with XX, and males with XY E. females with XX or XO, and males with XY or OYarrow_forwardA young couple is planning to have children. Knowing that there have been a substantial number of stillbirths, miscarriages, and fertility problems on the husband’s side of the family, they see a genetic counselor. A chromosome analysis reveals that, whereas the woman has a normal karyotype, the man possesses only 45 chromosomes and is a carrier of a Robertsonian translocation between chromosomes 22 and 13. a. List all the different types of gametes that might be produced by the man. b. What types of zygotes will develop when each of gametes produced by the man fuses with a normal gamete produced by the woman? c. If trisomies and monosomies entailing chromosomes 13 and 22 are lethal, approximately what proportion of the surviving offspring are expected to be carriers of the translocation?arrow_forwardShown below are photomicrographs of Rhoeo tradescantia cells undergoing meiosis. Answer the following question for each of the photomicrograph: a. Identify the cytogenetic abnormality observed (ex. ring, chain, laggard, bridge) b. Identify the meiotic stage in which these aberrations are observed (as shown in the photomicrograph) c. Explain how these aberrations are formed d. Will this result to sterile or fertile gametes? Explain.arrow_forward
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