Explanation Given information: A spacer is given as below indicating dimensions in millimeter. Calculation: As we know that area of a square is given by - A = s 2 , where s = side length. Here, side length of the spacer is 19.60 inch. i.e. s = 19.60 millimeter. So, area of the square will be - A = s 2 ⇒ A = ( 19.60 ) 2 mm 2 {Put s = 19.60 mm} ⇒ A = 384.16 mm 2 Here, radius length of the inner circle is 4.20 millimeter. i.e. R = 4.20 millimeter. So, area of the inner circle will be - A = π × R 2 ⇒ A = 3

8th Edition

ISBN: 9781337798310

Author: Peterson, John.

Publisher: Cengage Learning,

See similar textbooks

Question

Chapter 14, Problem 57A

To determine

To find the metal area of given spacer.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 14, Problem 56A

Chapter 14, Problem 58A

Students have asked these similar questions

5. (a) State the Residue Theorem. Your answer should include all the conditions required for the theorem to hold. (4 marks) (b) Let y be the square contour with vertices at -3, -3i, 3 and 3i, described in the anti-clockwise direction. Evaluate に dz. You must check all of the conditions of any results that you use. (5 marks) (c) Evaluate L You must check all of the conditions of any results that you use. ཙ x sin(Tx) x²+2x+5 da. (11 marks)

3. (a) Lety: [a, b] C be a contour. Let L(y) denote the length of y. Give a formula for L(y). (1 mark) (b) Let UCC be open. Let f: U→C be continuous. Let y: [a,b] → U be a contour. Suppose there exists a finite real number M such that |f(z)| < M for all z in the image of y. Prove that < ||, f(z)dz| ≤ ML(y). (3 marks) (c) State and prove Liouville's theorem. You may use Cauchy's integral formula without proof. (d) Let R0. Let w € C. Let (10 marks) U = { z Є C : | z − w| < R} . Let f UC be a holomorphic function such that 0 < |ƒ(w)| < |f(z)| for all z Є U. Show, using the local maximum modulus principle, that f is constant. (6 marks)

3. (a) Let A be an algebra. Define the notion of an A-module M. When is a module M a simple module? (b) State and prove Schur's Lemma for simple modules. (c) Let AM(K) and M = K" the natural A-module. (i) Show that M is a simple K-module. (ii) Prove that if ƒ € Endд(M) then ƒ can be written as f(m) = am, where a is a matrix in the centre of M, (K). [Recall that the centre, Z(M,(K)) == {a Mn(K) | ab M,,(K)}.] = ba for all bЄ (iii) Explain briefly why this means End₁(M) K, assuming that Z(M,,(K))~ K as K-algebras. Is this consistent with Schur's lemma?

Chapter 14 Solutions

Mathematics For Machine Technology

Ch. 14 - Subtract 7516278 .Ch. 14 - Multiply 7238 . Express the result as a mixed...Ch. 14 - Multiply 1.7022.35 .Ch. 14 - Use Figure 14-5 to answer Exercises 4 through 6....Ch. 14 - Use Figure 14-5 to answer Exercises 4 through 6....Ch. 14 - Use Figure 14-5 to answer Exercises 4 through 6....Ch. 14 - Raise the following numbers to the indicated...Ch. 14 - Raise the following numbers to the indicated...Ch. 14 - Raise the following numbers to the indicated...Ch. 14 - Raise the following numbers to the indicated...

Knowledge Booster

To find the metal area of given spacer.

Solution Summary: The author calculates the metal area of a spacer, indicating dimensions in millimeters.

To find the metal area of given spacer.

Want to see the full answer?

Chapter 14 Solutions