Chapter 14, Problem 54GP

To determine

To find: The amount of water lose.

Answer to Problem 54GP

Mass of water evaporated is $4.06\text{kg}$ .

Explanation of Solution

Given Data:

Metabolism rate, $\left(\frac{\Delta Q}{\Delta t}\right)=950$ kcal/h

Mass $=55$ kg

Time $=2.5$ hr

Formula used:

  $\Delta Q=m.L_v$

Here $L_v$ = latent heat of vaporization

Calculation:

Latent heat of vaporization at ${20}^{\circ }C$

  $L_{V2}=585\text{kcal/kg}$

Heat energy consumed in 2.5 hrs $=2.5\times 950kcal$

  $\begin{array}{l}2.5\times 950=m\times 585\hfill \\ m=\frac{2.5\times 950}{585}\text{kg}\hfill \\ =4.06\text{kg}\hfill \end{array}$

Conclusion:

Hence $4.06\text{kg}$ water will evaporate.