An average active person consumes about 2500 Cal a day. (a) What is this in joules? (b) What is this in kilowatt-hours? (c) If your power company charges about 10 $ per kilowatt-hour, how much would your energy cost per day if you bought it from the power company? Could you feed yourself on this much money per day?
Part(a)To determine:
To convert energy in calories to joules.
Answer to Problem 4P
Solution:
2500 Calories is kWhr
Explanation of Solution
Formula Used:
1000 Calories is 4186 J
Calculation:
If 1000 Calories is 4186 J, then 1 Calories is J
Then 2500 Calories must be J
Part(b)To determine:
To convert energy in calories to KiloWatt-Hours.
Answer to Problem 4P
Solution:
2500 Calories is 10465 KWhr
Explanation of Solution
Formula Used:
1000 Calories is 0.00116222KWhr
Calculation:
If 1000 Calories is 0.00116222 KWhr, then 1 Calories is KWhr
Then 2500 Calories must be KWhr
Part(c)To determine:
Cost for energy consumption.
Answer to Problem 4P
Solution:
Energy cost per day is cents
Explanation of Solution
Formula Used:
1000 Calories is 0.00116222 KWhr
Calculation:
If 1000 Calories is 0.00116222 KWhr, then 1 Calories is KWhr
Then 2500 Calories must be KWhr
If it costs 10 cents per KWhr, then it would cost cents
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