Interpretation:
The structure of the compound C in the given reactionis to be drawn and explanation of high degree of symmetry of compound D is to be suggestedby making structure.
Concept introduction:
According to
The aromatic compound contains conjugated pi bonds.
All the atoms in the ring have an unhybridized
Antiaromatic compounds contain
The numerical proportion of signals generated in
Nuclear Magnetic Resonance (NMR) is one of the most capable analytical techniques used for determining the functional groups and how the atoms are structured and arranged in a molecule.
Few elements, such as
In
Induced magnetic field consists of electricity generated from movement in a magnetic field.
Any signal’s position on the X-axis in the
The number of signals in
The area covered by the signal is proportional to the number of equivalent protons causing the signal.
The hydrogen atom on adjacent carbon atoms splits the peak into two or more peaks. One, two, and three hydrogen atoms split the peak into two, three and four peaks, which further, is referred to as doublet, triplet or quartet.
The decrease in the electron density around a proton deshields the signal downfield at a larger value of chemical shift.
The increase in electron density shields the signal upfield at a lower value of chemical shift.
Cyclopentadiene, on treatment with sodium, loses a proton to form cyclopentadienyl anion
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Organic Chemistry
- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardPropose a structure consistent with the following spectral data for a compound C8H18O2: IR: 3350 cm-1 1H NMR: 1.24 δ (12 H, singlet); 1.56 δ (4 H, singlet); 1.95 δ (2 H, singlet)arrow_forwardTreatment of 3,4-dibromohexane with strong base leads to loss of 2 equivalents of HBr and formation of a product with formula C6H10. Three products are possible. Name each of the three, and tell how you would use 1H and 13CNMR spectroscopy to help identify them. How would you use UV spectroscopy?arrow_forward
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- A compound with a molecular formula C9H120 has the H NMR spectrum shown. Which of the following structures is consistent with this spectrum? 2 1 exchanges with D20 PPM HO HO III ÓH IV V O II O IVarrow_forwardNonearrow_forward24. The 1HNMR spectrum of an unknown acid has the following peaks: 12.71 ppm (1H, S); 8.04 ppm (2H, d); 7.30 ppm (2H, d); 2.41 ppm (3H, s) Which structure best fits this spectral information? Dlan OH A B علی مود C OH D OHarrow_forward
- Compound X (molecular formula C10H12O) was treated with NH2NH2, −OH to yield compound Y (molecular formula C10H14). Based on the 1HNMR spectra of X and Y given below, what are the structures of X and Y?arrow_forwardpunqe You will characterize your product by 'H NMR spectroscopy. How many different proton environments do you expect your product compound to exhibit? How many "C environments would you expect to see in the "C NMR spectrum? OS IS TS ES YS SS 9S LS S 6S 09 19 19 99 59 99 L9 19 69 OL IL TL EL YL SL YL LL L 6L O1 I'8 X: parts per Million: Protonarrow_forwardTreatment of 2-butanone (CH3COCH2CH3) with strong base followed by CH3I forms a compound Q, which gives a molecular ion in its mass spectrum at 86. The IR (>1500 cm–1 only) and 1H NMR spectrum of Q are given below. What is the structure of Q?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningEBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT