1 SEM CARDLESS ACC W/RAVEN TEXT
12th Edition
ISBN: 9781265321062
Author: Raven
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Textbook Question
Chapter 14, Problem 2S
In the Meselson-Stahl experiment, a control experiment was done to show that the hybrid bands after one round of replication were in fact two complete strands, one heavy and one light. Using the same experimental setup as detailed in the text, how can this be addressed?
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Consider the following experiment. First, large populations of two mutant strains of Escherichia coli are mixed, each requiring a different, single amino acid. After plating them onto a minimal medium, 45 colonies grew. Which of the following may explain this result?
A) The colonies may be due to back mutation (reversion).
B) The colonies may be due to recombination.
C) Either A or B is possible.
D) Neither A nor B is possible.
In the Meselson and Stahl experiment, what part of the DNA gets labeled with 15N? Why?
After two generations of replication in the Meselson and Stahl
experiment, what was the composition of the two bands?
One band was all 14N and one band was half 14N and half 15N.
One band was all 15N and one band was half 14N and half 15N.
One band was all 14N and one band was all 15N.
One band was all 15N and one band was one quarter 14N and three
quarters 15N.
One band was all 14N and one band was one quarter 14N and three
quarters 15N.
Chapter 14 Solutions
1 SEM CARDLESS ACC W/RAVEN TEXT
Ch. 14.1 - Describe the experiments of Griffith and Avery.Ch. 14.1 - Evaluate the evidence for DNA as genetic material.Ch. 14.2 - Explain how the WatsonCrick structure rationalized...Ch. 14.2 - Prob. 2LOCh. 14.3 - Prob. 1LOCh. 14.3 - Prob. 2LOCh. 14.4 - Prob. 1LOCh. 14.4 - Prob. 2LOCh. 14.4 - Diagram the functions found at the replication...Ch. 14.5 - Compare eukaryotic replication with prokaryotic.
Ch. 14.5 - Prob. 2LOCh. 14.5 - Prob. 3LOCh. 14.6 - Prob. 1LOCh. 14.6 - Prob. 2LOCh. 14 - Prob. 1DACh. 14 - Prob. 2DACh. 14 - Prob. 1IQCh. 14 - Prob. 2IQCh. 14 - How does the structure of eukaryotic genomes...Ch. 14 - Prob. 4IQCh. 14 - Prob. 1UCh. 14 - Which of the following is NOT a component of DNA?...Ch. 14 - Chargaff studied the composition of DNA from...Ch. 14 - The bonds that hold two complementary strands of...Ch. 14 - Prob. 5UCh. 14 - Prob. 6UCh. 14 - Which of the following is NOT pan of the...Ch. 14 - If one strand of a DNA is 5 ATCGTTAAGCGAGTCA 3,...Ch. 14 - Hershey and Chase used radioactive phosphorus and...Ch. 14 - The Meselson and Stahl experiment used a density...Ch. 14 - Prob. 4ACh. 14 - If the activity of DNA ligase was removed from...Ch. 14 - Successful DNA synthesis requires all of the...Ch. 14 - The synthesis of telomeres a. uses DNA polymerase,...Ch. 14 - When mutations that affected DNA replication were...Ch. 14 - Prob. 1SCh. 14 - In the Meselson-Stahl experiment, a control...Ch. 14 - Enzyme function is critically important for the...
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- Consider the experiment conducted by Meselson and Stahl in which they used 14N and 15N in cultures of E. coli and equilibrium density gradient centrifugation. Draw pictures to represent the bands produced by bacterial DNA in the centrifuge tube before the switch to medium containing 14N and after one, two, and three rounds of replication in that medium. Use separate sets of drawings to show the bands that would appear if replication were (a) semiconservative; (b) conservative; (c) dispersive.arrow_forwardThis is a three part question: Figure B in Box 4.1 illustrates the results of the Meselson-Stahl experiment after a single cycle of replication in 14N. (a) Explain the results they observed after two rounds of replication in 14N medium. (b) Draw out the expected results if a third round of replication were allowed in 14N medium. (c) Two other models for template-directed replication were considered as alternatives to semi-conservative replication. One of these was conservative replication, in which the parental strands were unpaired, replicated, then reannealed such that the parental strands stayed together and the newly synthesized strands were together. The second model was dispersive replication, in which one strand was used as the template for polymerization, then the polymerase switched to using the other strand as the template, and subsequently switched back and forth between the two strands until bother were fully replicated. Each of these models is ruled out by one of your…arrow_forwardTwo pathways, homologous recombination and nonhomologous end joining (NHEJ), can repair double-strandbreaks in DNA. If homologous recombination is an errorfree pathway whereas NHEJ is not always error free, whyis NHEJ used most of the time in eukaryotes?arrow_forward
- As shown, five DnaA boxes are found within the origin of replication in E. coli. Take a look at these five sequences carefully. A. Are the sequences of the five DnaA boxes very similar to each other? (Hint: Remember that DNA is double-stranded; think about these sequences in the forward and reverse directions.) B. What is the most common sequence for a DnaA box? In other words, what is the most common base in the first position, second position, and so on until the ninth position? The most common sequence is called the consensus sequence. C. The E. coli chromosome is about 4.6 million bp long. Based on random chance, is it likely that the consensus sequence for a DnaA box occurs elsewhere in the E. coli chromosome? If so, why aren’t there multiple origins of replication in E. coli?arrow_forwardIn DNA-hybridization experiments on six species of plants in the genus Vicia, DNA was isolated from each of the six species, denatured by heating, and sheared into small fragments (W. Y. Chooi. 1971. Genetics 68:213–230). In one experiment, DNA from each species and from E. coli was allowed to renature. The graph shows the results of this renaturation experiment. Q. Notice that, for the Vicia species, the rate of renaturation is much faster in the first hour and then slows down. What might cause this initial rapid renaturation and the subsequent slowdown?arrow_forwardBased on the electrophoresis experiment, 0.7% agarose gel concentration was used. If the gel concentration increased to 1%, what would happen to the DNA migration? Explain briefly.arrow_forward
- For the following short sequence of double stranded DNA and the given primers, there will be one major duplex DNA product after many cycles (imagine 10 cycles) of PCR. Provide the sequence of this one major duplex product and label the 5’ and 3’ ends of each strand. Sequence to be amplified: 5’- GGTATTGGCTACTTACTGGCATCG- 3’ 3’- CCATAACCGATGAATGACCGTAGC- 5’ Primers: 5’-TGGC-3’ and 5’-TGCC-3’arrow_forwardWhat is an Okazaki fragment? In which strand of replicating DNA are Okazaki fragments found? Based on the properties of DNA polymerase, why is it necessary to make these fragments?arrow_forwardMake a side-by-side drawing of two DNA helices: one with 10 bpper 360° turn and the other with 15 bp per 360° turn.arrow_forward
- The figure at the right shows a partially drawn replication fork. a) Annotate this figure to show the proper location of each of the following: • template DNA strand polarity • DNA polymerase I Topoisomerase (gyrase) • leading strand daughter fragment(s) lagging strand daughter fragment(s) Single stranded binding proteins • DNA polymerase III • Primase • Ligase • Helicasearrow_forwardConsidering the Polymerase Chain Reaction (PCR), we can state that: a) It is a technique that promotes linear amplification of the number of DNA molecules in a sample. b) Depends on an initial template which can be a DNA or RNA molecule c) The reaction must contain, in addition to the template sequence, nitrogenous bases, sense and antisense primers and DNA polymerase enzyme. d)The primer sense rings on the template strand 3’>5’, extending from the 3’ end e)arrow_forwardIn gel electrophoresis, are the DNA fragments attracted to, or repelled from the negative pole of the electric field? The positive pole? Why are these attractions and repulsions important to the process?arrow_forward
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