Practical Operations Management
Practical Operations Management
2nd Edition
ISBN: 9781939297136
Author: Simpson
Publisher: HERCHER PUBLISHING,INCORPORATED
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Chapter 14, Problem 29P

(a)

Summary Introduction

Interpretation:

The time period required on an average to finish the job.

Concept Introduction:

Schedule the job on the basis of the FCFS . Then determine the average flow time for the each job. Calculate the average flow time that is required to finish the each job. Then calculate the average tardiness by adding the delay time of the order.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

The owner of an in HM Catering Company has four jobs to deliver today, shown in the order in which they are received:

    JobProcessing Time
    (hrs)
    Due (hrs)
    W45
    X39
    Y22
    Z11

Schedule the jobs based on the first come first served:

    Hours12345678910
    JobWXYZ

From the table, it is observed that the flow time of the job W is 4 hours which due in 5 hours. Thus, W has no delay in job.

The flow time of the job X is 7 hours which due in 9 hours. Thus, X has no delay in job.

The flow time of the job Y is 9 hours which due in 2 hours. Thus, X has 7 hours delay in job.

In order of the job Y :

The flow time of the job Z is 10 hours which due in 1 hour. Thus, it has a delay of 9 hours.

In order of the job Z :

Thus, calculate the average flow time that is required to finish the each job:

  4hours+7hours+9hours+10hours4=7.5hours

Now, calculating the average tardiness, adding the delay time of the order and divide it by the number of the orders;

  AT=0+0+7+94AT=4hours

(b)

Summary Introduction

Interpretation:

The job that will be late and the average job tardiness.

Concept Introduction:

Schedule the job on the basis of the SPT . Then determine the average flow time for the each job. Calculate the average flow time that is required to finish the each job. Then calculate the average tardiness by adding the delay time of the order.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given information:

The owner of an in home meal catering company has four jobs to deliver today, shown in the order in which they are received:

    JobProcessing Time
    (hrs)
    Due (hrs)
    W45
    X39
    Y22
    Z11

Schedule the jobs based on the SPT ,

    Hours12345678910
    JobZYXW

From the table, it can be observed that Z has the 1 hour flow time which due in 1 hour. Z will be deliver on time.

  Y has the 3 hour flow time which due in 2 hour. Y will be delay 1 hour of the job.

  X has the 6 hour flow time which due in 9 hour. There will be no delay in order of the job X .

  W has the 10 hours flow time which due in 5 hours. Thus, there is delay of 5 hours on job order of W

Thus, calculate the average flow time that is required to finish the each job:

  1hours+3hours+6hours+10hours4=4hours

Now, calculating the average tardiness, adding the delay time of the order and divide it by the number of the orders;

  AT=0+1+0+54AT=1.5hours

(c)

Summary Introduction

Interpretation:

The job that will be late and the average job tardiness.

Concept Introduction:

Schedule the job on the basis of the EDD . Then determine the average flow time for the each job. Calculate the average flow time that is required to finish the each job. Then calculate the average tardiness by adding the delay time of the order.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given information:

The owner of an in home meal catering company has four jobs to deliver today, shown in the order in which they are received:

    JobProcessing Time
    (hrs)
    Due (hrs)
    W45
    X39
    Y22
    Z11

Schedule the jobs based on the EDD ,

    Hours12345678910
    JobZYWX

From the table, it can be observed that Z has the 1 hour flow time which due in 1 hour. Z will be no delay.

  Y has the 3 hour flow time which due in 2 hour. Y will be delay 1 hour of the job.

  W has the 7 hour flow time which due in 5 hour. There will be delay of 2 hours for the job.

  X has the 10 hour flow time which due in 9 hours. There will be delay of 1 hour in order of the job X .

Now, calculating the tardiness, adding the delay time of the order and divide it by the number of the orders;

  AT=0+1+2+14AT=1hour

Thus, calculate the average flow time that is required to finish the each job:

  1hour+3hours+7hours+10hours4=5.25hours

(d)

Summary Introduction

Interpretation:

The most efficient sequence from the FCFS,SPT,EDD .

Concept Introduction:

The efficiency can be measured as the average tardiness or the number of jobs delayed and the average flow time.

(d)

Expert Solution
Check Mark

Explanation of Solution

Given information:

The owner of an in home meal catering company has four jobs to deliver today, shown in the order in which they are received:

    JobProcessing Time
    (hrs)
    Due (hrs)
    W45
    X39
    Y22
    Z11

The efficiency can be measured as the average tardiness or the number of jobs delayed and the average flow time.

Average flow time:

By comparing the average flow time, it is observed that SPT method gives the lowest average flow time.

Average tardiness:

By comparing the average tardiness, it is observed that EDD method gives the lowest average tardiness.

Number of jobs delayed:

Both FCFS and SPT have the lower number of the jobs delayed as compared to the EDD method.

Therefore, it depends on the owner which gives the priority to the most efficient method will vary.

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