Biological Science (7th Edition)
7th Edition
ISBN: 9780134678320
Author: Scott Freeman, Kim Quillin, Lizabeth Allison, Michael Black, Greg Podgorski, Emily Taylor, Jeff Carmichael
Publisher: PEARSON
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Chapter 14, Problem 17TYPSS
QUANTITATIVE Recall that hemophilia is an X-linked recessive disease. If a woman with hemophilia had children with a man without hemophilia, what is the chance that their first child will have the disease? What is the chance that their first child will be a carrier?
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Determine what is the most likely mode of inheritance of this disease (whether it is inherited
as the result of an X-linked dominant or X-linked recessive trait).
Use "A" for the allele associated with the dominant phenotype, and lowercase "a"" for
the allele associated with the recessive phenotype.
Write the most probable genotype for each individual based on the mode of inheritance you have determined.
Show how all the partners are crossed and the expected offspring produced (You may use Punnett Square).
OT
I
OT
do
II
Hemophilia is an X-linked recessive disease. A hemophilic man marries a woman who is not a carrier of the disease.
(a) Draw a Punnett square showing the genotypes of their children.
(b) What are the chances that their daughters will be carriers of the disease?
(c) What percentage of their children are likely to have the disease?
Hemophilia is an X-linked recessive phenotype. Suppose a man who expresses the hemophilia phenotype has children with a woman who has the normal phenotype (and does not have a family history of hemophilia). If the couple have a son, what are the chances that he will have hemophilia?
A) 50%
B) 25%
C) 0%
D) 100%
Chapter 14 Solutions
Biological Science (7th Edition)
Ch. 14 - 1. The genes for the trails that Mendel worked...Ch. 14 - Example Problem Two black female mice are crossed...Ch. 14 - Prob. 5TYKCh. 14 - Prob. 6TYPSSCh. 14 - Prob. 7TYPSSCh. 14 - 11. In garden peas, yellow seeds (Y) are dominant...Ch. 14 - Prob. 9TYPSSCh. 14 - The smooth feathers on the back of the neck in...Ch. 14 - SOCIETY As a genetic counselor, you advise couples...Ch. 14 - 15. Suppose you are heterozygous for two genes...
Ch. 14 - Suppose a woman with blood type O married a man...Ch. 14 - Prob. 14TYPSSCh. 14 - Society Two mothers give birth to sons at the same...Ch. 14 - Prob. 16TYPSSCh. 14 - QUANTITATIVE Recall that hemophilia is an X-linked...Ch. 14 - Prob. 18PIATCh. 14 - Given the pedigree, what is the most likely mode...Ch. 14 - Prob. 20PIATCh. 14 - QUANTITATIVE If the son with ALD in the third...Ch. 14 - Prob. 22PIATCh. 14 - Prob. 23PIAT
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- 1. A) Apply the concept of sex linkage to explain why color blindness is more prevalent in men than in women. B) Mary is concerned that she may be a carrier for hemophilia, a sex-linked condition located on the X chromosome. Mary is married to John, who doesn't have hemophilia. Assuming Mary is a carrier, what are the genotype ratios expected for Mary and John's kids (specify for boys and for girls)? C) Mary and John have 2 boys, none of them has hemophilia. Can we use this fact as proof that Mary does not carry the allele for hemophilia? Explain your argument.arrow_forwardA man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is X-linked recessive. a) How many of their daughters might be expected to be color-blind dwarfs? b)What proportion of their sons would be color-blind and of normal height? c)They have a daughter who is a dwarf with normal color vision. What is the probability that she is heterozygous for both genes?arrow_forwardThe gene for polydactyly (P) is autosomal and dominant to normal fingers (p). Hemophilia is sex-linked and recessive (X h ). A man and his wife both of whom are polydactylous and have normal red blood cells have a child who is non-polydactylous and with hemophilia. What are their genotypes?arrow_forward
- Mutant female: yellow body and purple eyes. Male: Normal Use: https://www.sciencecourseware.org/FlyLabJS/ Which mutant alleles are dominant? Which mutant alleles are recessive? Which mutant alleles are sex-linked? Which mutant alleles are autosomal? Can you tell at this point if the two genes are linked? Show the results of the dihybrid analysis. Are genes segregating independently? What is the evidence for or against this? Show the crosses you will use to obtain the mapping data. For the mapping crosses, Write out the crossing scheme and make a table of the results (ignore sex in this table, combine the male and female progeny). Identify the parental classes and the recombinant classes. For a 3-point cross, identify the double cross overs. Show your calculations for the recombination frequencies between the three genes (for the 3-point cross) or the two genes (for the two-point crosses). Draw a map of the Drosophila chromosomes 2, 3, and X, including…arrow_forwardPls answer fastarrow_forwardA color-blind man marries a woman with normal vision whose father was color-blind. Remember that color-blindness is an X-linked recessive trait. Hint: see figure 12.7 in book. A) What is the probability that their first child will be a color-blind daughter? B) What is the probability that their first son will be color-blind?arrow_forward
- What is a Barr body? How many Barr bodies in a person with genotype XXXXX? How is the structure of a Barr body different from that of other chromosomes in the cell? How does the structure of a Barr body affect gene expression? Color-blindness is an X-linked recessive trait. Heterozygous females are not color blind but they can sometimes have partial color blindness. Explain how this can occur.arrow_forwardDuchenne Muscular Dystrophy (DMD) is an X-linked recessive trait. Fill in a Punnett square for a man with DMD and a woman who carries DMD. Then use your Punnett square to answer the following questions: A) What is the probability that one of their daughters will have DMD? ___% B) What is the probability that one of their daughters is a carrier of DMD? ______ % C) What is the probability that one of their sons will have DMD? ______ % D) What is the probability that one of their sons is a carrier of DMD? ______ % E) On which chromosome is the gene for DMD located? _____arrow_forwardFor a recessive condition, two normal heterozygous individuals have children. What is the likelihood of their children being affected by this condition? What is the likelihood of their children being carriers without the condition? What is the likelihood of their asymptomatic children being carriers? Suppose that an individual with the condition has children with a heterozygous individual, what is the likelihood of their children being carriers?arrow_forward
- If a trait is X-linked dominant, who would express the trait? A) females homozygous for the dominant allele and males hemizygous for the recessive allele B) heterozygous females and males hemizygous for the dominant allele C) females homozygous for the recessive allele and males hemizygous for the recessive allele D) females homozygous for the recessive allele and males hemizygous for the dominant allele E) significantly more females than malesarrow_forwardIn humans, being right handed (R) is dominant over being left handed (r), and normal vision (X+) is dominant over color blindness (Xc). Color blindness is a X-linked (a.k.a sex linked) trait. Two right-handed parents with normal vision have a son who is color blind and left handed. What are the genotypes of the parents for right-handedness and color blindness?arrow_forwardColor blindness is an X-linked recessive disease. A female and a male with normal vision have 4 children. The phenotypes of the children are listed below: 2 Colorblind males, 1 normal vision female, one normal vision male. Given these results, the female must be a carrier for colorblindness. True Falsearrow_forward
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