Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 14, Problem 14.9QE
Interpretation Introduction
Interpretation:
The condition of a system when change in the volume does not change the equilibrium constant has to be determined.
Concept Introduction:
The condition of equilibrium is a state of balance of processes that runs in opposite directions. At equilibrium, the formation of a product from the reactant balanced the formation of reactant from the product. Also, the change in concentration of reaction and product seems to be negligible at equilibrium state.
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Unshared, or lone, electron pairs play an important role in determining the chemical and physical properties of organic compounds.
Thus, it is important to know which atoms carry unshared pairs.
Use the structural formulas below to determine the number of unshared pairs at each designated atom.
Be sure your answers are consistent with the formal charges on the formulas.
CH.
H₂
fo
H2
H
The number of unshared pairs at atom a is
The number of unshared pairs at atom b is
The number of unshared pairs at atom c is
HC
HC
HC
CH
The number of unshared pairs at atom a is
The number of unshared pairs at atom b is
The number of unshared pairs at atom c is
Draw curved arrows for the following reaction step.
Arrow-pushing Instructions
CH3
CH3 H
H-O-H
+/
H3C-C+
H3C-C-0:
CH3
CH3 H
Chapter 14 Solutions
Chemistry: Principles and Practice
Ch. 14 - Prob. 14.1QECh. 14 - Describe a nonchemical system that is in...Ch. 14 - Describe a nonchemical system that is not in...Ch. 14 - Prob. 14.4QECh. 14 - Prob. 14.5QECh. 14 - Prob. 14.6QECh. 14 - Prob. 14.7QECh. 14 - Prob. 14.8QECh. 14 - Prob. 14.9QECh. 14 - Prob. 14.10QE
Ch. 14 - Explain why terms for pure liquids and solids do...Ch. 14 - Temperature influences solubility. Does...Ch. 14 - Prob. 14.13QECh. 14 - Prob. 14.14QECh. 14 - Prob. 14.15QECh. 14 - Prob. 14.16QECh. 14 - Prob. 14.17QECh. 14 - Prob. 14.18QECh. 14 - At 2000 K, experiments show that the equilibrium...Ch. 14 - At 500 K, the equilibrium constant is 155 for...Ch. 14 - At 77 C, Kp is 1.7 104 for the formation of...Ch. 14 - Consider the following equilibria involving SO2(g)...Ch. 14 - Kc at 137 C is 4.42 for NO(g) + 12 Br2(g) NOBr(g)...Ch. 14 - Prob. 14.24QECh. 14 - Prob. 14.25QECh. 14 - Prob. 14.26QECh. 14 - Prob. 14.27QECh. 14 - Prob. 14.28QECh. 14 - Prob. 14.29QECh. 14 - Prob. 14.30QECh. 14 - Prob. 14.31QECh. 14 - Prob. 14.32QECh. 14 - Prob. 14.33QECh. 14 - Prob. 14.34QECh. 14 - Prob. 14.35QECh. 14 - Consider the system...Ch. 14 - Prob. 14.37QECh. 14 - Prob. 14.38QECh. 14 - Prob. 14.39QECh. 14 - Prob. 14.40QECh. 14 - Prob. 14.41QECh. 14 - Prob. 14.42QECh. 14 - Prob. 14.43QECh. 14 - Prob. 14.44QECh. 14 - Prob. 14.45QECh. 14 - Prob. 14.46QECh. 14 - Prob. 14.47QECh. 14 - Prob. 14.48QECh. 14 - Prob. 14.49QECh. 14 - Prob. 14.50QECh. 14 - Prob. 14.51QECh. 14 - Consider 0.200 mol phosphorus pentachloride sealed...Ch. 14 - Prob. 14.53QECh. 14 - Prob. 14.54QECh. 14 - Prob. 14.55QECh. 14 - Prob. 14.56QECh. 14 - Prob. 14.57QECh. 14 - Prob. 14.58QECh. 14 - Prob. 14.59QECh. 14 - Prob. 14.60QECh. 14 - Prob. 14.61QECh. 14 - Write the expression for the equilibrium constant...Ch. 14 - Prob. 14.63QECh. 14 - Prob. 14.64QECh. 14 - Write the expression for the solubility product...Ch. 14 - Prob. 14.66QECh. 14 - Prob. 14.67QECh. 14 - The solubility of silver iodate, AgIO3, is 1.8 ...Ch. 14 - Prob. 14.69QECh. 14 - Prob. 14.70QECh. 14 - Prob. 14.71QECh. 14 - Prob. 14.72QECh. 14 - Even though barium is toxic, a suspension of...Ch. 14 - Lead poisoning has been a hazard for centuries....Ch. 14 - Calculate the solubility of barium sulfate (Ksp =...Ch. 14 - Calculate the solubility of copper(II) iodate,...Ch. 14 - Calculate the solubility of lead fluoride, PbF2...Ch. 14 - Calculate the solubility of zinc carbonate, ZnCO3...Ch. 14 - Prob. 14.79QECh. 14 - Prob. 14.80QECh. 14 - Use the solubility product constant from Appendix...Ch. 14 - Prob. 14.82QECh. 14 - Some barium chloride is added to a solution that...Ch. 14 - Prob. 14.84QECh. 14 - Prob. 14.85QECh. 14 - Prob. 14.86QECh. 14 - Prob. 14.87QECh. 14 - Prob. 14.88QECh. 14 - Prob. 14.89QECh. 14 - Prob. 14.90QECh. 14 - Prob. 14.91QECh. 14 - At 3000 K, carbon dioxide dissociates CO2(g) ...Ch. 14 - Prob. 14.94QECh. 14 - Nitrogen, hydrogen, and ammonia are in equilibrium...Ch. 14 - The concentration of barium in a saturated...Ch. 14 - According to the Resource Conservation and...Ch. 14 - Prob. 14.98QE
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