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(a)
Interpretation:
The expression for equilibrium constant
Concept Introduction:
The condition of equilibrium is a state of balance of processes that runs in opposite directions. At equilibrium, the formation of a product from the reactant balances the formation of reactant from the product. Also, the change in concentration of reaction and product seems to be negligible at equilibrium state.
The general equilibrium reaction is as follows:
Here,
The expression of the equilibrium constant for the above reaction is as follows:
Here,
(b)
Interpretation:
The expression for equilibrium constant
Concept Introduction:
Refer to part (a).
(c)
Interpretation:
The expression for equilibrium constant
Concept Introduction:
Refer to part (a).
(d)
Interpretation:
The expression for equilibrium constant
Concept Introduction:
Refer to part (a).
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Chapter 14 Solutions
Chemistry: Principles and Practice
- The following 'H NMR spectrum was taken with a 750 MHz spectrometer: 1.0 0.5 0.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 ' 2.0 1.0 0.0 (ppm) What is the difference Av in the frequency of RF ac Δν ac radiation absorbed by the a and c protons? (Note: it's not equal to the difference in chemical shifts.) Round your answer to 2 significant digits, and be sure it has an appropriate unit symbol. = O O a will shift left, c will shift right. O a will shift right, c will shift left. a and c will both shift left, with more space between them. Suppose a new spectrum is taken with a 500 MHz spectrometer. What will be true about this new spectrum? O a and c will both shift left, with less space between them. O a and c will both shift right, with more space between them. O a and c will both shift right, with less space between them. Which protons have the largest energy gap between spin up and spin down states? O None of the above. ○ a Ob Explanation Check C Ar B 2025 McGraw Hill LLC. All Rights Reserved.…arrow_forwardWhat mass of Na2CO3 must you add to 125g of water to prepare 0.200 m Na2CO3? Calculate mole fraction of Na2CO3, mass percent, and molarity of the resulting solution. MM (g/mol): Na2CO3 105.99; water 18.02. Final solution density is 1.04 g/mL.arrow_forward(ME EX2) Prblms Can you please explain problems to me in detail, step by step? Thank you so much! If needed color code them for me.arrow_forward
- Experiment #8 Electrical conductivity & Electrolytes. Conductivity of solutions FLINN Scientific Scale RED LED Green LED LED Conductivity 0 OFF OFF 1 Dim OFF 2 medium OFF 3 Bright Dim Low or Nowe Low Medium High 4 Very Bright Medium nd very high AA Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ SE=Strong Electrolyte, FE = Fair Electrolyte CWE = Weak Electrolyte, NE= Noni Electrolyte, #Solutions 1 0.1 M NaCl 2/1x 102 M NaCl, 3/1X103 M Nall Can Prediction M Observed Conductivity Very bright red Bright red Dim red you help me understand how I'm supposed to find the predictions of the following solutions? I know this is an Ionic compound and that the more ions in a solution means it is able to carry a charge, right? AAAA Darrow_forward(SE EX 2) Prblsm 4-7: Can you please explain problems 4-7 and color code if needed for me. (step by step) detail explanationsarrow_forward(SE EX 2) Problems 8-11, can you please explain them to me in detail and color-code anything if necessary?arrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning
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